Artificial intelligent assistant

oint

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OINT: Trusted Full-Service Orthopedic Care in North Texas
We're the Orthopedic Institute of North Texas (OINT), and we are a leader in excellent, compassionate, full-service, patient-focused orthopedic surgery in ... www.oint.org
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OINT Definition & Meaning - Merriam-Webster
The meaning of OINT is anoint. www.merriam-webster.com
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OINT definition in American English - Collins Dictionary
oint in British English (ɔɪnt IPA Pronunciation Guide ) verb (transitive) to anoint or smear with oil Collins English Dictionary. www.collinsdictionary.com
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oint
oint, v. Obs. or arch. Forms: 4–8 oynt, 6 oynct, 6–9 oint. [f. F. oint, 3 sing. pres. ind., or pa. pple. of oindre:—L. ung(u)ĕre to anoint.] trans. = anoint v.1375 Creation 632 in Horstmann Altengl. Leg. (1878) 132 Of oyle taken ȝow som del, Wherwiþ ȝe mowen oynten me wel. ? a 1400 Cursor M. 7377 (C... Oxford English Dictionary
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oint, v. meanings, etymology and more | Oxford English Dictionary
The earliest known use of the verb oint is in the Middle English period (1150—1500). OED's earliest evidence for oint is from before 1382, in Bible ... www.oed.com
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oint - Word Root - Membean
The word part "oint" is a root that means "smear with oil". membean.com
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oint-plaster
† ˈoint-plaster Obs. In 6 oynt-playster. [Cf. oint v., also OF. oint n.] A plaster of ointment.1578 Lyte Dodoens iii. cxiii. 306 To be applyed, outwardly in oynt-playsters. Oxford English Dictionary
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oint - Wiktionary, the free dictionary
Old French. edit. Etymology 1. edit. From Latin unctus. Verb. edit. oint. past participle of oindre. Descendants. edit. Middle French: oint. French: oint ... en.wiktionary.org
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OINT (@ointortho) • Instagram photos and videos
Full-service orthopedic surgery practice. Frisco, Dallas and Flower Mound - Texas. Visit our website. 5575 Warren Parkway, Suite 115, Frisco, Texas 75034 www.instagram.com
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5-letter words containing OINT - Merriam-Webster
5-Letter Words Containing OINT: joint, noint, oints, point, roint. www.merriam-webster.com
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ointment and ointement - Middle English Compendium
Forms, oint(e)ment n. Also nointment, unt(e)ment, uintment, ungtment. Etymology, Blend of oinement & enointment. Some examples preceded by an may be vars. quod.lib.umich.edu
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What situations should $\oint$ be used? Sometimes people put a circle through the integral symbol: $\oint$ What does this mean, and when should we use this integration symbol?
This symbol is used to indicate a line integral along a closed loop. if the loop is the boundary of a compact region $\Omega$ we use also the symbol $ \int_{\delta \Omega} $ we can generalize such notation to the boundary of a region in an n-dimensional space and, if $\Omega$ is an orientable manifo...
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For the positively oriented circle, $\oint_{|z|=1}\frac{2\Re(z)}{z+1}dz=......$ > For the positively oriented circle, $\oint_{|z|=1}\frac{2\Re(z)}{z+1}dz=......$ > > (a) $0$ > > (b) $\pi i$ > > (c) $2\pi i$ > > (d...
By letting $z=e^{i\theta}$ we have $dz= i e^{i\theta}d\theta$ and the wanted integral equals $$ \int_{-\pi}^{\pi}\frac{\text{Re}(e^{i\theta})}{1+e^{i\theta}}ie^{i\theta}\,d\theta =i\int_{-\pi}^{\pi}\frac{\cos\theta(e^{i\theta}+1)}{2+2\cos\theta}\,d\theta=i\color{blue}{\int_{-\pi}^{\pi}\frac{\cos\the...
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From $ \oint \frac{\phi(t)}{t - z} dt = 0$ prove that $ \oint \frac{t \phi(t)}{t - z} dt = 0$ Let $D$ - a simply connected bounded domain and $\phi(t)∈C(\partial D)$. And let $ \displaystyle \oint \frac{\phi(t)}{t - z...
You didn't really say what you mean by $dt$ (some kind of arc length measure, I'm assuming). Ignoring this issue, we have that $$ \int \frac{t\phi(t)}{t-z}\, dt = \int \frac{(t-z+z)\phi(t)}{t-z}\, dt =\int\phi(t)\, dt , $$ so the (holomorphic) function $F(z)=\int\frac{t\phi(t)}{t-z}\, dt$ is constan...
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Why is $\oint_p \frac{1}{z} dz=0$ in simply connected regions? According to Cauchy's Theorem, $\oint_p f(z) dz=0$ for any function $f(z)$ holomorphic on a simply connected region $U$ along any closed-path around any p...
As said in the comments, Cauchy's theorem only applies to simply connected regions. For example, if you choose $U=\mathbb C\setminus \\{0\\}$, then $\frac1z$ is holomorphic in $U$, but $U$ is not simply connected. If $U$ is simply connected and does not contain $0$, then you cannot find a path that ...
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