A word is in $L$ iff either the number of $a$'s is not equal to the number of $b$'s, or the number of $c$'s, or if the number of $b$'s and $c$'s is unequal, hence we have \begin{align*} L = & \\{ w \in \\{a,b,c\\}^{\ast} \mid \\#_a(w) \
e \\#_b(w) \\} \\\ & ~ \cup \\{ w \in \\{a,b,c\\}^{\ast} \mid \\#_a(w) \
e \\#_c(w) \\} \\\ & ~ \cup\\{ w \in \\{a,b,c\\}^{\ast} \mid \\#_b(w) \
e \\#_c(w) \\}. \end{align*} As the context-free languages are closed under union, you just have to find a grammar for $\\{ w \in \\{a,b,c\\}^{\ast} \mid \\#_a(w) \
e \\#_b(w) \\}$ and similar the other languages.
Do you know how to do that? Maybe you should think about a CFG for $$ \\{ w \in \\{a,b\\}^{\ast} \mid \\#_a(w) \
e \\#_b(w) \\} $$ first and then generalise!