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extrapolate

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extrapolate
extrapolate, v. (ɛkˈstræpəleɪt, ˈɛkstrəpəleɪt) [f. extra- + -polate of interpolate v., or back-formation f. extrapolation.] † 1. trans. To remove (a passage) from written matter. (Nonce-use by analogy with interpolate v. 3.)1831 Gladstone Let. in C. Wordsworth Ann. Early Life (1891) 91 They inserted... Oxford English Dictionary
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Extrapolate as you wish: AI-powered code generation ...
May 2, 2024 — – Dr. Fei-Fei Li, Co-Director of the Stanford Human-Centered AI Institute. It's not a one-size-fits-all game. But wait, there's more! A key ...
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extrapolate
extrapolate/ɪkˈstræpəleɪt; ɪk`stræpəˌlet/ v[Tn, Tn.pr]~ sth (from sth) (fml 文)1 (mathematics 数) calculate (an unknown quantity) approximately from known values or measurements （从已知的值或量）推算出（未知的量）; 外推.2 estimate (sth unknown) from facts that are already known 由已知事实估计（未知事物）; 推断; 推知 One can extrapolate ... 牛津英汉双解词典
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Extrapolate a sum using partial sums at powers of two In an online textbook for MIT OCW 18.013a, Calculus with Applications, the author uses residue calculus to derive the well-known formula $$\sum_{n>0} n^{-2} = \fra...
This is a example of a general method. Richardson extrapolation is one example. Define a sequence $$a(n) = \sum_{k=1}^n 1/k^2$$ and the first few values of $a(2^k)$ strongly suggest that $a(n) \sim c_0 + c_1/n$. In general, there will be other terms. So our ansatz is that $$s(n) := a(n) \sim c_0 + c...
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Extrapolate data points from a series of averages Given a series of data points: $$\begin{array}{c|c|c|c|c|c|c|c|} & \text{Monday} & \text{Tuesday} & \text{Wednesday} & \text{Thursday} & \text{Friday} & \text{Saturda...
The table of averages gives $5$ linear equations in $7$ unknowns. It is unlikely that you can recover the data points from the averages. Indeed, the general solution can be expressed in terms of $x_1$ and $x_2$: \begin{align} x_3 &=-x_1-x_2+124\\\ x_4 &=x_1-22\\\ x_5 &=x_2+16\\\ x_6 &=-x_1-x_2+94\\\...
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Extrapolate from the facts mentioned below.
Shelley is likely a very supportive and loving parent, willing to do anything for her daughter. She has likely provided her daughter with the love and guidance to make her 15th birthday special and memorable.
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外推 - to extrapolate - wài tuī | Definition | ChinesePod.com
互相推诿. hù xiāng tuī wěi. 1 mutually shirking responsibilities (idiom); each blaming the other 2 passing the buck to and fro 3 each trying to unload responsibilities onto the other ...
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How to I extrapolate probability over a time period? The probability of a "success" is 16% in 5 years. What is the probability of success in 10 years? How much time do I need for the probability to reach 70%? Is the...
If the arrival of "success" is random with probability $16\%$ in a 5 year interval, then we can fit a Poisson model with rate parameter $\lambda$ to this to determine the Probability of no successes in an arbitrary number of years. Let $X_L$ be the number of successes in an interval of length $L$: $...
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How to extrapolate a reasonable price given data points? I work as a math tutor, and the kids get cards for getting work done. They then are able to exchange those cards for gift cards. The exchange policies being (10...
Using a naive polynomial approximation, I found that $f(x) = \frac{x}2 + \frac{x^2}{400} $ gives a reasonable approximation of your data points. Using this, I found that the pair (100,75) is a reasonable extrapolation for 100 cards. ![Naive Polynomial Approximation](
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Meaning of ってのも/というのも > > Idiots who run alone towards the setting sun ... The sentence seems to be lacking a verb. What is the function of and is there an implied verb ending? I read this link which matches my...
(and variants such as "", "") at the end of a sentence is fairly common in speech. Such a sentence is usually euphemistically saying "", "", etc. Likewise, if you encounter a verb-lacking sentence like "……" or "……", you can usually assume something negative is implied.
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How many of 1,2,3,4,5...11000 are invertible modulo 880? My work: I write 880 as $2^4$ x $5$ x $11$. I know that for a number to be invertible modulo 880, it must be coprime to 880. I have to count all such numbers fr...
You are looking for $\phi(880)$ where $\phi$ is Euler's totient function. Half the numbers are odd, $\frac 45$ are not divisible by $5$, and $\frac {10}{11}$ are not divisible by $11$, so the fraction coprime to $880$ is $\frac 12 \cdot \frac 45 \cdot \frac {10}{11}$
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2012 AIME II #8: Complex Problem ![Problem]( When attempting to solve this question, I multiplied the equations to extrapolate the zw. Once I did this though, I ran into some confusion. Am I allowed to use the quadra...
Yes you doing in the right way. Given $z+\frac{20i}{w}=5+i$ and $w+\frac{12i}{z}=-4+10i$ $$zw+32i-\frac{240}{zw}=-30+46i$$ $$(zw)^2+(30-14i)zw-240=0$$ Now use the quadratic formula $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ and we get Here $a=1,b=(30-14i),c=-240$ $$=\frac{-(30-14i)\pm \sqrt{(30-14i)^2-4(1)...
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Boundary of bounded connected open subset of $\mathbb{R}^n$, whose complement is also connected, is connected So I know that there are other threads available on this topic, but there seems to be proofs that miss some...
Here is an argument using homology. Suppose that $K=\partial U$ is not connected. Then there exists a pair of disjoint open subsets $A, B\subset R^n$ each of which has nonempty intersection with $K$. Without loss of generality we may assume that each component of $A$ and of $B$ has nonempty intersec...
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推断 [推斷] - to infer, to deduce, to predict, to extrapolate - tuī duàn ...
互相推诿. hù xiāng tuī wěi. 1 mutually shirking responsibilities (idiom); each blaming the other 2 passing the buck to and fro 3 each trying to unload responsibilities onto the other ...
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Can I reverse any hash algorithms to find a set of the possible orginals? If I map 1024 bits onto a 16 bit hash (just random numbers for conversation sake), I will have an average of 64 collisions per hash (assuming a...
If your hash is only 16 bits, then on average there will be $2^{1008}$ different possible preimages for any hash value. It may be that you're only using 64 of those in practice, but you can't identify those _from the hash_ alone, without using (very strong) additional information about the distribut...
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