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expound
expound, v. (ɛkˈspaʊnd) Forms α. 4–5 expoun-en, -pown-en, 4–6 expoun(e, -pown(e (5 exponne); β. 3–6 expounde, expownd(e (5 exspound), 4– expound. pa. tense and pa. pple. 5–6 expouned, -powne(d, -pownd(e, -pound(e. [ME. expoune-n, expounde, ad. OF. espondre, espundre, ex- (3 pl. esponent, derivs. esp... Oxford English Dictionary
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the use of the word "to expound" - English Language & Usage Stack Exchange
1. Expound means to set forth, declare, state in detail (doctrines, ideas, principles; formerly, with wider application); To explain, interpret (what is difficult or obscure) (OED). The verb is not used with 'on', 'upon' or 'about'. For example, "Our author proceeds to expound his own analysis." "The doctrines expounded by St. Augustine."
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Expound vs Explain: Differences And Uses For Each One
Scientific Research. You would "explain" the methodology and results of a study to a layperson. You would "expound" on the implications and potential applications of the study to fellow researchers in the field. As you can see, the choice between "expound" and "explain" can depend on the context in which they are used.
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expound
expound/ɪkˈspaund; ɪk`spaʊnd/ v[Tn, Tn.pr]~ sth (to sb) (fml 文) explain or make sth clear by giving details 详加解释或详述某事物 expound a theory 详细解释一理论 He expounded his views on education to me at great length. 他向我详细讲述了他的教育观点. 牛津英汉双解词典
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Bush lawyer
Zealand climbing plants in the genus Rubus, especially Rubus cissoides (Australian and New Zealand usage) person not qualified in law who attempts to expound wikipedia.org
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expounitour
† exˈpounitour Obs. rare—1. [f. expoune, expound v., on the analogy of expositor.] An expounder, expositor.c 1380 Wyclif Sel. Wks. III. 202 Expounitouris on þe gospellis and pistelis. Oxford English Dictionary
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John Evans (died 1779)
This was the first work published in Welsh to expound any portion of the Bible, being fifteen years earlier than that of Peter Williams. wikipedia.org
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re-expound
re-exˈpound, v. [re- 5 a.] trans. To expound again.1867 Bushnell Mor. Uses Dark Th. 249 The topic is in the hospitals and the courts expounded and re-expounded. 1888 Centen. Confer. Missions (U.S.) II. 61 The principle [of marriage] was re-expounded by the Lord Jesus Christ. Oxford English Dictionary
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Simple topology proof **Claim:** In a metric space $(X, d)$ the set $X$ is open. **Proof:** For each point $a ∈ X$, every open ball centered at $a$ is contained in $X$. Thus $X$ is open. * * * Could someone expound...
Recall that in a metric space $(X,d)$ the open ball centred at $a \in X$ of radius $r \in \mathbb{R}, r>0$ is by definition (!) $$B_X(a,r) = \\{x \in X: d(x,a) < r \\}$$ which is a subset of $X$. It's indeed a triviality from the definition. E.g. if $X = [0,1]\subseteq \mathbb{R}$ with $d(x,y) = |x-...
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推阐 [推闡] - to elucidate, to study and expound - tuī chǎn | Definition ...
互相推诿. hù xiāng tuī wěi. 1 mutually shirking responsibilities (idiom); each blaming the other 2 passing the buck to and fro 3 each trying to unload responsibilities onto the other ...
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Show that the element $φ(a)\in G'$ has also order d! **EXERCISE:** > Consider that $Φ:G\rightarrow G'$ homomorphism and $a\in G$ which has order d. > > Show that the element $φ(a)\in G'$ has also order d. I am sorr...
To expound on user8734617's comment: We have that $a^d =e$ (where $e$ is the identity). Therefore $\phi(a)^d = \phi(a^d) = \phi(e) =e$.
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Orientable manifold with finite first homology group. I've started going through old comps and have hit a road block, the following: Let $M$ be a closed, connected, orientable $n$-manifold, with $n \geq 3$. Show if $...
If $H_{1}(M)$ is finite then by the universal coefficient theorem, $$H^1(M) \cong \hom_{\mathbb{Z}}(H_1(M), \mathbb{Z})$$ is zero (because $\mathbb{Z}$ has no nonzero elements of finite order). And by Poincaré duality (the manifold is connected, closed, and orientable), there is an isomorphism $H_{n...
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$f^2$ holomorphic polynomial on the disc, $f$ entire, then $f$ is a polynomial. I know this question will look similar to this link's question: _=_ However, I am not entirely satisfied with either answer here. The ...
By uniqueness of analytic continuation, $f^2$ is globally a polynomial. Factor $f^2$ into linear factors. Each linear factor must occur to an even power since the zeros of $f^2$ are the same as the zeros of $f$, with twice the order. So $f^2=\lambda\cdot\prod_i(z-z_i)^{2n_i}$ Define $g=f/\prod_i(z-z...
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Finding $\sin \theta$ and $\cos \theta$ while vector is given. If **v** = 2 **i** -3 **j** , then find $\sin \theta$ and $ \cos \theta$? Solution manual says: ![enter image description here]( Can someone expound on...
This is the definition of $\sin{t}$ and $\cos{t}$ that you should be thinking of: ![]( This is on the unit circle, so you want to find a vector $\mathbf{w} = (\cos{t},\sin{t}) = \cos{t}\mathbf{i} + \sin{t}\mathbf{j}$ that points in the same direction as $\mathbf{v}$ (so that it preserves the angle $...
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Connection between monads and posets? I understand this is broad, but could any elucidate and/or direct me on which structures, areas, and objects to study to get a deep understanding of the relationship between monad...
I think you are referring to the fact that a closure operator is a monad on a poset. < Note that every poset can be viewed as a category with at most one arrow between each pair of objects. Your question would be better stated as "What is the connection between monads and closure operators?"
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