Artificial intelligent assistant

constat

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constat
‖ constat (ˈkɒnstæt) [L. constat it is certain, it is established, 3rd sing. pr. of constāre to stand firm: see constant.] † 1. Law. A certificate stating what appears (constat) upon record touching a matter, given by the clerk of the pipe and auditors of the Exchequer at the request of a person who... Oxford English Dictionary
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James Barbut
Les genres des insectes de Linné; constatés par divers échantillons d'insectes d'Angleterre, copiés d'après nature. London. (Dixwell). wikipedia.org
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Typesetting the mathematical expression "const." How do I write in the right way, that something is constant? I think, usually one does write `= const.`, which should be an abbreviation for the Latin `constat`. Shou...
Formally speaking, the right way to doing it would be to write something like $$\int 2x\, \mathrm{d}x = x^2 + k, \ \text{where } k \text{ is constant}$$ If you did insist on doing it that way, to me it would look weird if it was italicised: italicised letters inside equations or formulae are usually...
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Roger Baynes
Michaelis Angeli Cesi notarij constat". wikipedia.org
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inspeximus
‖ inspeximus Law. (ɪnˈspɛksɪməs) [L., = ‘we have inspected’: the first word in recital of the inspection of charters, etc.] A charter in which the grantor avouches to have inspected an earlier charter which he recites and confirms. Also attrib.[1282–3 Rolls Parlt. I. 225/1 Carta confirmationis liber... Oxford English Dictionary
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Walter Scott of Harden
Life The son of William Scott of Harden, Wat was born in 1550, when he was recognised as his father's heir by precept of clare constat, by Alexander Home wikipedia.org
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Special pleader
As an extreme instance, a learned judge in the 19th century challenged a pleading for putting the year without adding A.D., on the ground that "non constat wikipedia.org
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skeeling
ˈskeeling Orkney dial. Also 6 skilling. [prob. of Scandinavian origin.] skeeling-goose, the sheldrake.1578 [see rout n.7]. 1684 Sir R. Sibbald Scotia iii. 21 Skeeling-goose, de quo fama est, in ejus Ventriculo Grana Piperis reperiri, de quo tamen non constat. 1806 Neill Tour Ork. & Shetl. 195 Skeel-... Oxford English Dictionary
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fotmal
† ˈfotmal Obs. See also formell. [app. a use of OE. fótmǽl, foot measure (see foot n. and meal); the L. pes seems to have been used in the same sense. The reason for the name is obscure.] A weight used for lead, app. about 70 lbs., the thirtieth part of a fother or load.? a 1300 Assisa de Ponderibus... Oxford English Dictionary
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Trésor de la langue française
vol. 2 - Affinerie-Anfractuosité, XIX-987 1974 : vol. 3 - Ange-Badin, XXIV-1206 1975 : vol. 4 - Badinage-Cage, XXIV-1166 1977 : vol. 5 - Cageot-Constat wikipedia.org
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Basilica of the Nativity of the Blessed Virgin Mary, Šiluva
Pope John Paul II raised the shrine to the status of Minor Basilica via his Pontifical decree Constat Intra Fines on 6 May 1988. wikipedia.org
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Scaling in Schwartz space Suppose that $f\in \mathcal{S}(\mathbb R^n)$=(Schwartz space). > Can we find some constat $M>0$ such that $|\frac{1}{R} |x|^2 \nabla f(x/R)| \leq M$ for all $x\in \mathbb R^n$ and $M$ is in...
No. Take $y\in\mathbb{R}^n$ such that $y\ne0$ and $\nabla f(y)\ne0$, and let $x=R\,y$. If such an inequality were possible we would have $R\,|y|^2|\nabla f(y)|\le M$ for all $R>0$.
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GitHub
{"payload":{"allShortcutsEnabled":false,"fileTree":{"docs/linux/cli":{"items":[{"name":"README.md","path":"docs/linux/cli/README.md","contentType":"file"},{"name ...
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Huissier de justice
Huissiers de justice also serve as formal witnesses to events (constat d'huissier) in the manner of a notary public. wikipedia.org
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Negative curvature compact manifolds I know there is a theorem about the existence of metrics with constant negative curvature in compact orientable surfaces with genus greater than 1. My intuition of the meaning of g...
No, none. You are describing space forms, in this case the hyperbolic plane and 3-space. You might want to look at Cheeger and Ebin, Comparison Theorems in Riemannian Geometry. Right, Theorem 1.37 on page 41, simply connected manifolds of the same dimension and constant (sectional) curvature $K$ are...
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