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spital

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spital
spital (ˈspɪtəl) Also 7 spitall, 8 spittal. [Late respelling of spittle n.1 after hospital.] 1. = spittle n.1 1. Also in phr. to rob the spital.1634 Younger Brother's Apol. 50 Bryand Lyle,..hauing two sonnes, both leprous, built for them a Lazaretto or Spitall. 1648 Hexham ii. App., Spitael, a Spita... Oxford English Dictionary
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Spital
Spital-in-the-Street, a hamlet in Lincolnshire Spital, Merseyside, on the Wirral Peninsula Spital railway station Spittal, Northumberland, a seaside resort Spital, Tamworth, a Ward of Tamworth Borough Council Spital Tongues, an area of Newcastle upon Tyne Spital Brook, a tributary of the River Lea in Hertfordshire wikipedia.org
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Spital, Merseyside
Toponym The name "Spital" is a place or building known as a "spital house" that acted as a hospital or colony for lepers. Other original names of the village were "Poulton cum Spital" and "Spital Old Hall" until Spital was formally adopted at the end of the 19th century. wikipedia.org
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GALA BINGO - Spital Street, Dartford, Kent, United Kingdom - Yelp
Gala Bingo in Dartford, reviews by real people. Yelp is a fun and easy way to find, recommend and talk about what's great and not so great in Dartford and beyond.
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Proving that $\lim_{n\to\infty}\left ( \frac{2n-1}{2n+3} \right )^n=e^{-2}$ without using de l‘Hôspital > $$\lim_{n\to\infty}\left ( \frac{2n-1}{2n+3} \right )^n=\frac{1}{e^2}.$$ But how do I prove this without using...
Knowing that $$e^a =\lim_{x\to \infty}\left(1+\frac{a}{x}\right)^x$$ we have $$\lim_{n\to\infty}\left ( \frac{2n-1}{2n+3} \right )^n=\lim_{n\to\infty}\left ( 1 - \frac{4}{2n+3} \right )^{2n+3\frac{n}{2n+3}}\overset{x=2n+3}{=} \lim_{x\to\infty}\left ( 1 - \frac{4}{x} \right )^{\frac{x}{2}}=e^{-2}.$$
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Spital, Derbyshire
The main road here is Spital Lane. Spital also has 2 parks one located at the top of Valley Road the other is along Spital Lane heading towards Calow Lane. Spital also has a cemetery. wikipedia.org
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Otto-Wagner-Spital
The Otto-Wagner-Spital () is a hospital in Vienna, Austria. It was originally a psychiatric hospital and center for pulmonology. In 2000, five health facilities were consolidated under the label Sozialmedizinisches Zentrum Baumgartner Höhe - Otto Wagner Spital mit Pflegezentrum ( wikipedia.org
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Evaluating $\lim_{x\to 0}\frac{x}{2^x-1}$ without using L'Hôspital's rule So lately, when one my friends had asked for help, he showed me this task: > Evaluate the following limit $$\lim_{x\to 0}\frac{x}{2^x-1}$$ Th...
Since we are not allowed to use derivative we need to start from some well grounded point. Usually the starting point is the following limit for sequences (wich can be proved by monotonicity theorem): $$\lim_{n\to \infty}\left(1+\frac1n\right)^n =e$$ which can be easily extended to real functions $$...
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Spital Brook
Spital Brook is a minor tributary of the River Lea which rises in Hoddesdonpark Wood in the county of Hertfordshire, England. References Rivers of Hertfordshire Tributaries of the River Lea 1Spital wikipedia.org
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How do I show that $\lim_{x\rightarrow\pm\infty}\frac{\ln(x^2+1)}{x} = 0$ without L'Hôspital's rule? Without the use of series of L'Hôspital's rule, therefore with common limits and some intuition. I wanted to use th...
Let me consider only the $x\to+\infty$ case, as the other case follows trivially. Substituting $x\mapsto e^x$ shows $$\lim_{x\to\infty}\frac{\ln x}x=\lim_{x\to\infty}\frac x{e^x}=0$$ Now $$0\le\frac{\ln(x^2+1)}x\le\frac{\ln(2x^2)}x=\frac{\ln 2+2\ln x}x\to 0$$ So the limit is zero by squeezing.
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Spital Tongues
North of Spital Tongues is Leazes Park and the Town Moor. the proximity of the area to Newcastle city centre Satellite view of Spital Tongues, giving a good idea of the green fields surrounding the area Spital wikipedia.org
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How to Solve This Exponential Limit without Derivate / L'Hôspital's Rule can someone teach me how can I solve this limit without using the L'Hopital's Rule? $$\lim_{x\to 0} \left( \frac{2+x^{2}}{2-x^{2}} \right)^{\fr...
$$ \frac{2+x^2}{2-x^2}=1+\frac{2x^2}{2-x^2}=1+\frac{x^2}{1-\frac{x^2}{2}} $$ and $y=\frac{x^2}{1-\frac{x^2}{2}}\to 0$, as $x\to 0$. Hence $$ \left(1+\frac{x^2}{1-\frac{x^2}{2}}\right)^{\frac{1-\frac{x^2}{2}}{x^2}}=(1+y)^{1/y}\to e, $$ as $x\to 0$. Finally $$ \left(\frac{2+x^2}{2-x^2}\right)^{1/x^2}=...
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Spital am Pyhrn
Spital am Pyhrn is a municipality in the district of Kirchdorf an der Krems in the Austrian state of Upper Austria. Geography Spital lies in the Traunviertel. About 48 percent of the municipality is forest, and 19 percent is farmland. wikipedia.org
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Finding limit using l'hôspital We're supposed to find the following limits by applying l'Hôspital rule: $$ \lim_{x \to \infty} x^{sin(1/x)} $$ My idea was to view the limit as y, then evaluate ln(y). However, I wasn'...
HINT. $$e^{\frac{\ln x}{\sin^{-1} (1/x)}}=e^{-\frac{\ln t}{\sin^{-1} t}}\underbrace=_H e^{\frac{\sin t}{t}\frac{\sin t}{\cos t}}\rightarrow 1 \ \ \ (t\rightarrow 0)$$
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Spital-in-the-Street
Spital-in-the-Street is a small hamlet in the West Lindsey district of Lincolnshire, England. The first part of its name, "Spital", comes from the ancient hospital for the poor which was situated here, having its origins in a Hermitage. wikipedia.org
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