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equalize
equalize, v. (ˈiːkwəlaɪz) Also 7–8 equallize, (7 egalise). [f. equal + -ize. Cf. Fr. égaliser.] I. To equal, match. † 1. trans. To be or become equal to; to come up to, match, rival; = equal v. 3. Obs.15.. Tom Thumb 136 in Hazl. E.P.P. II. 239 Sir Tom Thomb, for thy fame, None can thee equalize. 159...
Oxford English Dictionary
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Equalize
Equalize is the third album by the UK band Swami, released on 24 September 2007.
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en.wikipedia.org
equalize
equalizeequalise, / ˈi:kwəlaɪz; `ikwəlˌaɪz/ v [I, Tn](cause sth to) become equal (in size, amount, etc) （使某事物）（在大小、 数量等上）相等 Germany were winning the match until just before the end when the other team equalized, ie scored another goal to make the scores equal. 德国队眼看要赢得这场比赛, 而恰在终场前对方把比分扳平.
牛津英汉双解词典
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disequalize
disˈequalize, v. rare—0. [f. dis- 6 + equalize.] trans. To render unequal. Hence disˈequalizer, one who or that which renders unequal.1847 Lytton Lucretia i. Epil., The mechanic—poor slave of the capitalist—poor agent and victim of the arch disequaliser, Civilisation.
Oxford English Dictionary
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Equalize the three numbers You have three numbers, $x, y, z$. You are allowed the following two operations on these numbers. * Choose any two numbers and increase them by $1$. * Else choose any number and increas...
Let $x+y+z=s$ where $x>y\ge z$ or $x\ge y>z$ Now the ultimate sum should be either $3x$ or $3(x+1)$ as all the numbers will be equal and the sum will have the same parity as the initial(it increase by 2) Now since highest value i.e $x=5$ So $3x=15$ and $3(x+1)=18$ Parity of $x+y+z=11 $ is odd as $15...
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How to equalize correctly? If i have this number: $2 \sqrt{2-\sqrt{3}}$ and i want to find some $x,y$ nonzero real numbers such that $2\sqrt{2-\sqrt{3}} = \sqrt{x} + \sqrt{y}$ And for that, i do this: $(2 \sqrt{2-\...
You should assume a binomial of the form whose root you desire. In this case, you should have supposed the root is $$\sqrt x -\sqrt y$$ instead. To be specific, the problem in the above calculation is in your step ii, where you set $$-\sqrt{12}=\sqrt{xy}.$$ But this is impossible if you're dealing o...
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(CodeForces) Equalize
Feb 16, 2024Property of The Given Permutation . An array consisting of n distinct integers from 1 to ? in arbitrary order.For example, [2, 3, 1, 5, 4] is a permutation, but [1, 2, 2] is not a permutation (2 appears twice in the array), and [1, 3, 4] is also not a permutation (n = 3 but there is 4 in the array). Idea. First we can remove all the duplicate values in the given a, because each p i is ...
notes.yxy.ninja
$f(x)=3x+5$, what is $f(\frac{1-x}{x})$? How can I solve this problem? Should I equalize $x=\frac{1-x}{x}$? Or find $f(\frac{1-x}{x})=3(\frac{1-x}{x})+5$?
Since $f(x) = 3x+5$ , taking $\left(\dfrac{1-x}x\right) = y $ , we get : $$f(y) = 3y+5\implies f\left(\dfrac{1-x}x\right) = 3\left(\dfrac{1-x}x\right) +5$$ $$\color{#24f}{f\left(\dfrac{1-x}x\right) = \dfrac 3x +2}$$
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DOCX GitHub
{"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"1083cantor表.txt","path":"1083cantor表.txt","contentType":"file"},{"name":"1294全排列 ...
github.com
Equalizing of powers in power series solution method I have reached to the following equation using power series solution method $$ \sum_{i=0}^p(i+1)\,a_i\,r^{i+1}+\sum_{i=0}^pa_i\,r^i+\sum_{i=0}^p(i+2)\,a_i\,r^{i-1}=...
$$\sum_{i=0}^p(i+1)\,a_i\,r^{i+1}+\sum_{i=0}^pa_i\,r^i+\sum_{i=0}^p(i+2)\,a_i\,r^{i-1}=0$$ For each term, make the power equal to $k$ to get the required $i$. So, for the first term, $i+1=k\implies i=k-1$, for the second $i=k$ and for the third, $i-1=k\implies i=k+1$. Rewriting $$ka_{k-1}+a_k+(k+3)a...
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世卫组织呼吁国际社会在应对艾滋病毒方面实现平等
在12月1日，即2022年世界艾滋病日这一天，世界卫生组织（世卫组织）呼吁全球领导人和公民大胆承认和解决阻碍实现到2030年消除艾滋病全球目标的不平等现象。. 世卫组织正在与全球合作伙伴和社区一道，以"实现平等"为主题纪念2022年世界艾滋病日——这一 ...
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Please explain how to: maintain & equalize rv batteries
an equalizer urghhh we want to boost up over 15 so all we're going to do is take the point of something sharp like a pen and we're going to push the equalize button and activate the equalized mode and that rapid flashing light indicates that were in equalize mode and you can see the voltage is now being pushed
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Difficult category theory: kernels In a category with a zero object ($0$ = initial and terminal) and zero morphisms are unique $A \to 0 \to B$ for every $A,B$, define the kernel of a map as the equalizer of $(f,0)$ an...
What you've written is mostly correct, but I'm not very convinced by your 'uniqueness of equalizers' argument. In any case, it could be expressed more neatly. What I'd do is as follows. Let $f : A \to B$ be the kernel of $g : B \to C$. Let $c = \operatorname{coker}(f) : B \to Q$. We want to show tha...
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Oblique asymptote coincides with the function I know when the oblique asymptote exists and I also know how to find it but I've always wondered, if you equalize the remainder you will always get the point at which the ...
Say that you have a function $f(x) = p(x)/q(x)$ with oblique asymptote $\ell(x)$ and remainder $r(x)$ (i.e., $f(x) = \ell(x) + r(x)$, where $\ell(x)$ is linear and $r(x) = \tilde p(x)/q(x)$ tends to $0$ as $x$ tends to $\infty$). If there is a solution to $r(x) = 0$, call it $x_0$, then we have $$f(...
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$E(x)=\sqrt{\cos^{4}(x)+m\cdot\sin^{2}(x)}+\sqrt{\sin^{4}(x)+m\cdot\cos^{2}(x)}$ is constant for $m=?$ The values of $m$ such that $E(x)$ is constant. $$E(x)=\sqrt{\cos^{4}(x)+m\cdot\sin^{2}(x)}+\sqrt{\sin^{4}(x)+m\c...
As $E(x)$ is a constant, $E(0)=E(\pi/4)$. \begin{align*} 1+\sqrt{m}&=\sqrt{\frac{1}{4}+\frac{m}{2}}+\sqrt{\frac{1}{4}+\frac{m}{2}}\\\ 1+2\sqrt{m}+m&=1+2m\\\ 2\sqrt{m}&=m\\\ m&=0 \quad\textrm{or}\quad 4 \end{align*} When $m=0$, $E(x)=1$ for all $x$. When $m=4$, \begin{align*} E(x)&=\sqrt{\cos^{4}x+4\...
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