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homogenize

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homogenize
homogenize, v. (həʊˈmɒdʒɪnaɪz) [f. homogene + -ize.] 1. a. trans. To render homogeneous; to unite or incorporate into a single whole of uniform composition; to make uniform or similar. Also fig.1886 Fortn. Rev. XL. 201 The whole island [Ireland] would have become homogenized by the action of strong ... Oxford English Dictionary
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homogenize
homogenizehomogenise, / həˈmɔdʒənaɪz; hə`mɑdʒəˌnaɪz/ v [Tn]1 treat (milk) so that the particles of fat are broken down and the cream is blended with the rest 对（牛奶）作均质处理（将脂肪微粒搅碎使奶油分布均匀）.2 make (sth) homogeneous 使（某物）成分均匀. 牛津英汉双解词典
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Nova Generatsiia
Additionally, the magazine has been praised for being the last in Ukraine to give in to the demands of the Communist Party when it sought to neuter and homogenize wikipedia.org
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homogenate
homogenate (həˈmɒdʒɪneɪt) [f. homogenize v. + -ate, after condensate, filtrate, etc.] The suspension of cell fragments and cell constituents that is obtained when tissue is homogenized.1941 V. R. Potter in Jrnl. Biol. Chem. CXLI. 775 Rat liver which had been freshly homogenized and diluted..was used... Oxford English Dictionary
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QuEChERS
Such instruments can homogenize the food sample in a centrifuge tube, then agitate the sample with the reagent of choice, before moving the extracted sample wikipedia.org
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homogenized
homogenized, ppl. a. (həˈmɒdʒɪnaɪzd) [f. homogenize v. + -ed1.] 1. Rendered uniform throughout in composition or character; loosely, = homogeneous a. 2.1935 G. E. Doan Princ. Physical Metall. iv. 140 The true solidus line of alloys of this kind is..determined..by reheating specimens of a completely ... Oxford English Dictionary
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Critical illumination
Alternatively, a ground or opal glass diffuser can be used to homogenize the light source, but this will cause a significant amount of light to be scattered wikipedia.org
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homogenizer
homogenizer (həˈmɒdʒɪnaɪzə(r)) [f. homogenize + -er1.] A machine or apparatus designed to homogenize some kind of material (as milk or tissue). Also fig.1886 Sci. Amer. 11 Dec. 371 The mixture is thoroughly amalgamated and ground together in an apparatus called by the inventors a ‘homogenizer’. 1908... Oxford English Dictionary
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Bazna pig
As the breed formed and developed, Yorkshire, Angler Sattelschwein, Wessex, and Hampshire breeds were all used to help homogenize and better it. wikipedia.org
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homogenization
homogenization (həˌmɒdʒɪnaɪˈzeɪʃən) [f. homogenize v. + -ation.] 1. The process of making or becoming homogeneous; the action of homogenizing. Also fig.1908 Practitioner June 830 Methods for concentrating the bacilli..depend mainly on the homogenisation of the sputum by means of dilute alkalies or o... Oxford English Dictionary
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Inequality Question - Homogeneity Let $n>3$ and $x_1, x_2, \ldots, x_n$ be positive real numbers with $x_1x_2\cdots x_n=1$. Prove that $$ \frac{1}{1+x_1+x_1x_2}+\frac{1}{1+x_2+x_2x_3}+\cdots+\frac{1}{1+x_n+x_nx_1}>1\....
You can make the homogenization by the following way. Let $x_1=\frac{a_2}{a_1},$ $x_2=\frac{a_3}{a_2},$..., $x_{n-1}=\frac{a_n}{a_{n-1}},$ where all $a_i>0$, $a_{n+1}=a_1$ and $a_{n+2}=a_2$. Thus, the condition gives $x_n=\frac{a_1}{a_n}$ and $$\sum_{i=1}^n\frac{1}{1+x_1+x_2}=\sum_{i=1}^n\frac{1}{1+...
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Inequality with condition $a^2+b^2+c^2=3$ Let $a,b,c>0$ with $a^2+b^2+c^2=3$. Prove that $$\frac{a^5}{b^3+c}+\frac{b^5}{c^3+a}+\frac{c^5}{a^3+c} \geq \frac{3a^2b^2c^2}{2}.$$ I have tried Cauchy-Schwarz inequality in E...
By C-S, Vasc's inequality and AM-GM we obtain: $$\sum_{cyc}\frac{a^5}{b^3+c}\geq\frac{(a^3+b^3+c^3)^2}{\sum\limits_{cyc}(b^3a+ac)}\geq\frac{(a^3+b^3+c^3)^2}{3+3}\geq\frac{9a^2b^2c^2}{6}=\frac{3a^2b^2c^2}{2}.$$ The Vasc's inequality is the following: $$(a^2+b^2+c^2)^2\geq3(b^3a+c^3b+a^3c).$$ Also I u...
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Homogenization of an affine variety in projective space I think I have a fundamental understanding issue. I am trying to prove that if we embed $\mathbb{A}^{n}$ into $\mathbb{P}^{n}$ by $x_{0} \neq 0$, and we have aff...
Hint: We may as well assume that $I$ and $J$ are radical (why?). Note then that $V(I)\subseteq V(J)$ is equivalent to $I\supseteq J$. Clearly then $I^\ast\supseteq J^\ast$, and so $V(I^\ast)\subseteq V(J^\ast)$.
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Inequality from IMO 2000 problem 4 question $\prod\limits_{cyc}\left(a-1+\frac{1}{b}\right)\leq 1$ $abc=1$ I know the problem is repeated but my question is somehow different. I want to know whether my proof is correc...
If $x,y,z$ are not the sides of a triangle, then the inequality is trivial because the left hand side would negative.
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Prove that inequality $27+7\left(ab+bc+ca\right)\le 8\left(\sum \sqrt{a+3b}\right)$ For the positive reals $a,b$ and $c$ so that $a+b+c=3$. Show that $$27+7\left(ab+bc+ca\right)\le 8\left(\sqrt{a+3b}+\sqrt{b+3c}+\sqrt...
You are actually very close. We can go on from your last inequality, with $x=2u, y=2v, z=2w$, we need to show $$u+v+w \ge u^2v^2+v^2w^2+ w^2u^2\tag{1}$$ for $u^2+v^2+w^2=3$. Now, the RHS of (1) is $$\frac{(u^2+v^2+w^2)^2 - (u^4+v^4+w^4)}2 = \frac{9- (u^4+v^4+w^4)}2$$ So we need to prove $$u^4+ v^4 +...
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