For $k \in \mathbb{N}$, define $A_k = \\{ \epsilon > 0: L(\delta F^{\epsilon}) > \frac{1}{k} \\}$. Notice that $A:= \bigcup_k A_k = \\{ \epsilon > 0: L(\delta F^{\epsilon}) > 0 \\}$.
Suppose $A$ is uncountable. Then at least one of the $A_k$ must be uncountable and in particular infinite. But if some $A_k$ is infinite, then by disjointness of the $\delta F^{\epsilon}$, $L(\mathbb{D})$ would be infinite, which is a contradiction.