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semicircular
semicircular, a. (sɛmɪˈsɜːkjʊlə(r)) Also 5 -er. [ad. med.L. sēmicirculāris, f. L. sēmicircul-us semicircle. Cf. F. semi-circulaire.] Of the form of a semicircle.1432–50 tr. Higden (Rolls) IV. 101 After auctores theatrum is proprely a flore semicirculer, in the myddes of whom was an howse whiche was ...
Oxford English Dictionary
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Semicircular bund
A semi-circular bund (also known as a demi-lune or half-moon) is a rainwater harvesting technique consisting in digging semilunar holes in the ground with the opening perpendicular to the flow of water. Background These holes are oriented against the slope of the ground, generating a small dike in t...
wikipedia.org
en.wikipedia.org
semicircular
semicircular/ˌsemɪˈsɜ:kjulə(r); ˌsɛmɪ`səkjəlɚ/ adjhaving the shape of a semicircle 半圆形的.
牛津英汉双解词典
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Head rotation evoked tinnitus due to superior semicircular canal ...
This paper reports a case of head rotation evoked tinnitus due to superior semicircular canal dehiscence. Head rotation with a velocity of over 600°/second in the plane of the superior semicircular canal induced a cricket-like sound at the right ear; the diagnosis was also supported by (a) high resolution temporal bone computed tomography ...
www.ncbi.nlm.nih.gov
Semicircular canals
The semicircular canals or semicircular ducts are three semicircular, interconnected tubes located in the innermost part of each ear, the inner ear. of the semicircular canals.
wikipedia.org
en.wikipedia.org
Using Semi-circle find side of triangle The figure below above shown a bicycle path. If semicircular portion $ABC$ is $100$ $\pi$ and $CD$ is $100$$ft$ then what is $AD$? ![a busy cat\]\('\) !\two muppets I have tr...
The ratio of a circle's circumference to its diameter is $\pi$: $$\frac{\text{circumference}}{\text{diameter}}=\pi.$$The length of the semicircle arc is **half** the circumference of what would be the full circle. Thus, $$\frac{\text{semicircle}}{\text{diameter}}=\frac{\frac{1}{2}\cdot\text{circumfe...
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Semicircular potential well
Similarly, if the semicircular potential well is a finite well, the solution will resemble that of the finite potential well where the angular operators
wikipedia.org
en.wikipedia.org
The solid with a semicircular base of radius 5 whose cross sections perpendicular to the base and parallel to the diameter are squares How would I go about solving this problem? I'm stuck.
For a square base parallel to the x-axis, you can use the formula: $$ \int_a^b f\left(y\right)^2 dy $$ The equation for a circle is $$ x^2+y^2=r^2 \\\ x=\sqrt{25-y^2} $$ The endpoints of integration are $y=0$ to $y=5$. Also, since rewriting this formula, we only get the half of the circle in positiv...
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Centroid of a semicircle vs. a semicircular arc Why is the $y$ centroid of a semicircle and that of a semicircular arc different? Using Pappus' second theorem on a semicircle of radius $r$, $\bar{y}=\frac{V}{2\pi A}=...
To answer your first question - why the centroids of a half-disk and half-arc are different, imagine their physical manifestations: both are objects having the same mass. The former is a half-disk of material that is evenly distributed throughout. The latter is also a half-disk, but it has all of it...
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Equilateral triangle in Semicircular I have a geometry question. In this question, We have a Equilateral triangle ($ \triangle BDC$) that we draw it with one point on the circle and 2 point on the diameter. We want to...
As you can see from the picture, your claim is not true. You need some other hypotheses.  dx$ I have noticed that $\begin{align*}\int_{-\infty}^{\infty}f(x) dx \end{align*}$ can be solved using residue theorem...
exists,
$$\int_{-\infty}^{\infty} = \lim_{r \to \infty} \int_{-r}^r = \lim_{r \to \infty} \left( \oint_{\text{boundary of semicircle}} - \int_{\text{semicircular $$
A typical proof method using this fact is:
* Compute $\oint_{\text{boundary of semicircle}}$ by the residue theorem
* Show that $\int_{\text{semicircular
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Integral on semicircular arc of a function with a simple pole at $z=0$ Let $C(\epsilon)$ denote the semicircular arc about $z=0$. Suppose $f(z)$ is a meromorphic function that has a simple pole at $z=0$. I'm trying to...
It's not hard to show that sum tends to $0$ with $\epsilon$. But there's no reason it has to come up. Instead of starting with the Laurent series start with $b_{-1}/z + g(z)$, where $g$ is holomorphic near the origin, hence bounded in some neighborhood of the origin.
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Why does the direction of endolymph flow oppose direction of body motion? In the semicircular canals, the endolymph always flows in a direction that is opposite to the motion of the vestibular apparatus itself. I’m ha...
The ear and semicircular canals themselves are fairly solidly connected to the rest of the body and so accelerate smoothly.
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geometry question on areas in arcs PS is a line segment of length 4 and O is the midpoint of PS. A semicircular arc is drawn with PS as diameter. Let X be the midpoint of this arc. Q and R are points on the arc PXS su...
This diagram will help: ![enter image description here]( Note that I have connected $OQ$ and $OR$ - these are both equal to the radius of the blue circle centered at $O$ and so their lengths must be equal to $2$. I have also labelled the intersection of $QR$ and $OX$ as $Y$. From the question statem...
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Is this Complex Integration correct? I want to integrate $\displaystyle \int_{-\infty}^\infty dx \, e^{iax}\frac{1-e^{-bx^2}}{x^2}$ for a>0. I am going to try and do this using the method of contour integration. I wi...
You are mistaken. The integral along the circular arc emphatically does not vanish. You can see this by writing it out: $$i R \int_0^{\pi} d\theta \, e^{i \theta} \, e^{i a R e^{i \theta}} \frac{1-e^{-b R^2 e^{i 2 \theta}}}{R^2 e^{i 2 \theta}} $$ The magnitude of this integral is bounded by $$\frac1...
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