No reference, sorry, but it is straightforward to evaluate the transform: $$\psi_{n, k}(t) = 2^{n/2}([0 < 2^n t - k < 1/2] - [1/2 < 2^n t - k < 1]), \\\ \int_{-\infty}^\infty \psi_{n, k}(t) e^{i p t} dt = \frac {2^{n/2 + 2} \sin^2(2^{-n - 2} p)} {i p} \exp(2^{-n - 2} (4 k + 2) i p).$$