ProphetesAI is thinking...
Ind
Answers
MindMap
Loading...
Sources
Ind
Ind (ɪnd) Forms: 3–6 Ynde, (4 Yngde), 4–9 Inde, 5 Yende, Ynd, 7– Ind. [a. F. Inde:—L. India (cf. Afric, Greece): see India.] 1. An earlier name of the country now called India; sometimes applied to Asia or the East. Now archaic and poetic.a 1225 Ancr. R. 342 Deorewurðe ouer alle gold hordes, and oue...
Oxford English Dictionary
prophetes.ai
IND
Ind or IND may refer to:
General
Independent (politician), a politician not affiliated to any political party
Independent station, used within television of each year to mark the contributions nurses make to society
Science and technology
Improvised nuclear device, theoretical illicit nuclear weapon
IND
wikipedia.org
en.wikipedia.org
Ind
Indabbr 缩写 = (politics 政) Independent (candidate) 独立的(候选人) Tom Lee (Ind) 汤姆?李(独立候选人).
牛津英汉双解词典
prophetes.ai
Indé
Indé is the municipal seat of the municipality of Indé in the Mexican state of Durango. As of 2010, the town had a population of 659. The village of Indé was founded in 1547.
References
Populated places in Durango
Populated places established in 1547
wikipedia.org
en.wikipedia.org
Computing the Ind-completion of the terminal category Let $C$ be any category. $\text{Ind}(C)$ is the free completion under all filtered colimits. Can you help me in computing the Ind-completion of the terminal categ...
The Ind-completion may be constructed as the closure of the representables in $\widehat{C}$ under filtered colimits. That is, the terminal category is its own Ind-completion.
To confirm, we can check the universal property.
prophetes.ai
Schur Index Divisibility Question: Ind A^E divides Ind A Background notation: If $A\in\mathcal{F}$ is a central simple algebra, $A\cong M_n(D)$, where $D$ is a division algebra. The Schur index of $A$ is defined as $I...
By your definition $\operatorname{Ind}(A)=\deg D$ and $\operatorname{Ind}(A^E)=\deg D_E$, so we are done.
prophetes.ai
definition of $\mathbb{N}:=\bigcap Ind$ \--- let $A$ a set, $A^+=A \cup \\{A\\}$ \--- let $B$ a set, B is inductive if $\emptyset \in B \wedge \forall A \in B(A^+ \in B )$ \--- let $Ind:=\\{C|C \text{ is inductive }...
I don't know how to give a meaning to the formula $\bigcap \text{Ind}$ if $\text{Ind}$ is not a set, which it isn't. This set is what one would end up with if one could consider an entity such as $\bigcap \text{Ind}$.
prophetes.ai
When are two ind-objects isomorphic? Two diagrams may be different, but they may still have the same isomorphic limits (or colimits). Ind-objects are, so to speak, formal colimits of diagrams, even if the actual lim...
If $"\varinjlim" \alpha$ and $"\varinjlim"\beta$ are two Ind-objects over a category $C$ then they are in particular contravariant functors from $C$ to Actually we define the category $Ind(C)$ as a full subcategory of $C^{\wedge}=Fct(C^{op},Set)$ with ind-objects as objects and natural transformations
prophetes.ai
Ind.Zone - Translation into Chinese - Reverso Context
Translations in context of "Ind.Zone" in English-Chinese from Reverso Context: F12,BLDG22(Pujing Semiconductor ind.park)Chuangye Ind.Zone, Shapuwei Community, Songgang, Bao'an District, Shenzhen, China
context.reverso.net
Ind Sent Flashcards | Quizlet
Study with Quizlet and memorize flashcards containing terms like 敕勒川, 阴山下, 天似穹庐 and more.
quizlet.com
Simplify $\langle \operatorname{Ind}^G_1 1, \operatorname{Ind}^G_H\phi\rangle_G$ Let $G$ be a finite group and $H$ a subgroup. Let $\phi$ be an irreducible character of $H$ and $\mathbb 1$ the trivial character of the...
Therefore we have $\langle\operatorname{Ind}^G_11, \operatorname{Ind}^G_H \phi\rangle_G= \sum_\chi\langle\chi,\operatorname{Ind}^G_H\phi\rangle_G\chi(1 )=(\operatorname{Ind}^G_H\phi)(1)=[G:H]\phi(1)$.
prophetes.ai
Prove that if $g$ and $h$ are primitive roots modulo $m$ so $\text{ind}_g (h)$ is the inverse of $\text{ind}_h (g)$ modulo $\phi(m)$ > Prove that if $g$ and $h$ are primitive roots modulo $m$ so $\text{ind}_g (h)$ is ...
Let $a=\text{ind}_g(h)$ and $b=\text{ind}_h(g)$. Then $h\equiv g^a\pmod{m}$ and $g\equiv h^b\pmod{m}$. So $h\equiv (h^b)^a\equiv h^{ab}\pmod{m}$.
prophetes.ai
Why is $ U \otimes \operatorname{Ind}(W) = \operatorname{Ind}(\operatorname{Res}(U) \otimes W)$? If $U$ is a representation of $G$ and $W$ is a representation of $H$, then why is $$ U \otimes \operatorname{Ind}(W) = \...
I take it $H \leq G$. These reps are not equal, but they are isomorphic. It will be more natural to prove that $ (W \otimes U|_H) \uparrow^G \cong (W \uparrow ^G) \otimes U $, but this is equivalent as $A\otimes B \cong B \otimes A$ for modules over group algebras. We want a module map $kG \otimes_H...
prophetes.ai
An elaboration of Thm. 8.11(c) proof. The theorem is given below$ should be apparent but my proof to it was as follows: Since the index def...
So, when you have $r^{\operatorname{ind} 1}\equiv 1\bmod n$, this implies that $\phi(n)|\operatorname{ind} 1$.
prophetes.ai
How does $\operatorname{Ind}^G_H$ behave with respect to $\bigoplus$? How does $\operatorname{Ind}^G_H$ behave with respect to $\bigoplus$? What are the properties of $\operatorname{Ind}^G_H$ with regard to taking dir...
Induced representation is a left adjoint functor, so it preserves colimits, in particular arbitrary direct sums.
prophetes.ai