Hint:
We may as well assume that $I$ and $J$ are radical (why?). Note then that $V(I)\subseteq V(J)$ is equivalent to $I\supseteq J$. Clearly then $I^\ast\supseteq J^\ast$, and so $V(I^\ast)\subseteq V(J^\ast)$.
Hint:
We may as well assume that $I$ and $J$ are radical (why?). Note then that $V(I)\subseteq V(J)$ is equivalent to $I\supseteq J$. Clearly then $I^\ast\supseteq J^\ast$, and so $V(I^\ast)\subseteq V(J^\ast)$.