stably

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stably
▪ I. † ˈstably, n. Obs. Also 4–5 stable. [a. AF. establie (latinized stabilia, stabilea, stablea: see G. J. Turner, Sel. Pleas of Forest, Gloss.), f. establir to station, establish. Cf. med.L. stabilitiones venationum (Domesday Book).] 1. Hunting. A besetting of a wood with men, hounds in leash, net... Oxford English Dictionary
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Stably free module
In mathematics, a stably free module is a module which is close to being free. An infinitely generated module is stably free if and only if it is free. wikipedia.org
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stably
stably/ˈsteɪblɪ; `steblɪ/ adv: in a stable manner 稳定地; 沉稳地. 牛津英汉双解词典
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Atomic Heart is almost finished and already runs stably on ...
Developer Mundfish announced on the game's official Discord that Atomic Heart is almost finished. The studio is not going to announce a release date yet,
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Stably finite ring
Namely, any nontrivial stably finite ring has IBN. Commutative rings, noetherian rings and artinian rings are stably finite. Subrings of stably finite rings and matrix rings over stably finite rings are stably finite. wikipedia.org
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Question regarding stably free module A finitely generated projective module is stably free if $P \oplus R^m \cong R^n$ for some $m,n$. Show that every stably free $R$-module is free iff every unimodular row over $R$ ...
Your definition of unimodular row is totally wrong. Rather, a unimodular row is just a row whose entries generate the unit ideal in $R$. That is, $(a_1,\dots,a_n)\in R^n$ is unimodular if there exist $b_1,\dots,b_n\in R$ such that $\sum b_ia_i=1$.
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K- theory of stably projectionless C* algebras could anyone give me an example of a stably projectionless C*-algebra with non-zero $K_0$ group?
To show that $C_0(\mathbb R^2)$ is stably projectionless, consider any map $f:\mathbb R^2\to M_n(\mathbb C)$, vanishing at infinity, with $f(x)$ a projection
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Non-trivial stably free, projective right ideals I am working on _Stably free, projective right ideals_ (1985) by J.T. Stafford. Trying to get through Theorem 1.2 on page 66 [4]. From the beginning of the paper we ar...
Since $a$ is regular, the map $r\mapsto ar$ is an isomorphism. The same applies to b too. The author isn't claiming that all such noncommuting a and b have that property, he is just saying such a pair can be found.
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CN103670416A - Method for rapidly and stably arranging equipment on ...
The invention relates to a method for arranging equipment on a fully mechanized coal mining face, in particular to a method for rapidly and stably arranging equipment on the fully mechanized coal mining face. The method comprises the following steps: arranging an equipment train; arranging a belt self-moving machine tail and a transfer smashing machine; arranging a crossheading rubber belt ...
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What does it mean: carrying the stably integrated gene Reading this study < They writing > Multiple **exogenous** and endogenous genes can be simultaneously activated by CRISPR-on > > We tested single, double and t...
According to Merriam Webster, an exogeneous gene is defined as " introduced from or produced outside the organism or system; specifically : not synthesized within the organism or system—compare endogenous". I believe they refer to the tetO::tdTomato transgene as an exogeneous, or not originating fro...
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Hemisphere surmounted by cone We have a rotationally symmetric solid, consisting of a half-ball of radius $R$, surmounted by a right circular cone of height $H$. If the centroid of the solid is in the half-ball part, ...
A cone of height $H$ and base radius $R$ has volume $\pi R^2 H/3$ and its centre of mass is at height $H/4$ above the base. The half-ball of radius $R$ has volume $2 \pi R^3/3$ and its centre of mass is $3 R/8$ below the base of the cone. So the combined solid's centre of mass is at height $$ \dfrac...
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Stably trivial vector bundles over a torus It is not difficult to see that there are non-trivial stably trivial bundles of rank $2$ for a closed surface $\Sigma$ of genus $\neq 1$ using that $T \Sigma$ is non-trivial,...
I solved the question, I'll leave the answer for reference. The answer is yes for the first question and no for the second. Consider the tangent bundle of $T^2 \times S^2$, which is trivial. $T^2 \times S^2$ contains tori of nonzero self-intersection number. Pick one such torus, say $Y$, and let $E ...
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Do I really need -dmS option in screen to run background job stably even log out? I saw many place introduce `screen` to run background job stably even log out. They use screen -dmS name According ...
You would only use `-dm` if you want to run a command in a screen session and not enter it interactively `-S` is just to give the session a usable name so you can reconnect to it again easily later If you want to use it interactively and don't want to give it a human readable name, you can omit all ...
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