The table of averages gives $5$ linear equations in $7$ unknowns. It is unlikely that you can recover the data points from the averages.
Indeed, the general solution can be expressed in terms of $x_1$ and $x_2$: \begin{align} x_3 &=-x_1-x_2+124\\\ x_4 &=x_1-22\\\ x_5 &=x_2+16\\\ x_6 &=-x_1-x_2+94\\\ x_7 &=x_1-1 \end{align} where I've used fractions for the averages, that is, $124/3$ instead of $41.33$.
If you have limits for the ranges of $x_1$ and $x_2$, then these equations give you limits for the ranges of the other variables.