To expound on user8734617's comment:
We have that $a^d =e$ (where $e$ is the identity). Therefore $\phi(a)^d = \phi(a^d) = \phi(e) =e$.
However, all this tells us is that the order of $\phi(a)$ divides $d$.
To expound on user8734617's comment:
We have that $a^d =e$ (where $e$ is the identity). Therefore $\phi(a)^d = \phi(a^d) = \phi(e) =e$.
However, all this tells us is that the order of $\phi(a)$ divides $d$.