awk + print line only if the first field start with string as Linux1
how to print the line in case the first field start with Linux1
for example:
echo Linux1_ver2 12542 kernel-update | awk '{if ($1 ~ Linux1 ) print $0;}'
the target is to print the line , while the first field start with Linux1
example of lines:
Linux1-new 36352 Version:true
Linux1-1625543 9847
Linux1:16254 8467563
remark - space or TAB could be before the first filed