condense

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condense
▪ I. † condense, a. Obs. [ad. L. condensus, f. con- + densus thick, dense.] Dense, condensed.1610 W. Folkingham Art of Survey i. viii. 16 Distinguishing between open and rare soyles, and such as are condense and close. 1652 Earl of Monmouth tr. Bentivoglio's Hist. Relat. 2 Tenacious and condence Mat... Oxford English Dictionary
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Condense Multiple Pages and Multiple Columns down to 2 ...
I converted the File to Google Sheets so its easy and safe to share. Google Sheets Link: https://docs.google.com/spreadsheets/d ... www.reddit.com
www.reddit.com 0.0 1.5 0.0
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condense
condense/kənˈdens; kən`dɛns/ v1 [I, Ipr, Tn, Tn.pr]~ (sth) (into/to sth)(a) (cause sth to) become thicker or more concentrated (使某物)变稠或变浓; 浓缩 Soup condenses when boiled, ie by losing most of the water. 汤煮过後就浓了(失去大量的水分). condensed milk, soup, etc 炼乳、 浓缩汤等.(b) (cause sth to) change from gas or vapour ... 牛津英汉双解词典
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Is there a way to condense ../.. parts of a path out programmatically? Say for example I have these types of paths to files in a script: /path/to/some/file/../../file1.txt Is there a command I can ...
Ah, asked too quickly. On Linux, the answer is to use `readlink` with the `-m` switch: $ readlink -m /home/saml/web/../web_login_form_examples/basic-php-parsing.zip /home/saml/web_login_form_examples/basic-php-parsing.zip _readlink man page_ -m, --canonicalize-missing canonicalize by following every...
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Formula to Condense 65000 to 255 I'm working on a problem for a Python program, and I'm stuck on figuring out a solution to this math problem: I have a robot that records the "brightness" of the light through a senso...
$\times \frac{255}{65000}$ converts it to a value in 0-255 range. You can use floor or Ceil functions to make it a whole number (approximates) How we found it: I'm denoting value in $0-65000$ scale as $d$, and in $0-255$ scale in $r$. $65000\equiv 255, d\equiv r\implies 255\times d=65000\times r\imp...
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What's the procedure to condense several states into one in Markov chain? I am wondering the validity and the procedure to condense/group several states into one in markov chain, namely, if it is possible, how to tran...
To generalize slightly the result mentioned by mjqxxxx, assume that one groups the original states $S_i$ into classes $C_a$. Hence the collection of classes $(C_a)$ is a partition of the state space and each class can be reduced to one state, or not. Then a sufficient condition for the resulting pro...
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删除字符串中的空格(CONDENSE text [NO-GAPS]) | 摆渡SAP - BaiduSAP
可以使用CONDENSE text [NO-GAPS]. 删除字符串中的空格。 测试代码 [crayon-65af9fc7b4282754565140/] 运行结果: 以上。 www.baidusap.com
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css有没有样式级合并工具?
比如 cssnano / csso / CSS Shrink / css-condense 等等,而且基本都有 postcss 的插件。 以 cssnano 为例: 运行: 输出: 这里有不同的压缩工具的 benchmark: ,可以参考后自行选择。 zhihu
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Condensing of $f(x)=\sec(\frac{\pi}{4}x)$ The function $f(x)=\sec(\frac{\pi}{4}x)$ is undefined every time $\cos(\frac{\pi}{4}x)$is equal to $0$. Therefore, I set cosine equal to zero, and the solutions I got were: ...
To rigorously show that condensation, you need to show that $\\{8k+2\\}\cup\\{8k+6\\} =\\{4k+2\\} $. Here's how I would do that seemingly obvious proof: If $n = 8k+2$, then $n = 4(2k)+2$, so $n \in \\{4k+2\\} $, so $\\{8k+2\\} \subset \\{4k+2\\} $. Similarly, if $n = 8k+6$, then $n = 4(2k)+4+2 = 4(2...
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Multi Valued Model Suppose we have a set of observations $\\{(x_1,y_1),...,(x_n,y_n)\\}$ and a function $f$ that provides an optimal (in some sense) prediction of an output given an input. Also suppose that for some $...
Read about Least Square Fitting. I think that this is what you need. To sum it up briefly, I'd say the you should consider which type of function you expect the approximation would be (linear, polinomial, etc.) and then, using LSF, you should approximate this function with the observations you have....
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Does $\nabla \phi = \nabla\times A$ have non-trivial solutions As stated in the title. Is there a non-trivial solution for $n=\nabla \phi$ and $n=\nabla \times A$. With the information that $|n|=1$ \begin{eqnarray} \n...
Since the given conditions imply that $n$ is both divergence-free and curl-free, you are looking for a harmonic vector field; so in particular $\Delta n = \nabla \cdot \nabla n = 0$ as you deduced. The additional condition $|n|^2 = 1$ is now very powerful: the product rule gives $$\Delta |n|^2 = 2|\...
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Solving $A_{n+1}=3A_n+2^n$ Let's say I want to find a formula for the following expression given $n$ number of threes $$\ldots(3(3(3(3(3(3+1)+2)+4)+8)+16)+\ldots$$ If $A_0=1$, then $$A_{n+1}=3A_n+2^n$$ Plugging in val...
One way to see the correct answer is to use that: $$x^n-y^n=(x-y)\left(x^{n-1}+x^{n-2}y+\cdots+xy^{n-2}+y^{n-1}\right)$$ Putting in $x=3,y=2$ you get that: $$3^n-2^n = 3^{n-1}+3^{n-2}\cdot2+\cdots+3\cdot 2^{n-2}+2^{n-1}$$ Now add $3^n$ to both sides, and you get: $$2\cdot 3^n -2^n = 3^{n}+3^{n-1}+3^...
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Prove that $\exp(A+B)=\exp(A)\exp(B)$ iff $[A,B] = 0$ I have searched throughout the forum and online as well, and I got that with condition of $[A,B]=0$, $e^{(A+B)t}=e^{At}e^{Bt}$. Now the question is, to show for a...
To show $e^{(A+B)t} = e^{At}e^{Bt}$ for all $t$ $\implies [A,B] = 0$ compare the coefficient of $t^2$ in the power-series expansion of both sides of the equation. We have $$e^{(A+B)t} = 1+ (A+B)t + \color{red}{\frac{(A+B)^2}{2!} t^2} + \ldots$$ and $$e^{At}e^{Bt} = \left(1+At + \frac{A^2}{2!}t^2+\ld...
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