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enclose
▪ I. † enˈclose, n. Obs. rare. [f. next; in Caxton perh. a. OF. enclos or enclose.] = enclosure. 1. The space enclosed by a boundary; the precincts.1484 Caxton Curial (1888) 16 Wythin thenclose of thy pryue hous. 2. A letter or document enclosed within another.1648 Evelyn Mem. (1857) III. 32 Since m... Oxford English Dictionary
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enclose
enclose/ɪnˈkləuz; ɪn`kloz/ v[Tn, Tn.pr]~ sth (with sth)1 (also inclose) put a wall, fence, etc round sth 用墙、 篱笆等围住某物 enclose a garden with a wall 在花园周围筑起墙 an enclosed order of monks, ie one that lives in isolation from the outside world 隐修士团.2 put sth in an envelope, letter, parcel, etc 将某物放入封套、 信件、... 牛津英汉双解词典
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Cheap Fence Ideas: 18 Frugal Ways to Enclose Your Property - Bob Vila
Jan 18, 2023A fence that keeps out nosy neighbors and possible intruders can also boost your home's curb appeal without breaking the bank. While fencing materials such as aluminum ($45 to $65 per linear ...
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$\require{enclose}\enclose{horizontalstrike}{\rm Greatest}\!$ Least prime factor of $n$ is less than square root of $n$, proof I remember reading this somewhere but I cannot locate the proof.
It is the **smallest** prime factor that is less than or equal to $\sqrt{n}$, unless $n$ is prime. One proof is as follows: Suppose $n=ab$ and $a$ is the smallest prime factor of $n$, and $n$ is not prime. Since $n$ is not prime, we have $b\ne1$. Since $a$ is the smallest prime factor of $n$, we hav...
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A circular field encloses maximal area for minimal perimeter Suppose a farmer has a certain length of fence, $P$ and wished to enclose the largest possible area. What shape area should the farmer choose? Answer is "c...
You can approach thge problem by first switching from rectangular to polygonal fields (with fixed side lengths $a$). By a compactness argument, a maximal such polygon exists. If $A,B,C,D$ are four (out of $n$) consecutive points in such a constellation, it is still easy to show that the contribution...
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PowerPoint「囲み文字」で文字を四角や丸で囲む方法 | PPDTP
PowerPointで文字を四角「 」や丸「 」で囲んだ「囲み文字(囲い文字)」を作る方法をご紹介します。文字と図形を組み合わせてデザイン性に優れた囲み文字が作れます。合わせて「囲み文字アニメーション」「囲み文字マクロ」も解説します。
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Using fission method with a series like v^5 + v^12 + v^19+... I am studying for exam FM and I know we can use the "fission" method to represent a summation like $v^5 + v^{10} + ... + v^{100}$ as $\frac{ \require{enc...
So, why not write instead $$\frac{1}{v^2}(v^7 + v^{14} + \cdots + v^{56}) = \frac{ \require{enclose}a_{\enclose{actuarial}{56}}}{v^2 \require{enclose}s _{\enclose{actuarial}{7}}}?
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为什么苹果直营店店员也会看不起顾客?
北京 \quad \enclose{horizontalstrike}{朝阳大悦城}三里屯 ,我热了把外套脱下来放进自己包里,负责排队的工作人员大声呵斥我“你把什么装包里了!”意思是我偷他们东西,问题是你天才吧有什么可偷的?破了皮的网线吗? 嘿,我记错了,是三里屯,就是这几天库克现身的那家。 zhihu
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Product of inexact differential forms is inexact Suppose we have a product manifold $M = M_1 \times M_2$. Let $\omega$ be a closed but inexact form on $M_1$ and $\eta$ a closed but inexact form on $M_2$. Then the clai...
I think the key here is de Rham's theorem, (part of) which can be pertinently paraphrased: > A closed $k$-form $\omega$ is exact if and only if $\int_c \omega = 0$ for every closed $k$-chain $c$. The fact that $$ \int_{c_1 \times c_2} \omega \wedge \eta = \int_{c_1} \omega \int_{c_2} \eta $$ is then...
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Question on Triangles In a right triangle, the length of hypotenuse is $c$. The centers of three circles of radius $c/5$ are found at its vertices. Find the radius of the fourth circle which touches the three given ci...
The midpoint of the hypotenuse is at a distance of $c/2$ from either of the endpoints of the hypotenuse. It's not hard to show that it's also at that same distance from the vertex of the right angle. Therefore a circle centered there that is just big enough to touch the two circles of radius $c/5$ c...
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Shape of curve with constant geometric parameter ratio What shapes (apart from a semi-circle) should curves of length L have when keeping their ends on X-axis, enclose an area A between it and X-axis and have a consta...
Like suggested in the comments, you should reflect in the x-axis. Then you will obtain a closed loop whose length is $\tilde{L}=2L$ and enclosed area is $\tilde{A}=2A$. Now apply the equality case of the isoperimetric theorem (< which states that $$ \tilde{L}^2/\tilde{A} = 4 \pi $$ if and only if th...
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grep not working when I enclose the directory in double quotes When I do something like this: grep "hello" /home/paul/* It works. But when I do something like this: grep "hello" "/ho...
From the bash reference manual: > Enclosing characters in double quotes (‘"’) preserves the literal value of all characters within the quotes, with the exception of ‘$’, ‘`’, ‘\’, and, when history expansion is enabled, ‘!’. So you must remove the special character `*` from your quoted string in ord...
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Finding the maximum area of a shape. You have $3.0$ m of edging to put around a flower bed. Find the maximum area you can enclose if the flower bed is an equilateral triangle. A) Find the maximum area you can enclose...
Equilateral triangle: > Side length is $3/3=1$m, area of equilateral triangle is given by $\dfrac{s^2\sqrt3}4$ so area is $\boxed{\dfrac{\sqrt3}4\approx0.433}$ Square: > Side length is $3/4=\frac 34$m, area of square is given by $s^2$ so area is $\boxed{\dfrac 9{16}\approx0.563}$ Circle: > Circumfer...
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