Artificial intelligent assistant

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langle
▪ I. langle, n. Obs. exc. dial. (ˈlæŋg(ə)l) Forms: 4 langald, langhalde, 6 langhold, 8 langel(l, 8, 9 dial. langle. [Of obscure origin; both form and sense appear to point to an OF. *langle, *lengle:—L. lingula thong, strap, dim. of lingua tongue; but the word is app. not recorded in French. Cf. lin... Oxford English Dictionary
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Pierre de Langle
Pierre de Langle (6 March 1643, in Evreux – 12 April 1724, in Boulogne-Sur-Mer) was a French bishop and Jansenist theologian. Landrin, Un prélat gallican, Pierre de Langle, évêque de Boulogne (1644-1724), Calais, Imprimerie J. wikipedia.org
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Paul Antoine Fleuriot de Langle
Fleuriot de Langle took part in the American Revolutionary War. In April 1781, Fleuriot de Langle was given command of the 32-gun frigate Résolue. Legacy Fleuriot de Langle was posthumously promoted to Chef de Division on 24 April 1788. wikipedia.org
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Let $a$ and $b$ be elements of a group. If $|a|=m, \;|b|=n $ and $(m,n)=1$, show that $\langle a \rangle \cap \langle b \rangle = \{e\}$ > Let $a$ and $b$ be elements of a group. If $|a|=m, \;|b|=n $ and $(m,n)=1$, sh...
The problem comes in the very first equality: $$ \langle a^n\rangle \cap \langle b^m\rangle = \langle a^{\operatorname{lcm}(m, n)}\rangle $$ This is true We have that $\langle a\rangle\cap \langle b\rangle$ is a subgroup of $\langle a\rangle$, and thus has order that divides $m$.
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Charles-Alexandre de Maurville de Langle
Charles-Alexandre de Maurville de Langle was a French Navy officer. Maurville de Langle joined the Navy as a Garde-Marine on 12 November 1764. He was promoted to Lieutenant on 1 April 1778. wikipedia.org
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Fernand de Langle de Cary
Unlike generals Ruffey and Lanrezac, Langle de Cary was not relieved of his command. De Langle de Cary was retired (removed from the officer Active List) the following year. wikipedia.org
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Find all generators of $\langle a\rangle , \langle b\rangle,$ and $\langle c\rangle$ Suppose that $\langle a\rangle , \langle b\rangle,$ and $\langle c\rangle$ are cyclic groups of orders $6, 8,$ and $20,$ respectivel...
Hence, $\langle a\rangle = \\{a^0 = e, a^1, a^2 \cdots a^5\\}$, by the definition of $\langle a\rangle$, where $|\langle a \rangle| = 6$. You can apply this, then, in the same manner, to $\langle b\rangle$ and $\langle c\rangle$.
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La Proiselière-et-Langle
La Proiselière-et-Langle is a commune in the Haute-Saône department in the region of Bourgogne-Franche-Comté in eastern France. wikipedia.org
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If $\langle a \rangle \unlhd \langle a,b \rangle$ and $a,b$ have finite order, then $\langle a, b \rangle$ is finite. Let $G$ be a group and $a,b \in G$. If $\langle a \rangle \unlhd \langle a,b \rangle$ and $a,b$ hav...
Then in particular given any word in $\langle H \cup K \rangle$ we can write it as $kh$, by "moving each $k$ to the left" as we did above. Trivially, it follows that $\langle H \cup K \rangle = \langle K \rangle \langle H \rangle$.
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Is $\langle S \rangle \cup \langle T \rangle = \langle S \cup T \rangle$ and $\langle S \rangle \cap \langle T \rangle = \langle S \cap T \rangle$? Let $G$ a group, $S,T \subseteq G$ and $\langle S \rangle, \langle T ...
Then $\langle (12)\rangle \cup\langle (13)\rangle$ has three elements (And is not even a group!). But, $\langle (12), (13)\rangle = S_3$. But the intersection of $\langle (12)\rangle$ and $\langle (13)\rangle$ contains the identity.
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Langle智能电池管理系统8S 24V 80A保护板8S 24V 200A LiFePo4彩色显示器，用于过充电保护
Langle智能电池管理系统8s 24v 80a保护板8s 24v 200a Lifepo4彩色显示器，用于过充电保护 , Find Complete Details about Langle智能电池管理系统8s 24v 80a保护板8s 24v 200a Lifepo4彩色显示器，用于过充电保护,锂电池bms保护板:,过充电保护,智能bms 8s 24v 80a板8s 24v 200a Lifepo4彩色显示屏，用于过充电保护 from Supplier or Manufacturer ...
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什么是 Jahn-Teller 效应？
轨道角动量被淬灭（quenched，详见下边讨论）， \langle \psi \vert \boldsymbol{L} \vert\psi \rangle = 0\quad \langle \psi \vert \boldsymbol{L}^2 \vert \psi \rangle \neq 0 铁系原子 \rho \rangle \langle \rho {\vert} V_{s'} \vert \nu' \rangle }{E_{\nu}-E_{\rho}} \right] 此时线性项对角元 \langle \nu \vert V_{s} \vert \nu\rangle 的选律为：设 V_{s} zhihu
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什么叫强关联系统？
数学上说， 强相互作用是 H=H_0+H_I, 其中相互作用部分H_I不是一个小量，微扰展开不能收敛； 强关联是指 \langle A B\rangle\neq \langle A\rangle \langle B\rangle,观测到的物理量，（尤其是说电子的性质），并不独立。 zhihu
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为什么观测会影响双缝衍射的结果？
那么这个仪器的量子态1和量子态2可以被我们完全区分开来（例如一个偏向左侧的指针和偏向右侧的指针），所以， \langle1|2\rangle=0 很显然，上式中所显示的干涉项消失了。也就是说，只要打开仪器，记录不记录都是一样的：干涉消失。 而这个 \langle1|2\rangle=0 意味着什么呢？这意味着电子的路径与观测仪器形成了最大程度的量子纠缠。 所以说，观察者的作用就是建立路径信息与观测仪器的信息关联。关联一旦建立，就会干扰干涉，无论观测结果有没有被记录、有没有被我们看到。 zhihu
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为什么成键轨道和反键轨道同时存在？
为了讨论简单起见，我们进一步使用Huckel Molecular Orbital (HMO)方法，这样一来 \langle\phi_i|\phi_j\rangle=\delta_{ij}\\ 所以 \langle \Psi|\Psi \rangle=c^2_a+c^2_b 。 所以我们对系数 c_a 和 c_b 求能量的极值点（变分）： L=\langle\Psi|\hat{H}|\Psi\rangle-E(\langle\Psi|\Psi\rangle-1)\\ 展开就是 L=c^2_a\alpha+2c_ac_b\beta+c^2_b\alpha-E(c^2_a+c^2 zhihu
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