trigonometrical

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Trigonometry - Wikipedia
Trigonometry is a branch of mathematics concerned with relationships between angles and side lengths of triangles. In particular, the trigonometric ... en.wikipedia.org
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trigonometrical, adj. meanings, etymology and more | Oxford English ...
trigonometrical is of multiple origins. Either (i) formed within English, by derivation. Or (ii) a borrowing from Latin, combined with English elements. www.oed.com
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trigonometrical - Wiktionary, the free dictionary
trigonometrical (not comparable). Of, pertaining to, or obtained using trigonometry. Derived terms. edit · trigonometrical station. en.wiktionary.org
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trigonometrical
trigonometrical, a. (ˌtrɪgənəʊˈmɛtrɪkəl) [f. trigonometry or mod.L. trigonometria + -ic + -al1; after geometrical, etc.] Of, pertaining to, or performed by trigonometry. trigonometrical functions, those functions of an angle, or of an abstract quantity, used in trigonometry, viz. the sine, tangent, ... Oxford English Dictionary
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Great Trigonometrical Survey - Wikipedia
The Great Trigonometrical Survey of India was a project that aimed to carry out a survey across the Indian subcontinent with scientific precision. en.wikipedia.org
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"TRIGONOMETRICAL": Relating to angles or triangles - OneLook
We found 13 dictionaries that define the word trigonometrical: General (12 matching dictionaries). trigonometrical: Oxford English Dictionary ... onelook.com
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Great Trigonometrical Survey
The Great Trigonometrical Survey was a project that aimed to survey the entire Indian subcontinent with scientific precision. Walker to amalgamate the Great Trigonometrical, Topographical and Revenue Surveys into the Survey of India. wikipedia.org
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[PDF] 4.2 The Trigonometrical Ratios - Mathcentre
The side opposite the right-angle is called the hypotenuse. The side opposite to θ is BC. The remaining side, AB, is said to be adjacent to θ. www.mathcentre.ac.uk
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Maps and Map-making in India | The Great Trigonometrical Survey
The Great Trigonometrical Survey (GTS) was a part of the larger Survey of India. Whereas the Survey of India acquired geographical information mostly through ... apps.lib.umich.edu
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TRIGONOMETRIC Definition & Meaning - Merriam-Webster
The meaning of TRIGONOMETRIC is of, relating to, or being in accordance with trigonometry. www.merriam-webster.com
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TRIGONOMETRICAL FUNCTIONS. - Emerald Insight
In the right-angled triangle B A C with A B as radius, describe the arc E B F. In the triangle B A C let A B = c, A C = b, B C = a, we then have 1. sine A. www.emerald.com
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Trigonometrical equations Find the general solution of the equation $\sin x + \sin 2x + \sin 3x = 0$. I have started doing this problem by applying the formula of $\sin A + \sin B$ but couldn't generalise it. Please s...
HINT: Using Prosthaphaeresis Formulas, $$\sin x+\sin3x=2\sin\frac{3x+x}2\cos\frac{3x-x}2$$ We can also use $\sin x=\sin(2x-x),\sin3x=\sin(2x+x)$ Now $\sin y=0\implies y=n\pi$ and $\cos A=\cos B\implies A=2m\pi\pm B$ where $m,n$ are arbitrary integers
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Trigonometrical solution of complex equation Need present in trigonometrical form the solution of the complex equation: $x^6 = 1 + \sqrt3 + (1-\sqrt3)i$ To take out the coefficients of the real & imaginary parts re...
So, you know that $\cos\theta=\frac{1+\sqrt3}{2\sqrt2}$ and that $\sin\theta=\frac{1-\sqrt3}{2\sqrt2}$. Therefore, $2\sin(\theta)\cos(\theta)=-\frac12$, which means that $\sin(2\theta)=\sin\left(-\frac\pi6\right)$. This suggests (and it is easy to prove) that $\theta=-\frac\pi{12}$. So$$x^6=2\sqrt2\...
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Trigonometrical Solve There are 2 different values of $ \ \theta \ $. They are $ \ a \ $ and $ \ b \ $, such that $ \ 0 \ < \ a,b \ < \ 360^\circ \ $. If $ \ \sin(\theta+\phi) = \frac{1}{2} \sin2\phi \ $ , prove tha...
We have $\displaystyle\sin\theta\cos\phi=\sin\phi(\cos\phi-\cos\theta)$ Squaring we get $\displaystyle\sin^2\theta\cos^2\phi=\sin^2\phi(\cos\phi-\cos\theta)^2$ $\displaystyle\implies \sin^2\phi(\cos^2\phi+\cos^2\theta-2\cos\phi\cos\theta)=(1-\cos^2\theta)\cos^2\phi$ $\displaystyle\iff \cos^2\theta-2...
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Trigonometrical relation (searching a easy way to see it). In the figure I want to know $cos(\phi)$. I only know the cosines $cos(\theta)$ and $cos(\eta)$. A is in the xy plane. ![enter image description here]( I can...
Let $C$ be placed on the $x$-axis such that $AC\perp OC$. Thus, since also $OC\perp AB$, we obtain $OC\perp(ABC)$, which says $OC\perp BC$. From here we get $\cos\varphi=\cos\theta\cos\eta$ immediately: $$\cos\varphi=\frac{OC}{OB}=\frac{AO}{OB}\cdot\frac{OC}{OA}=\cos\theta\cos\eta.$$
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