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RATIONALIZE Definition & Meaning - Merriam-Webster
1 ... to bring into accord with reason or cause something to seem reasonable: such as ... a ... to substitute a natural for a supernatural explanation ... www.merriam-webster.com
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Rationalize - Definition, Meaning & Synonyms - Vocabulary.com
Rationalize means to justify by developing a rationale, or a set of reasons for something. You could rationalize cutting school, saying your classes are ... www.vocabulary.com
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RATIONALIZE Definition & Meaning - Dictionary.com
Rationalize definition: to ascribe (one's acts, opinions, etc.) to causes that superficially seem reasonable and valid but that actually are unrelated to ... www.dictionary.com
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rationalized
ˈrationalized, ppl. a. [f. rationalize v. + -ed1.] a. That has been rendered rational.1855 Sir G. C. Lewis Credib. Rom. Hist. xi. I. 426 According to another, and probably a rationalized, version. 1896 Spectator 11 Apr. 519 Swift's grim conceptions of animalized man and rationalized animals. b. spec... Oxford English Dictionary
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Rationalization (psychology) - Wikipedia
Rationalization is a defense mechanism (ego defense) in which apparent logical reasons are given to justify behavior that is motivated by unconscious ... en.wikipedia.org
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RATIONALIZE | definition in the Cambridge English Dictionary
to try to find reasons to explain your behavior, decisions, etc.: She rationalized the cost by saying that an expensive carpet would last longer than a cheaper ... dictionary.cambridge.org
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Does rationalizing the denominator lead to more or less round-off error? I evaluated $\frac{1}{\sqrt{2}}$ and $\frac{\sqrt{2}}{2}$ in Matlab, and got a slight difference: $0.707106781186547$ and $0.707106781186548$, r...
In this case, the value is $0.707106781186547524400844362104849039284835937688474036588339...$, so the second is (marginally) closer. I wouldn't expect there to be a uniform rule on which is more accurate, depending on what expressions you are considering. The point about division by $2$ being exact...
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Rationalization | Psychology Today
Rationalization is a defense mechanism in which people justify difficult or unacceptable feelings with seemingly logical reasons and explanations. www.psychologytoday.com
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rationalized, adj. meanings, etymology and more | Oxford English ...
There are two meanings listed in OED's entry for the adjective rationalized. See 'Meaning & use' for definitions, usage, and quotation evidence. www.oed.com
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RATIONALIZE Synonyms: 13 Similar Words - Merriam-Webster
Synonyms for RATIONALIZE: explain, justify, account (for), attribute, condone, forgive, excuse, explain away, absolve, vindicate. www.merriam-webster.com
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Rationalization: Overview, Types, Pros and Cons - Investopedia
Rationalization is the reorganization of a company in order to increase its operating efficiency. This sort of reorganization may lead to an expansion or ... www.investopedia.com
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Rationalization - Definition, Method, Solved Examples - Cuemath
Rationalization is the process of removing a radical or surd from the denominator and shifting it to the numerator. By rationalizing, we make a denominator of a ... www.cuemath.com
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how to rationalize $\frac{1}{\sqrt a+\sqrt b+\sqrt c+\sqrt d+e}$ let say $a, b, c, d, e \in \Bbb Z^+ $ and $\sqrt a, \sqrt b, \sqrt c, \sqrt d \notin \Bbb Z^+ $ My problem is how to rationalize the denominator of $\f...
In general you have that, $$\Pi_{(i_1,\dots, i_n)\in C_2^n}((-1)^{i_1}\sqrt{a_1}+\dots+(-1)^{i_n}\sqrt{a_n})$$ is an integer, where $a_i$ is an integer $\forall i$. Can you prove this? * * * I think an elementary proof may be this: The polynomial $$\Pi_{(i_1,\dots, i_n)\in C_2^n} ((-1)^{i_1}X_1+\dot...
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Unrationalize Denominator What is the method to unrationalize or reverse a rationalized fraction? **For example:** How do you simplify $\frac{1}{2\sqrt\frac{1}{2}}$ = $\frac{1}{\sqrt{2}}$
$$\frac{1}{2\sqrt{\frac{1}{2}}}=\frac{1}{\sqrt{4}\sqrt{\frac{1}{2}}}=\frac{1}{\sqrt{\frac{4}{2}}}=\frac{1}{\sqrt{2}}$$ Now you can multiply by "1": $$\frac{1}{\sqrt{2}}\frac{1}{1}=\frac{1}{\sqrt{2}} \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{(\sqrt{2})^2}=\frac{\sqrt{2}}{2}$$
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Find $\lim_{x \to 1}\frac{\sqrt{x^2+35}-6}{x-1}$ I've rationalized the numerator to $x^2+35-36$ $$= \frac{x^2+35-36}{(x-1)\left(\sqrt{x^2+35}+6\right)} = \frac00$$ (when I substitute $x=1$) I don't know what to do t...
**Hint 1:** $$35 - 36 = -1$$ **Hint 2:** You know that the numerator is $0$ when you substitute $x=1$. That means that $(x-1)$ is a factor of the numerator: $$x^2+35-36 = (x-1)(\ \ldots\ )$$ You can then cancel out $(x-1)$ from top and bottom. (But simplify first using Hint 1.)
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