Artificial intelligent assistant

nither

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1
nither
▪ I. nither, v. Obs. exc. north. dial. and Sc. (ˈnɪðə(r)) Forms: α. 1 niðerian, nyðerian, (h)niðrian, 2 nytheren (2–3 niþeren, 3 niþþrenn), 7– Sc. and north. nither; 6 Sc. nydder, 8 nidder. β. 3 neoðerien, 5, 7 Sc. and north. nether, 7 Sc. nedder. [OE. niðerian, etc. (also ᵹeniðerian) = OFris. (for)... Oxford English Dictionary
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Neither vs Nither - What's the difference? | WikiDiff
Usage notes * Neither is used to mean none of two or more. Although some suggest that using the word neither with more than two items is incorrect, it has been commonly used to refer to more than two subjects since the 17th century. The more modern usage does prefer none with more than two things. * There is considerable variation in the number of the verb employed with this construction.
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Sherko Moarefi
Nither Moarefi nor his lawyers received advance warning of his execution. He was executed by hanging on November 4, 2013. wikipedia.org
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nidder
nidder variant of nither v. Oxford English Dictionary
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Culture of Jember
Nither training programs nor competitions were held by the government to attract the Jember artists interested in order to developing the cultural. wikipedia.org
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i-niþered
i-niþered ME. pa. pple. of nither v. Oxford English Dictionary
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nedder
▪ I. nedder variant of nither v.▪ II. nedder, -ir, -re obs. ff. adder, nether. Oxford English Dictionary
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anither
† aˈnether, aˈnither, v. Obs. [f. a- prefix 1 + OE. niðerian to lower: see nether. Cf. Ger. erniedrigen.] To bring down, lower, reduce, humiliate.a 1121 O.E. Chron. (Laud MS.) an. 675 Aniðrod mid Iudas and mid ealle deofle on helle. 1205 Lay. 14861 Þus we scullen an ure daȝen{revsc} aniðeri [1250 a-... Oxford English Dictionary
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nyðere
nyþer(e, nyðer(e see nether a. and adv.; nither v. Oxford English Dictionary
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nydder
nydder obs. Sc. variant of nither v. Oxford English Dictionary
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nethring
nethring see nither v. Oxford English Dictionary
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Determine whether a given language $L$ is regular , CFL or nither. Let > $$L=\left\\{w\in\\{a,b,c\\}^{\ast}\Bigg\vert \exists \sigma_1,\sigma_2\in\\{a,b,c\\}\text{ s.t } \\#_{\sigma_1}(w)\ne \\#_{\sigma_2}(w)\right\\...
A word is in $L$ iff either the number of $a$'s is not equal to the number of $b$'s, or the number of $c$'s, or if the number of $b$'s and $c$'s is unequal, hence we have \begin{align*} L = & \\{ w \in \\{a,b,c\\}^{\ast} \mid \\#_a(w) \ne \\#_b(w) \\} \\\ & ~ \cup \\{ w \in \\{a,b,c\\}^{\ast} \mid \...
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To show $ax^{2}+bx+c$ is neither injective or surjective. I want to show that $\displaystyle ax^{2}+bx+c$ is nither injective nor surjective where $a,b,c\in \mathbb{R}$ and $a\neq 0$. Can i use the following result? ...
If you complete the square, you will know all. We have $$ax^2 + bx + c = a\left(x^2 + {b\over a} x \right) + c = a\left(x + {b\over 2a}\right)^2 + c - {b^2\over 4a}. $$ If $f(x) = ax^2 + bx + c$, we have $$f(x) = a\left(x + {b\over 2a}\right)^2 + {4ac - b^2\over 4a}.$$ if $a > 0$ then $f(x)\ge {4ac-...
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neither
▪ I. neither, adv. (conj.) and a. (pron.) (ˈniːðə(r), ˈnaɪðə(r)) Forms: α. 2 naiðer, 5 nayther, 6 Sc. naythir; 4 neyþur, 4–5 -der, 5– -þer, -þir, thir, -thyr, -dyr, 5–7 -ther; 5 neider, neiþir, 3–5 neiþer, 5– neither. β. 4 nethir, (5 -yr), 4–5 neþer, 6–7 nether, (6 -ar, neder); 5 neethur, -yr. γ. 5–... Oxford English Dictionary
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nether
▪ I. nether, a. (ˈnɛðə(r)) Forms: 1 nioðerra, niðera, nyðera, 3 nyþere; 1 neoþ(e)ra, 3 neoþere; 4 nethere, 4–5 neþer, (5 -ire), 5–6 nethir, (5 -yr, Sc. nathir), neder, (6 -ur, Sc. neddir); 4 nei-, neyþer, 6 neyther, 7 neither, 6–7 neather; 5– nether. [Common Teut.: OE. neoþera, niþera, etc., = OFris... Oxford English Dictionary
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