portmanteau

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portmanteau
▪ I. portmanteau, n. (pɔətˈmæntəʊ) Forms: see below. [ad. F. portemanteau (1547 in Godef. Compl.) an officer who carries a prince's mantle, a valise, a clothes-rack, f. porte- + manteau (OF. mantel) mantle; see also manteau, mantua, pockmanteau.] 1. a. A case or bag for carrying clothing and other n... Oxford English Dictionary
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Portmanteau (disambiguation)
Portmanteau may also refer to: Portmanteau (luggage), a case or bag to carry clothes in that usually opens into two equally sized compartments Portmanteau (mail), a specialized mail bag Portmanteau film, an anthology film made up of several short films that interrelate Portmanteau inhibitor, in pharmaceuticals wikipedia.org
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portmanteau
portmanteau/pɔ:tˈmæntəu; pɔrt`mænto/ n(pl ~s or -teaux / -təuz; -toz/) (dated 旧) large oblong (usu leather) case for clothes that opens on a hinge into two equal parts 旅行衣箱(通常为皮制, 以合叶联接相同的两部分). 牛津英汉双解词典
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Portmanteau (luggage)
A portmanteau is a piece of luggage, usually made of leather and opening into two equal parts. Portmanteau mail bag In the 1700s the term would also have described a Mail bag. This continued in the 1800s for bags used by the Post Office. wikipedia.org
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Portmanteau inhibitor
A portmanteau inhibitor is a drug that is a combination of two drug molecules, each of which is itself a type of inhibitor. wikipedia.org
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portmanteau word
portmanteau word(also blend) invented word that combines parts of two words and their meanings eg motel from motor and hotel or brunch from breakfast and lunch 紧缩词, 合并词(将两个词的词素合并构成一个新词, 如 motel 为 motor 和 hotel 的紧缩词, brunch 为 breakfast 和 lunch 的紧缩词). 牛津英汉双解词典
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Portmanteau test
A portmanteau test is a type of statistical hypothesis test in which the null hypothesis is well specified, but the alternative hypothesis is more loosely This portmanteau test is useful in working with ARIMA models. wikipedia.org
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Portmanteau Theorem and lipschitz functions In the Portmanteau Theorem, on the equivalence forms of weak convergence for random vectors $X_n\to X$, the fact that $E[f(X_n)]\to E[f(X)]$ for all Lipschitz function is us...
If $G$ is not open, then there does, in general, not exist a sequence of Lipschitz functions $(f_n)_{n \in \mathbb{N}}$ such that $0 \leq f_n \uparrow 1_G$. Consider for instance $G=[0,1]$. Take a sequence of (Lipschitz) continuous functions $(f_n)_n$ such that $0 \leq f_n(0) \uparrow 1_{[0,1]}(0)=1...
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Portmanteau - xrthnty.blogspot.com
Clash Royale CLAN TAG #URR8PPP For other uses, see Portmanteau (disambiguation). A portmanteau ( / p ɔːr t ˈ m æ n t oʊ / ( listen ) , ...
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Portmanteau lemma: Prove that 4 implies 2 If lim inf $E[f(X_n)] \geq E[f(X)]$ for any non-negative, continuous function $f(.)$ then $E[g(X_n)]=E[g(X)]$ for all bounded, continuous functions $g(.)$., where $X_n$ define...
Let $f$ be any bounded continuous function and $M$ be its supremum. Then $M-f$ is a non-negative continous function so $\lim \inf E(M-f(X_n)) \geq E(M-f(X))$. Cancelling $M$ we get $\lim \sup Ef(X_n) \leq Ef(X)$. Changing $f$ to $-f$ we get $\lim \inf Ef(X_n) \geq Ef(X)$. Hence $\lim Ef(X_n)=Ef(X)$.
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混成词
术语起源 portmanteau 代表混成词的用法源自路易斯·卡罗1871年的《爱丽丝镜中奇遇》。 最初以 portmanteau word 指混成词,最先收录于1990年代早期出版的辞典,其后缩略为 portmanteau,用法渐渐普及起来。 构词法 语言学中,「混成词素」指混合了两项语法范畴(参见屈折语)的词素。在英语中,动词后缀「-s」是一个典型例子。 wikipedia.org
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Continuity sets are neccesary for weak convergence. Portmanteau theorem In particular if $\mu_n \to \mu$ weakly then $\mu_n(A)\to \mu(A)$ for each continuity set. I want an example to show that the hypothesis of $\...
The problem in your attempt is that $\mathbf 1_A$ is not continuous in general, hence we cannot use the definition of weak convergence. However, defining $\mu_n:=n\mathbf 1_{(0,1/n]}\lambda$, that is, $\mu_n(A)=n\lambda(A\cap (0,1/n])$, we have that $\mu_n\to\delta_0$ weakly, $\mu_n(\\{0\\})=0$ for ...
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property of borel measures I am reading chapter 1.3 in weak convergence and empirical processes of Van der Vaart and Wellner. Let $(\mathbb{D}, d)$ a metric space and let $L$ a Borel probability measure. In the proof ...
For $k \in \mathbb{N}$, define $A_k = \\{ \epsilon > 0: L(\delta F^{\epsilon}) > \frac{1}{k} \\}$. Notice that $A:= \bigcup_k A_k = \\{ \epsilon > 0: L(\delta F^{\epsilon}) > 0 \\}$. Suppose $A$ is uncountable. Then at least one of the $A_k$ must be uncountable and in particular infinite. But if som...
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