If the arrival of "success" is random with probability $16\%$ in a 5 year interval, then we can fit a Poisson model with rate parameter $\lambda$ to this to determine the Probability of no successes in an arbitrary number of years.
Let $X_L$ be the number of successes in an interval of length $L$:
$P(X_L=n) = Poi(X_L;\lambda) = Poi(X_L;\phi L)$ where $\phi$ is the "normalized rate" (e.g., per year, second, or whatever units we have for $L$).
Then, for a given $L$, we get:
$P(X_L>0)=1-P(X_L=0) = 1-Poi(0;\phi L)=1-e^{-\phi L}$
Since we know $P(X_5=0)=0.84$ this means that $e^{-5\phi}=0.84 \rightarrow \phi=-\frac{\ln 0.84}{5}$
Thus, $P(X_{10}>0)=1-e^{\frac{\ln 0.84}{5} \times 10}=1-0.84^{\frac{10}{5}}=1-0.84^2$ Just as Tunococ derived.
This post just shows how you can derive it from a Poisson model.