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sub-
sub-, prefix (sʌb, səb) repr. L. sub- = the prep. sub under, close to, up to, towards, used in composition (cf. under-) with the various meanings detailed below. (The related Skr. upa-, Gr. ὑπο- have a similar range of meaning.) The b of L. sub- remained unchanged when it preceded a radical beginnin... Oxford English Dictionary
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Urban Dictionary: sub-
a very small suburb. with hardly anything in it. no resturants, or anything like that...but it has a bar and gas station. also a nickname for minnesota city
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sub- | Etymology of prefix sub- by etymonline
Sep 15, 2023The original meaning is now obscure in many words from Latin ( suggest, suspect, subject, etc.). The prefix is active in Modern English; the indication generally being: 1. "under, beneath, at the bottom of;" in adverbs "down, low, lower;" 2. "inferior part, agent, division, or degree; inferior, having subordinate position" ( subcontractor) also ...
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sub-
sub-pref 前缀1 (with ns and adjs 与名词和形容词结合) under; below 在...之下; 低於... subway * subsoil * submarine.2 (with ns 与名词结合) lower in rank; inferior 级别较低的; 次於...的: sub-lieutenant subspecies.3 (with adjs 与形容词结合) not quite; almost 不完全的; 近似的: subnormal subtropical * substandard.4 (with vs and ns 与动词和名词结合) (form... 牛津英汉双解词典
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Sub-$1 plasticized cellulose curtains of 1947 - Boing Boing
Sub-$1 plasticized cellulose curtains of 1947. Cory Doctorow 9:55 pm Sun Sep 12, 2010. What America clearly needs is a good, $0.39 plasticized cellulose window-dressing. Look at how goddamned ...
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AMD's Radeon HD 5670: Sub-$100 DirectX 11 Starts Today - AnandTech
At $99, the 5670 is intended to stake out the all-important sub-$100 position for video cards, which is a big price point for price-sensitive buyers and OEMs. Bear in mind that the entire sub-$100 ...
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Why sub- and super-harmonic? My question might sound stupid, but here we go. Recall that a function $u$ is called subharmonic (superharmonic) if $\Delta u\ge 0 (\le 0)$. 1) Why is the former called subharmonic but n...
Sub-harmonic = under harmonic. If two functions $u, h$ have the same boundary values in a domain $\Omega$, and satisfy $\Delta u\ge 0$ and $\Delta h=0$, then $u\le h$ in $\Omega$: the graph of subharmonic function lies under the graph of harmonic function. (This is a consequence of the maximum princ...
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How to take complements in sub-$\sigma$-algebra If I have a $\sigma$-algebra $\mathcal{A}$ over $X$ and I have some sub-$\sigma$-algebra $\mathcal{B}$, is $X\in\mathcal{B}$? What's the usual definition? I have two see...
Given a $\sigma$-algebra $\mathcal{A}$ of subsets of $X$, a subset $\mathcal{B} \subset \mathcal{A}$ is a $\textbf{sub-algebra}$ of $\mathcal{A}$ if $\mathcal{B}$ is also a $\sigma$-algebra of subsets of $X$, i.e. $\emptyset \in \mathcal{B}$, $X \in \mathcal{B}$, and $\mathcal{B}$ is closed under co...
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$L^2$ representation of Hilbert subspace of $L^2$ Suppose that $\mathcal{H}$ is a Hilbert space which is a subspace of $L^2(X,\mathcal{A},\mu)$. Does there exist a sub-$\sigma$-algebra $\mathcal{B}$ of $\mathcal{A}$ s...
Let $f$ be a bounded function in $L^{2}(X,\mathcal A,\mu)$ such that $f^{2}$ is not a scalar multiple of $f$. Let $M$ be the one dimensional subspace generated by $f$. If $M$ has the desired form then $f^{2}$ is an $L^{2}$ function measurable w.r.t. $\mathcal B$ so it must belong to $M$. This is a c...
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SUB1
SUB1 (SUB1 homolog, transcriptional regulator) هوَ بروتين يُشَفر بواسطة جين SUB1 في الإنسان. الوظيفة الأهمية السريرية المراجع قراءة متعمقة جينات على كروموسوم 5 wikipedia.org
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Eng Sub-墨西哥风味牛油果酱 Gourmet Guacamole - YouTube
牛油果是墨西哥的传统调料，在北美洲极为受欢迎，营养丰富，老少咸宜。每个星期我们都会买一袋回家。最普遍的吃法是切片用来夹三文治，另外 ...
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Understanding all sub-$\sigma$-algebras of a $\sigma$-algebra Suppose I have a set $\Omega$, and I partition $\Omega$ into $4$ sets $A_{1}, A_{2}, A_{3}, A_{4}$. Clearly, the $A_{i}$'s are pairwise disjoint and their...
I think the following are also sub-$\sigma$-algebras: $$\sigma(A_1\cup A_2),\quad\sigma(A_1\cup A_3),\quad\sigma(A_1\cup A_4).$$ More generally, let Then $\sigma(A_1\cup B)$ is a sub-$\sigma$-algebra of $\sigma(A_1,\ldots,A_n)$ for all $B\in S$.
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(PDF) Preliminary analysis of the Chinese sub- database of the Chinese ...
PDF | JQ. 2018. Preliminary analysis of the Chinese sub-database of the Chinese crust single-grain zircon U-Pb geochronology database. Acta Petrologica... | Find, read and cite all the research ...
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conditional mean / integration Consider a $\sigma$-algebra $\mathcal{G}$ and a sub-$\sigma$-algebra $\mathcal{f}$ For any $A \in \mathcal{f}$ holds: $$\int_A E(E(X|G)|F)dP = \int_A E(X|G) dP$$ Why is this the case?
Let $Y=E(X|\mathcal G)$. We are asked to show that $\int_A E(Y|\mathcal F)dP=\int_A Y dP$ for $A \in \mathcal F$. This follows from the definition.
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Purely infinite $C^*$-algebras In the book of Rordam, Larsen, Lautsen (exercise 5.7) they give three equivalent definitions for a simple, unital, purely infinite $C^*$-algebra. Assume $A$ is unital, simple and not equ...
It is needed for showing $(c) \Rightarrow (a)$ : Following the Hint the book suggests you, with the same notations, you find a non-zero, properly infinite projection $p$ in $\overline{aAa}$. A is simple, so $p$ must be a full projection. By 4.9(i) we know that $1_{A} \preceq p$, i.e. there exists a ...
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