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formular
formular, a. and n. (ˈfɔːmjʊlə(r)) [ad. L. type *formulār-is, f. formula. As n., a. F. formulaire. See -ar1, -ar2.] A. adj. 1. Formal, correct or regular in form.1773 Johnson in Boswell 29 Apr., A speech on the stage, let it flatter ever so extravagantly, is formular. It has always been formular to ...
Oxford English Dictionary
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Formular Column Displaying Percentages
Jul 17, 2023 — Click the overall calculation field at the bottom of the group to open a customization panel, and select the percentage ...
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Formular stationery
Formular stationery require the addition of an adhesive stamp before posting. References
External links
Formular Postal Stationery of Luxembourg
Postal stationery
Philatelic terminology
Envelopes
wikipedia.org
en.wikipedia.org
Derivative with constant in the denominator I have the formular $\frac{d(y(t)*a)}{d(t*b)}$ with a and b being constants, which can be changed to $\frac{a}{b}\frac{d(y(t))}{d(t)}$. My question is why this is possible?...
Write $w=y(t)a$ and $z=tb$. Then $$\frac{dw}{dt}=a\frac{d(y(t))}{dt}.$$ Since $t=\frac{z}{b}$, we get $$\frac{dt}{dz}=\frac{1}{b}.$$ Hence, $$\frac{d(y(t)a)}{d(tb)}=\overbrace{\frac{dw}{dz}=\frac{dw}{dt}\cdot\frac{dt}{dz}}^{\text{Chain Rule}}=a \frac{d(y(t))}{dt}\cdot\frac{1}{b}=\frac{a}{b}\cdot\fra...
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how to prove the convolution formular? let $\overset{\backsim} {g}(x)=g(-x)$; suppose $u,\phi,\psi$ always make the integral significant,$E_n$ is the n-dimensional euclidean space. Then how to prove $\int_{E_n}(u*\p...
We have \begin{align*} \int_{E_n} (u * \phi)(x)\psi(x)\, dx &= \int_{E_n} \int_{E_n} u(y)\phi(x-y)\, dy\,\psi(x)\, dx\\\ &= \int_{E_n} \int_{E_n} u(y)\phi(x-y)\psi(x)\, dx\, dy\\\ &= \int_{E_n} u(y) \int_{E_n} \overset\backsim\phi(y-x)\psi(x)\,dx\, dy\\\ &= \int_{E_n} u(y)(\overset\backsim\phi * \ps...
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what is the explicit form of this iterativ formular I am not sure, if there is an explicit form, but if there is, how do I get it? This is the formula: $$c_n=\frac{1-n \cdot c_{n-1}}{\lambda}$$ where $\lambda \in \m...
The expression for $c_n$ is $$c_n=\frac{(-1)^n n!}{\lambda^{n+1}}\left\\{S_{n}(-\lambda)+\lambda c_0-1\right\\}$$ where \begin{equation}S_n(x)=\sum_{k=0}^n\frac{x^k}{k!} \end{equation} for all $x \in \mathbb{R}$. I prove it inductively. For $n=1$ the proposed expression begets $$-\frac{1}{\lambda^2}...
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$\sin(z)$ in polar coordinates the following formula can be found in the literature: $\vert \sin(z) \vert^2 = \sin(x)^2 + \sinh(y)^2$, $z=x+iy;$ $x,y\in\mathbb{R}$. I am wondering if there is a similar formular in p...
$r e^{i\theta} = r \cos(\theta) + i r \sin(\theta)$, so $$|\sin(r e^{i\theta})|^2 = \sin(r \cos(\theta))^2 + \sinh(r \sin(\theta))^2$$
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Where does this formular for rotating a vector in 3D space around another 3D vector comes from? I found this formular: $\mathbf{R}_{\vec{n}}(\alpha)\vec{x}=\vec{n}(\vec{n}\cdot\vec{x})+\cos(\alpha)(\vec{n}\times\vec{x...
That is just another flavor of the Rodrigues rotation formula: < which can be found in german text books for sure. Proof: Rodrigues formula is: $$v' = \cos(\theta) v + \sin(\theta) n \times v + (1 - \cos(\theta)) n (n \cdot v)$$ which can also be written as: $$v' = n (n \cdot v) + \cos(\theta) (v - ...
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Excel FormulaR1C1格式引用 - 知乎
R1C1格式引用中,R代表行(Row),C代表列(Column),有绝对引用、相对引用以及混合引用三种用法: 相对引用相对引用指的是相对于"活动单元格"的位置,R正向下;R负向上;C正向右;C负向左。关于正负及方向非常容易…
zhuanlan.zhihu.com
中国除了葬尸湖还有哪些有实力的金属乐队?
有一些乐队和上面残死是重叠的,重叠的没有写出来):肆伍乐队,暗星乐队,利维坦,惊乐队,变态少女乐队,beyond cure,破茧而出,堕天乐队,scarlet horizon,last gasp,berserker 前卫金属/前卫金属核:猎魔人,von citizen,牢铝(同时也是数学摇滚),直惘乐队,樟脑丸,fancy formular
zhihu
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Find $\sin(\frac{x}{2})$, given $\tan(x) = 2$, with $0 < x < \frac{\pi}{2}$. Find $\sin(\frac{x}{2})$, given $\tan(x) = 2$, with $0 < x < \frac{\pi}{2}$. Which half-identity formular should I use and why?
$\tan^2 x + 1 =\sec^2 x\\\ \sec x = \sqrt 5\\\ \cos x = \frac {1}{\sqrt 5}\\\ \sin \frac{x}{2} = \sqrt {\frac {1-\cos x}{2}}$
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The result of exponential sum formula I am awakard to deal with math problem !enter image description here I am trying to understand the first condition that is (k-r)=mN I can understand when (k-r) is mN, the left ...
Your calculation, if I read it correctly, is right. However, $$e^{(j)(2\pi)(k-r)}=1,$$ since $k-r$ is an integer. It follows that the expression $1-e^{(j)(2\pi)(k-r)}$ that we get on top when summing the geometric series is equal to $0$. If $k-r$ is not of the shape $mN$, the result is $0$, since th...
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Solve recursion relation finding closed formula We have a recursion relation, that looks like: $$ S(1) = 1 $$ $$S(n) = \sum_{i=1}^{n-1} i* S(i) $$ with $$ n>1$$ Now, I have to solve this relation, finding a closed f...
$S(n) = \frac{n!}2$ for $n\ge 2$. You can prove that very easily by induction.
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Solving Boolean functions and changing to simplified form How is the truth table for $(p \lor q) \lor (p \land r)$ e same as the truth table for $p \lor q$? Using formular such as De Morgans n etc.. And can anyone tel...
**Hint:** $$ (p \lor q) \lor (p \land r) = ((p \lor q) \lor p) \land ((p \lor q) \lor r) $$ by the distributive property.
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