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passman

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passman
passman (ˈpɑːsmən, ˈpæs-) [f. pass n.2 + man.] a. In some universities: A student who reads for and takes a ‘pass’ degree; opposed to honour- or honours-man, class-man.1860 Burrows Pass & Class i. 6 A place in either Class List will distinguish him from the Pass-men. 1888 Bryce Amer. Commw. III. vi.... Oxford English Dictionary
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Passman
Passman (also called Passman Jewelry) is a line of black coral jewelry currently produced by Brindle & Fig under license. The brand was created in 1975 by Bernard Passman, sculptor and jeweler, on Grand Cayman. wikipedia.org
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Passman (surname)
Passman is a surname. Notable people with the surname include: Al Passman (1923–1984), Canadian football player Bernard K. Passman (1916–2007), American sculptor and jeweler Donald S. Passman (born 1940), American mathematician George Passman Tate (1856–?) wikipedia.org
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Richard Passman
Early life and education Passman was born in Cedarhurst, New York, to Ethel and Matthew Passman. Personal life and death Passman was married to Minna for 70 years. wikipedia.org
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Exact Sequences of R-Modules In "A Course in Ring Theory by Passman" it is mentioned, "But the kernel of the combined epimorphism $P\rightarrow B\rightarrow C$ is clearly equal to $E$". I don't understand this part. H...
Let $\psi : B\to C$ and $\pi : P \to B$ be the relevant maps, then $$ \ker(\psi\circ\pi) = \\{x \in P : \psi(\pi(x)) = 0\\} = \\{x\in P : \pi(x) \in \ker(\psi)\\} $$ Since $0 \to A\hookrightarrow B\xrightarrow{\psi} C \to 0$ is exact, $\ker(\psi) = A$, hence $$\ker(\psi\circ\pi) = \pi^{-1}(A)$$ whic...
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Bernard K. Passman
Passman (22 January 1916 – 10 February 2007) was a sculptor and jeweller, founder of a black coral jewellery company and brand, Passman (currently produced Passman founded the eponymous Passman in 1975 on Grand Cayman. wikipedia.org
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Projective Dimension and Supremum Here is a lemma that appears in A Course in Ring Theory by Passman. In the last section of the proof the writer shows that, $\mbox{pd }A_i\leq n\iff \mbox{pd }A\leq n$ and finishes th...
A supremum is an upper bound so $\operatorname{pd}A_i \leq \sup\\{\operatorname{pd}A_i \ | \ i\\}$. Letting $n = \sup\\{\operatorname{pd}A_i \ | \ i\\}$ then gives $\operatorname{pd}A \leq \sup\\{\operatorname{pd}A_i \ | \ i\\}$. Conversely $\operatorname{pd}A \leq \operatorname{pd}A$ so letting $n ...
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Tina Passman
Passman has voiced interpretations that recognized a "patriarchal voice" in the Homeric Hymn to Demeter. Passman, Kristina M. "The Classical Amazon in Contemporary Cinema." The Bucknell Review 35.1 (1991): 81. wikipedia.org
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Annihilator and Projective Dimension I was reading the book A Course in Ring Theory by Passman and in it is the following lemma; !enter image description here and after this lemma there's a example which I don't qui...
$K[x]$ means the polynomial ring over $K$. You can prove $K[X]/(x^2)$ is isomorphic to the direct sum $K\dot{+}K\bar{x}$, where $\bar{x}^2=0$, by thinking about the homomorphism $$\phi:K[X]\to K\dot{+}K\bar{x}$$ sending $p(x)$ to $p(\bar{x})$, which is also just the remainder of $p(x)$ when divided ...
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Al Passman
Allan Passman (May 5, 1923 – June 30, 1984) was a Canadian football player who played for the Winnipeg Blue Bombers and Calgary Stampeders. wikipedia.org
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Basis for Quotient Ring of Group Ring I recently read a paper from passman " _Observation On Group Rings_ " and I came across a sentence below: Let $H\lhd G$ and let $ B=\\{B_1,B_2,B_3,...\\}\subseteq K[H]$ be a $K-$...
It's not a quotient ring; it's a quotient of ideals (so it forms a representation). Select coset representatives for each element of a basis of the quotient.
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Donald S. Passman
Passman has written 7 books and more than 180 research publications. In 1963 Passman married Marjorie Mednick. wikipedia.org
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Why is a semisimple (Wedderburn) ring von Neumann regular? In exercise 6 of chapter 5 Passman's "A Course in Ring Theory" he asks us to prove that every semisimple (Or Wedderburn as he calls it) ring is von Neumann re...
A ring $R$ is von Neumann regular if and only if each principal left ideal is generated by an idempotent. In a semisimple ring, every left ideal is a direct summand.
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慰藉物
Passman, R. H. (1987). Attachments to inanimate objects: Are children who have security blankets insecure? Passman, R. H., & Lautmann, L. A. (1982). wikipedia.org
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George Passman Tate
George Passman Tate, FRGS, (1856–?) was an Anglo-Indian surveyor and authority on the history of Afghanistan. wikipedia.org
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