This diagram will help:
![enter image description here](
Note that I have connected $OQ$ and $OR$ - these are both equal to the radius of the blue circle centered at $O$ and so their lengths must be equal to $2$.
I have also labelled the intersection of $QR$ and $OX$ as $Y$. From the question statement it is clear that:$$QY=YR=OY$$ and I have labelled this length as $a$.
Now note in triangle $OYR$ that $OY=YR$ and angle $OYR=90^{\circ}$. This implies that angles $YOR=YRO=45^{\circ}$.
Using similar arguments you can deduce that angles $YOQ=YQO=45^{\circ}$.
This should give you enough information to be able to calculate the value of $a$ and hence calculate the area you require.