The only way I can think of is to break into several cases based on the relative order of $x,y,z$. Not too many, though.
First assume $y\le z$. Then the LHS is $x\Rightarrow 1=1$. For the RHS, $x\Rightarrow z$ is equal to either $1$ or $z$. No matter which, we have $y \le (x\Rightarrow z)$, so the RHS is also $1$.
Next, assume $y>z$. Then the LHS becomes $x\Rightarrow z$, and you must break things up based on how $x$ compares to $z$. I'll leave the rest to the reader.