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lurker
▪ I. lurker1 (ˈlɜːkə(r)) [f. lurk v. + -er1.] 1. One who lurks or lies concealed: freq. employed as a term of abuse in early quots. lit. and fig.a 1325 Names of Hare in Rel. Ant. I. 133 The wilde der, the lepere, The shorte der, the lerkere. 1399 Langl. Rich. Redeles iii. 57 But as sone as þey [the ...
Oxford English Dictionary
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潜水员 (@lurker233) | Twitter
The latest Tweets from 潜水员 (@lurker233): "あの頃は 何もなくて、それだって 楽しくやったよ"
twitter.com
The Lurker (film)
The Lurker is a 2019 American horror feature film written by John Lerchen and directed by Eric Liberacki. The Rotting Zombie calls Travolta a "great scene stealing actor" and "by far the best part of The Lurker."
wikipedia.org
en.wikipedia.org
Grok, long time lurker, first time poster
Dec 3, 2023 — Grok, long time lurker, first time poster Introduce Yourself.
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Lurker Rock
Lurker Rock is a rock high, located northeast of Dismal Island, Faure Islands, in Marguerite Bay, Antarctica.
wikipedia.org
en.wikipedia.org
The Lurker at the Threshold
The Lurker at the Threshold is a horror novel by American writer August Derleth, based on short fragments written by H. P. The Lurker at the Threshold was included in The Watchers Out of Time and Others, the 1974 Arkham House omnibus edition of Derleth's stories credited as
wikipedia.org
en.wikipedia.org
under-blade-lurker
† under-blade-lurker Obs. [under-2.] The subscapular muscle.1683 Snape Anat. Horse iv. xviii. (1686) 180 The second Puller or Drawer back of the shoulder is the subscapularis, the under-blade-lurker.
Oxford English Dictionary
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Louis Sarowsky
Skateboarding
Lurker Lou Sarowksy is known for skating unique and difficult spots. References
External links
Lurker Lou and the Purple Shoe
An Interview With Lurker Lou - Quartersnacks
American skateboarders
People from Dennis,
wikipedia.org
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Contour integral involving moduli in the integrand Long-time lurker, first time questioner. Here is the problem: Let $ a,b \in \mathbb{C} $, with $|b|<1$. Calculate the integral $$ \frac{1}{2\pi i}\int_{|z|=1} \fra...
The way I would do it is by using that on $|z| = 1$, $\bar{z} = \frac{1}{z}$, so you can rewrite the fraction $\frac{|z-a|^2}{|z-b|^2}$ as $\frac{(z-a)(1-z\bar{a})}{(z-b)(1-z\bar{b})}$ which is analytic, and then use the residue theorem while considering a few special cases like $a=b$, $a=0$, $b=0$,...
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The Lurker's Guide to Babylon 5
The name is derived from the term lurker, which creator J. Structure
The Lurker's Guide has five major sections, starting with "The Babylon 5 Universe".
wikipedia.org
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Debian (jessie) with XFCE, Sessions and Startup: Application Autostart Long-time lurker, first time question-asker. I am running Debian jessie with XFCE, kernel 3.16.7. In the course of setting up Conky to run at st...
Gnome's GDM (Gnome Display Manager) manages graphical display servers and handles graphical user logins. See this page on the ArchWiki for more information. (from the above link): To autorun programs: Ensure your `~/.xinitrc` or `/etc/X11/xinit/xinitrc` files source `~/.xprofile`: #!/bin/sh # Make s...
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The Evictors
Ruth is repeatedly terrorized by a mysterious slow-moving lurker when Ben is away. Near the end, Ben himself tries to stop the lurker from hurting Ruth only to end up being killed by accident when Ruth attempts to shoot the lurker only
wikipedia.org
en.wikipedia.org
What does 通して聞く mean when they are used together? long-time lurker, am hoping that I can get some help on something I came upon a tweet which has this particular sentence "..." I am perplexed by how are used togeth...
I believe this usage corresponds to the following definition of / from : > (…—— So ~ would basically be "listen to straight through, from beginning to end."
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Visualising a region involving the $1$-norm I'm a long-time lurker but first-time poster so I apologise if this post isn't formatted correctly. I'm having trouble visualising the region $\mathcal{R}$ defined as: $$\ma...
It is a square. Let inspect the unit norm ball. $$\mathcal{R}=\\{\textbf{x}\in\mathbb{R}^2:\Vert{\textbf{x}}\Vert_1\leq 1\\}$$ Let say, $\Vert{\textbf{x}}\Vert_1= 1.$ So, $$|x_1|+|x_2|=1.$$ **Case-1** When, $x_1,\ x_2 \geq 0,$ $$x_2=1-x_1.$$ **Case-2** When, $x_1 > 0,\ x_2 0,\ x_1 < 0,$ $$x_2=x_1+1....
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