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residuum

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residuum
residuum (rɪˈzɪdjuːəm) Pl. residua (rɪˈzɪdjuːə); also 8 residuums. [a. L. residuum, neut. of residuus remaining, f. residēre to remain, reside v.1] 1. That which remains; a residue. (Chiefly of immaterial things, and often with more or less direct allusion to sense 3.)1672 T. Jacombe Serm. Rom. (186... Oxford English Dictionary
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Residuum (geology)
While residuum is similar to the term regolith, it is more specific. Residuum differs from saprolite through its structure and degree of weathering. wikipedia.org
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Crider (soil)
They formed in a mantle of loess and the underlying limestone residuum." wikipedia.org
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Properties of the residuum of a t-norm Let $\Rightarrow:[0,1]^2\to[0,1]$ such that $$ x\Rightarrow y=1\text{ iff }x\leq y $$ and $$ x\Rightarrow y=y\text{ iff }x>y $$ How can I prove, that $x\Rightarrow(y\Rightarrow ...
The only way I can think of is to break into several cases based on the relative order of $x,y,z$. Not too many, though. First assume $y\le z$. Then the LHS is $x\Rightarrow 1=1$. For the RHS, $x\Rightarrow z$ is equal to either $1$ or $z$. No matter which, we have $y \le (x\Rightarrow z)$, so the R...
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De-asphalter
A de-asphalter is a unit in a crude oil refinery or bitumen upgrader that separates asphalt from the residuum fraction of crude oil or bitumen. The de-asphalter unit is usually placed after the vacuum distillation tower and receives feed from the bottom (residuum) stream. wikipedia.org
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Computing residue of $f(z)=\frac{z-\pi}{\sin^2z}$ at $z = \pi$ I know how to find residuum simple function but now I have function $$f(z)=\frac{z-\pi}{\sin^2z}$$ and I have to calculate residuum in $\pi$ (that is, $...
One may note that it is a simple pole, hence $$\text{Res}_{z=\pi}\frac{z-\pi}{\sin^2z}=\lim_{z\to\pi}\frac{(z-\pi)^2}{\sin^2z}=1$$
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Alum Bluff Group
group includes: Chipola Formation Oak Grove Sand Shoal River Formation Choctawhatchee Formation Jackson Bluff Formation The Alum Bluff Group has a residuum The residuum includes Lower to Upper Miocene and younger weathered sediments. wikipedia.org
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True of False: If $f$ is analytic at each point of a closed contour $L$, then $\int_L f(z) \mathrm{d}z = 0$ True of False: If $f$ is analytic at each point of a closed contour $L$, then $\int_L f(z) \mathrm{d}z = 0$. ...
Then the integral of this function over this contour is equal $2\pi i$ times residuum at 0 and this is certainly not zero. We just used Cauchy residuum theorem.
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Caulleryella
Cytokinesis occurs to yield a bouquet of merozoites attached at one end to a residuum. The gamonts are spheroidal. This leads to the formation of 8 sporozoites attached to a single polar residuum. wikipedia.org
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Limit of a complex function (resulting in divide by zero situations) I have the following limit which I'm attempting (and failing) to evaluate: $\lim_{x \to i} (z-i)\frac{e^{imz}}{(z^2+1)^2}$ Evaluating directly, we...
Thus the residuum results from the linear term in the numerator and is $f'(a)$.
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Alveocystis
Within each oocyst there are 8 or more free sporozoites and a large oocyst residuum. References Apicomplexa genera wikipedia.org
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Spermatobium
The sporogonia contain numerous sporoblasts or spores and a residuum. References Aconoidasida Apicomplexa genera wikipedia.org
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How to approach/solve this integral? Could somebody suggest how to approach or solve this integral: $$ \int_{0}^\infty e^{-a t}{2+t-2\sqrt{1+t}\over t^2}{\rm d\,}t, $$ where $a>0$ ? It is not a homework. I tried to us...
Here is a start. Differentiating twice with respect to $a$ gives > $$ \int_{0}^\infty e^{-a t}(2+t-2\sqrt{1+t}){\rm d\,}t.$$ Now, work out the integral and follow the technique used in this problem.
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Sivatoshella
Neither a residuum or micropyle is present in the oocyst. A sporocyst residuum present as minute refractile globules embedded in a dark matrix. wikipedia.org
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Pfeifferinella
A large oocyst residuum is present. The micropyle tends to be large. References Conoidasida Apicomplexa genera wikipedia.org
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