Artificial intelligent assistant

adjoining

answer Answers

ProphetesAI is thinking...

MindMap

Sources

1
adjoining
adjoining, ppl. a. (əˈdʒɔɪnɪŋ) [f. adjoin + -ing2.] 1. a. Lying next, contiguous, adjacent; neighbouring.1494 Fabyan vi. cc. 208 Other countrees adioynynge dyd the same. 1794 Sullivan View of Nat. I. 291 The seas, forests, and adjoining mountains. 1849 Macaulay Hist. Eng. II. 506 To step aside into ... Oxford English Dictionary
prophetes.ai 0.0 3.0 0.0
2
Tree-adjoining grammar
Tree-adjoining grammar (TAG) is a grammar formalism defined by Aravind Joshi. For these reasons, tree-adjoining grammars are often described as mildly context-sensitive. wikipedia.org
en.wikipedia.org 0.0 1.5 0.0
3
Almost adjoining NYT Crossword Clue
This crossword clue might have a different answer every time it appears on a new New York Times Puzzle, please read all the answers until you find the one that solves your clue. Today's puzzle is listed on our homepage along with all the possible crossword clue solutions. The latest puzzle is: NYT 01/04/24. When facing difficulties with puzzles ...
nytcrosswordanswers.org 0.0 0.90000004 0.0
4
What does the adjoining mean? What is the adjoin operation? The wikipedia link is pretty scant, but from eat it appears to be something along the lines as the smallest step towards the union of two sets? Are Adjunctio...
There are two kinds of adjunction. The easiest is when your field $K$ and your element $\alpha\notin K$ are both sitting inside a bigger field $\Omega$. Then $K(\alpha)$ may be defined to be the smallest subfield of $\Omega$ that contains both $K$ and $\alpha$: it’s the intersection of all subfields...
prophetes.ai 0.0 0.6 0.0
5
Parklands adjoining the Yarra River
Dogs are not permitted in parklands adjoining the river unless otherwise stated in special off-lead areas. historic bridges) Yarra Ranges National Park (hiking trails) (*) = Note: this list only includes parklands within the Warrandyte State Park that are adjoining wikipedia.org
en.wikipedia.org 0.0 0.6 0.0
6
Adjoining an element to a ring This is an exercise in Artin, > Describe the ring obtained from $\mathbb{Z}$ by adjoining an element $\alpha$ satisfying the two relations $2\alpha - 6 = 0$ and $\alpha - 10 = 0$. I h...
The idea it's simple indeed, what you're doing is considering the quotient ring obtained by $\mathbb Z[x]$ and its ideal generated by the polynomials $2x - 6$ and $x - 10$ (i.e. $(2x -6 , x - 10)$). Through some calculations it's easy to see that $$(2x - 6,x - 10) = (x - 10, 14) = (x + 4, 14)$$ an s...
prophetes.ai 0.0 0.3 0.0
7
Find the area of the adjoining figure In the adjoining figure, $ABCD$ is a trapezium in which $AB||DC$; $AB=7$ $cm$; $AD=BC=5$ $cm$ and distance between $AB$ and $DC$ is $4$ $cm$. Find the length of $DC$ and hence, fi...
$DL^2 = AD^2 - AL^2$ => $DL^2 = 9$ => $DL = 3$ the same way $MC=3$ $LM = AB = 7$ => $DC = DL + LM + MC$ => $DC = 3 + 7+ 3$ => $DC = 13$
prophetes.ai 0.0 0.3 0.0
8
Adjoining elements to a ring. I have a question in Artin's Algebra, about adjoining elements on page 339. Proposition 11.5.5 says: Let $R$ be a ring, and let $f(x)$ be a monic polynomial of positive degree $n$ with c...
Consider your ring $A = R[x]/(f)$, inside of which sits the subring $B = \\{ r + (f) : r \in R \\}$. Consider the new set $$ C = (A \setminus B) \uplus R $$ (that's a disjoint union). Turn $C$ into a ring, by defining operations as in $A$, except that when you have to add or multiply an element $d \...
prophetes.ai 0.0 0.3 0.0
9
When talking about adjectives to describe proximity, which of these words fit into a 'near' category, and which are 'far'. Miles, close, neighbouring, distant, remote, adjacent, adjoining, outlying.
Close, neighbouring, adjacent and adjoining are adjectives describing a 'near' proximity.
prophetes.ai 0.0 0.3 0.0
10
In the adjoining figure, $ABCD$ is a parallelogram In the adjoining figure, $ABCD$ is a parallelogram. If $DF=CE$ and $AG||HF$ then prove that $||gm FAGH =||gm ABCD$. !enter image description here My Attempt. $1. FD...
From $CE=DF$, we have $$[\triangle{BEC}]=[\triangle{AFD}]\tag1$$ Also we get $$\begin{align}AB&=CD\\\&=CE+ED\\\&=DF+ED\\\&=FE\end{align}$$ so $ABEF$ and $FAGH$ are parallelograms. Since $HF=GA,FE=AB$ and $\angle{HFE}=\angle{GAB}$, we get $$\triangle{HFE}\equiv \triangle{GAB}$$ from which we get $$[\...
prophetes.ai 0.0 0.3 0.0
11
Adjoining an identity to a ring I am run into the following in an Algebra text: "Let $R_0=\mathbb Z/2\mathbb Z⊕\mathbb Z/2\mathbb Z⊕\cdots$ viewed as a ring without identity, with addition and multiplication defined ...
Multiplication is not defined coordinatewise, rather $(n,r)(m,s)=(nm,rs+rm+ns)$. In particular $(1,0)(n,s)=(n,s)$. Writing $(n,r)$ as $n+r$ should help in understanding why we have defined multiplication in such a way.
prophetes.ai 0.0 0.0 0.0
12
Doubts regarding 'quadratic field can be obtained by adjoining square root' This is from Artin's _Algebra_ (2nd ed.), Proposition 15.3.3: > ![enter image description here]( ![enter image description here]( I think t...
In the first paragraph, they show that a degree-2 extension can be obtained by adjoining a root of _some_ quadratic polynomial (not necessarily a square Then in the second paragraph they show how the same extension can be obtained just by adjoining a square root (a square root of $D$).
prophetes.ai 0.0 0.0 0.0
13
Motivation for the method of adjoining roots of polynomials In Galois theory we learned the standard method of adjoining a root of an irreducible polynomial. More precisely, we saw that if $K$ is a field and $f\in K[x...
We observe that $K$ has no root of $f$, so we just let $x$ be a root (this corresponds to looking at $K[X]$). Well if $x$ needs to be a root then $f(x)$ better be $0$, so let's just quotient by $f(x)$ in order to make $f(x)=0$ (this corresponds to looking at $K[X]/(f)$).
prophetes.ai 0.0 0.0 0.0
14
Find the radius of the sector adjoining a triangle [![\[img\] \[/img\]]( We know that the area of the sector should be $\frac{40}{360}\cdot\frac{22}{7}\cdot r^2$ Any ideas on how to begin? Many Thanks:)
Let $r$ be the radius, then the area of the triangle is $$ A = \frac{1}{2}2 \pi r $$ and the area of the sector is $$ A = \frac{40}{360} \pi r^2 $$ Setting these equal gives you one equation with one unknown $$ \frac{1}{2}2 \pi r = \frac{40}{360} \pi r^2 $$ which you can solve for $r$.
prophetes.ai 0.0 0.0 0.0
15
Prove that $\mathbb Q[x]/\langle x^3+x^2-2x-1\rangle$ cannot be obtained by adjoining any cube root of rational number I am trying to find an extension of degree $3$ of $\Bbb Q$ which is not isomorphic to one of the f...
Isn't $f(X)=X^3+X^2-2X-1$ the minimum polynomial of $u=2\cos(2\pi/7)$? If so then $K=\mathbb{Q}(u)$ is a degree $3$ Galois extension of $\mathbb{Q}$. But a pure cubic field $L=\mathbb{Q}(a^{1/3})$ cannot be Galois, as its Galois closure contains all cubic roots of unity. These are quadratic over $\m...
prophetes.ai 0.0 0.0 0.0