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haar

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1
haar
▪ I. haar local. (hɑː(r)) Also harr, haur. [a. MDu. hare (Du. haere) keen cold wind.] A wet mist or fog; esp. applied on the east coast of England and Scotland, from Lincolnshire northwards, to a cold sea-fog.1662 Dugdale Hist. Imbanking Pref., The air being..cloudy, gross, and full of rotten harrs.... Oxford English Dictionary
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Mere Bharat Ke Kanth Haar - Wikipedia
Mere Bharat Ke Kanth Haar is the state song of the Indian state of Bihar. The lyrics were written by Satya Narayan and the music was composed by Hari Prasad Chaurasia and Shivkumar Sharma. The song was officially adopted in March 2012. Lyrics. Hindi original Hindi romanisation
en.wikipedia.org 0.0 1.5 0.0
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Haar bei München - Aktuelle Nachrichten - SZ.de
Aktuelle Nachrichten aus Haar bei München. Zum Ressort "Landkreis München"Anzeige SUSHI Bike 3.0 WESTbahn Schwabinger Tor Les Misérables Artoui Kaufdown Prospektbeilagen.
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Haar cascade classifier-Car Detection | Kaggle
In this project, we will be working on detecting and counting vehicles in a given image or a video. We will be using OpenCV for image processing and Haar cascade which is used for object detection. We can also create our own customized haar cascade classifier. As haar cascade is used for object detection we have a very vast scope for this project.
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definition of unimodular group Suppose $G$ is a locally compact group,we call $G$ an unimodular group if the modular function $\Delta =1$,that is to say,if the left Haar measure is also a right Haar measure. How to s...
By definition of the modular function, if $\nu$ is a right Haar measure, then for every $g\in G$, we have $\nu(g^{-1}S)=\Delta(g)\nu(S)$ for all open $
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Is the Haar measure of a product of finite measure and compact, finite? Let $G$ be a locally compact group with Haar measure $ \mu $, $K \subset G$ a compact subset and $ F \subset G $ any subset of finite Haar measur...
Take $G:=\Bbb R$ (additive group) with Lebesgue measure, $K:=[0,1]$ and $F:=\Bbb Z$. Then $$KF=\\{x+y,x\in [0,1],y\in\Bbb Z\\}=\Bbb R$$ which has infinite measure.
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Haar measure of quotient group Suppose $G$ is a (Hausdorff) compact group with normalised Haar measure $\mu$, and that $H\trianglelefteq G$ is a closed normal subgroup. Is it true that the pushforward of $\mu$ to $G/H...
The answer is yes: if you write $\pi^{-1}(A)=AH=HA$ (since the subgroup $H$ is normal in $G$), then you realize that for any element $gH=Hg\in G/H$ you have $$gH.A=gH.AH=g.HA=g.\pi^{-1}(A).$$ Since the measure $\mu$ is invariant under the multiplication by $g$, so is the pushforward measure: $$ \nu(...
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Fourier transform of the Haar system The Haar system form an orthonormal basis of $L^2(\mathbb{R})$. Being the Fourier transform an isometry of $L^2(\mathbb{R})$ onto itself, the Fourier transform of the Haar system i...
No reference, sorry, but it is straightforward to evaluate the transform: $$\psi_{n, k}(t) = 2^{n/2}([0 < 2^n t - k < 1/2] - [1/2 < 2^n t - k < 1]), \\\ \int_{-\infty}^\infty \psi_{n, k}(t) e^{i p t} dt = \frac {2^{n/2 + 2} \sin^2(2^{-n - 2} p)} {i p} \exp(2^{-n - 2} (4 k + 2) i p).$$
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Nice applications of the Haar measure The existence of the Haar measure is a beautiful result that has a lot of applications. For example, one can prove using the Haar measure that the category of representations of a...
One important "application" is Peter-Weyl theorem. A good article can be found at here.
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Haar 小波——原理 - 知乎
这样我们就对原来的图像进行了一次 Haar 分解。. 每经过一次分解，均值"图像"的分辨率就会减半。. 对每次产生的新的均值部分重复上面两个步骤，直到均值只剩下一个数，无法进一步分解：. 这样，我们就得到了一组由 1 个均值（approximation coefficients）和 3 ...
zhuanlan.zhihu.com 0.0 0.3 0.0
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Haar measure of point sets Let $G$ be a locally compact group with Haar measure $\mu$ (left or right doesn't matter to me). I know that the Haar measure is positive on open sets. What can be said about the Haar measur...
The former happens already for the Lebesgue measure on $\mathbb{R}$ and the latter occurs for, say a discrete group, since as you know Haar measure is
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传统经典CV算法_Haar-CSDN博客
二.Haar-like特征的计算-积分图. 积分图就是只用遍历一次图像就可以求出图像中所有区域像素和的快速算法，大大的提高了图像特征值计算的效率。. 积分图主要的思想 ：将图像从起点开始到各个点所形成的矩形区域像素之和作为一个数组的元素保存在内存中 ...
blog.csdn.net 0.0 0.0 0.0
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Is the Haar measure on $\mathbb{Q}_p$ complete? The field of $p$-adic numbers $\mathbb{Q}_p$ is locally compact, and so there exists a Haar measure on $(\mathbb{Q}_p,+)$. My question is whether a Haar measure on $\mat...
A Haar measure for a locally compact group $G$, like $\mathbb{Q}_p$, is not complete, because the Borel sigma algebra in the measure space $(G,B(G),\mu
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Haar小波变换-CSDN博客
小波变换的基本思想是用一组小波函数或者基函数表示一个函数或者信号，例如图像信号。首先，以haar小波变换过程为例来理解小波变换。例：求有限信号的均值和差值 假设有一幅分辨率只有4个像素 的一维图像，对应的像素值或者叫做图像位置的系数分别为：[9 7 3 5]，计算它的哈尔小波变换系数。
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Why a left-invariant Haar measure is $\mu(A)=\int_A \frac{1}{a^2}da\,db$ and a right-invariant Haar measure is $\mu'(A)=\int_A\frac{1}{a}da\,db$? Let $G$ be the group of affine transformations of $\mathbb R$, $x\mapst...
multiplication by $(a,b)$, the determinant of $\begin{bmatrix}a&0\\\0&a\end{bmatrix}$ is $a^2$, which is the reason for the factor $\frac{1}{a^2}$ in the left Haar multiplication by $(a,b)$, the determinant of $\begin{bmatrix}a&0\\\b&1\end{bmatrix}$ is $a$, which is why we have the factor $\frac{1}{a}$ in the right Haar
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