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print-field
† ˈprint-field Obs. [f. print v. + field n.] An establishment for printing and bleaching calicoes; = print-work 1.1799 J. Robertson Agric. Perth 380 Printfields for staining cotton cloth have been established at Cromwel-haugh, Huntingtower, Stormont-field and Tulloch. 1806 Gazetteer Scotl. (ed. 2) 1...
Oxford English Dictionary
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Print Quarterly
Print Quarterly is an international academic journal devoted to the history and art of printmaking, from its origins to the twentieth and twenty-first Eitel-Porter: September 2010 – present
Editorial Board
Clifford Ackley, David Alexander, Judith Brodie, Michael Bury, Paul Coldwell, Marzia Faietti, Richard Field
wikipedia.org
en.wikipedia.org
print field that contain a certain value is it possible to print the field that contain a certain value? Consider below file: foo,boo,123,1234312,ABC foo,boo,ABC,bla,bla There is a field tha...
Yes, just like in your previous question, but match each field:
$ awk -F, '{for(i=1;i<=NF;i++){if($i~/ABC/){print $i}}}' file
ABC perl -F, -lane 'print grep{/ABC/}@F' file ## field matches
perl -F, -lane 'print grep{$_=="ABC"}@F' file ## field is
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awk: print one line per field-1 value (distinct) where difference "field-2 - field-3" is minimum I want to distinct print the lines where diff is minimum. (diff=$2-$3) The input file is: c1,5,2 ...
a[$1]) { a[$1]=diff; b[$1]=$2 FS $3 } }
END{ for(i in a) print i,b[i] }' OFS=',' yourfile
The output:
c1,5,3
c2,8,4
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Popular print
to categorise them.
15th century
From about 1400, there began a "visual revolution that inundated Europe with images during the fifteenth century" (Field Notes
References
Field, Richard (1965). Fifteenth Century Woodcuts and Metalcuts. National Gallery of Art
Mayor, A. Hyatt (1980).
wikipedia.org
en.wikipedia.org
AWK: Print first field of every line as identifier for every following field in the corresponding line I have a input file like this with a blank as field seperator AAABBB: 243.234.12.2 123.3.2 231.5.12 ...
Fairly straightforwardly:
awk '{ for(i=2; i <= NF; i++) print $1, $i}' < input
On every line, loop from 2 until the last field (`N` umber of `F`ields), printing field 1 and the looped field.
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print last field from line + alternative for awk Due to technical reason on my Solaris machine, I can't use `awk` in order to print the last field in line. What are the other alternatives to `awk` that print the last...
*\s//'
The following was contributed by mr.spuratic in a comment:
echo "foo bar baz " | perl -lane 'print $F[-1]'
# Bash
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print lines if comma seperated fields matching together in another line **Input:** 1,1,10,1 2,1,10,3 3,0,10,1 **Expected Output:** 1,1,10,1 2,1,10,3 So how to print ...
Quick'n'dirty method (requiring two passes over the file, the first to count occurrences of `$2,$3`, and the second to print whenever the field combination
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Printing more than one field Is there a way to print multiple fields with a single line command? I want to print $3 to $NF, I can do it like below: awk -F[:] '{print $3,$4,$5 .... $NF}' Yet it i...
The only way I know is to loop over each field:
$ echo "a:b:c:d:e:f:g:h:i" |
awk -F":" '{for(i=3;i<=NF-1;i++){printf "%s ", $i}print $NF}'
c d e f g h i
Alternatively, you could just use `perl`:
$ echo "a:b:c:d:e:f:g:h:i" | perl -F":" -lane 'print "@F[2..
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how to print field between the double quote I have the following file `conf.txt`: perl /home/site/gen.pl "GG - W C1 Test - sai1" "15072" && ssh 13.4.93.103 perl /home/site/gen.pl "GG - W C1 Test -...
Try using `awk`:
awk -F'"' '{ print $2 }' conf.txt
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awk compare two files and print first field in file 1 I have two files like this. file 1 1:apple 2:banana 3:pineapple 4:guava 5:orange and file 2 like this apple ...
($2 in a) {print $1}' file2 file1
2
3
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Print the last-but-one field How to print the word before the last word in line (with ksh or awk or sed or perl one liner) Example 1: echo one two three will print "two" Example 2: ...
With awk:
awk '{ print $(NF-1) }'
`NF` is the number of fields -- all that happens here is that one is subtracted from the total field length to get the penultimate field.
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awk + print line only if the first field start with string as Linux1 how to print the line in case the first field start with Linux1 for example: echo Linux1_ver2 12542 kernel-update | awk '{if ($...
One way: echo "Linux1_ver2 12542 kernel-update" | awk '$1 ~ /^ *Linux1/'
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Awk field printing within the ternary operator If you're familiar with DISA STIGs, the test for RHEL-06-000518 is /bin/rpm -Va 2>/dev/null \ | /bin/grep '^.M' What I want to do is pull just t...
./` is always true, except when `$2` is the empty string, ie when there is 0 or 1 field in the line. You should try `$2 ~ /^.$/`. You can also combine the grep and awk into one:
awk '/^.M/ {print ($2 ~ /^.$/ ? $3 : $2)}'
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How to print from the field separator ":" until end of the line? How to print from the field separator ":" until end of the line example: echo " llap_java_opts : -XX:+AlwaysPreTouch {% if java_version...
I would use `cut -d: -f2-` for this: echo " llap_java_opts : -XX:+AlwaysPreTouch {% if java_version > 7 %}-XX:+UseG1GC -XX:TLABSize=8m -XX:+ResizeTLAB -XX:+UseNUMA -XX:+AggressiveOpts" | cut -d: -f2-
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