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FORMULAR definition in American English - Collins Dictionary
noun 1. a model or set form adjective 2. of or relating to formulas 3. formal Collins English Dictionary. www.collinsdictionary.com
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formular - Wiktionary, the free dictionary
See also: Formular, formulär, and formulář. Contents. 1 English. 1.1 Etymology; 1.2 Adjective. 1.2.1 Derived terms. 2 Catalan. 2.1 Pronunciation; 2.2 Verb. en.wiktionary.org
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German-English translation for "Formular" - Langenscheidt
Translation for 'Formular' using the free German-English dictionary by LANGENSCHEIDT -– with examples, synonyms and pronunciation. en.langenscheidt.com
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formular
formular, a. and n. (ˈfɔːmjʊlə(r)) [ad. L. type *formulār-is, f. formula. As n., a. F. formulaire. See -ar1, -ar2.] A. adj. 1. Formal, correct or regular in form.1773 Johnson in Boswell 29 Apr., A speech on the stage, let it flatter ever so extravagantly, is formular. It has always been formular to ... Oxford English Dictionary
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Formular - Brownfox
Unlike its dogmatic Modernist predecessors, Formular is a hip Swiss sans serif of the new generation. Inspired by the utilitarian 19th-century grotesques, its ... brownfox.org
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Formular stationery - Wikipedia
The term formular (often misspelled formula) is an adjective applied to envelopes, cards and aerograms, etc., produced by postal authorities or to their ... en.wikipedia.org
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Formular Column Displaying Percentages
Jul 17, 2023 — Click the overall calculation field at the bottom of the group to open a customization panel, and select the percentage ...
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FORMULAR definition - Cambridge Dictionary
to create or prepare a plan or system carefully and in detail; formulate [verb] to express an idea or opinion in carefully chosen words. dictionary.cambridge.org
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"FORMULAR": A prescribed form or method - OneLook
adjective: following or relating to a formula; formulaic Similar: formulistic, formularistic, formulational, formulatory, formalist, formal, well-formed, ... www.onelook.com
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formular, adj. & n. meanings, etymology and more | Oxford English ...
The earliest known use of the word formular is in the mid 1500s. OED's earliest evidence for formular is from 1563, in a letter by William Cecil, ... www.oed.com
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FORMULER | Home
Formuler specializes in the development, design, production, and support of digital broadcast receivers. Current models: Android OTT, 4K Android HYBRID, ... www.formuler.tv
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Formular stationery
Formular stationery require the addition of an adhesive stamp before posting. References External links Formular Postal Stationery of Luxembourg Postal stationery Philatelic terminology Envelopes wikipedia.org
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Derivative with constant in the denominator I have the formular $\frac{d(y(t)*a)}{d(t*b)}$ with a and b being constants, which can be changed to $\frac{a}{b}\frac{d(y(t))}{d(t)}$. My question is why this is possible?...
Write $w=y(t)a$ and $z=tb$. Then $$\frac{dw}{dt}=a\frac{d(y(t))}{dt}.$$ Since $t=\frac{z}{b}$, we get $$\frac{dt}{dz}=\frac{1}{b}.$$ Hence, $$\frac{d(y(t)a)}{d(tb)}=\overbrace{\frac{dw}{dz}=\frac{dw}{dt}\cdot\frac{dt}{dz}}^{\text{Chain Rule}}=a \frac{d(y(t))}{dt}\cdot\frac{1}{b}=\frac{a}{b}\cdot\fra...
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how to prove the convolution formular? let $\overset{\backsim} {g}(x)=g(-x)$; suppose $u,\phi,\psi$ always make the integral significant,$E_n$ is the n-dimensional euclidean space. Then how to prove $\int_{E_n}(u*\p...
We have \begin{align*} \int_{E_n} (u * \phi)(x)\psi(x)\, dx &= \int_{E_n} \int_{E_n} u(y)\phi(x-y)\, dy\,\psi(x)\, dx\\\ &= \int_{E_n} \int_{E_n} u(y)\phi(x-y)\psi(x)\, dx\, dy\\\ &= \int_{E_n} u(y) \int_{E_n} \overset\backsim\phi(y-x)\psi(x)\,dx\, dy\\\ &= \int_{E_n} u(y)(\overset\backsim\phi * \ps...
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what is the explicit form of this iterativ formular I am not sure, if there is an explicit form, but if there is, how do I get it? This is the formula: $$c_n=\frac{1-n \cdot c_{n-1}}{\lambda}$$ where $\lambda \in \m...
The expression for $c_n$ is $$c_n=\frac{(-1)^n n!}{\lambda^{n+1}}\left\\{S_{n}(-\lambda)+\lambda c_0-1\right\\}$$ where \begin{equation}S_n(x)=\sum_{k=0}^n\frac{x^k}{k!} \end{equation} for all $x \in \mathbb{R}$. I prove it inductively. For $n=1$ the proposed expression begets $$-\frac{1}{\lambda^2}...
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