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cond

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COND definition in American English - Collins Dictionary
Definition of 'cond' 1. condenser. 2. condition; conditional . www.collinsdictionary.com
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COND Definition & Meaning - Merriam-Webster
What does the abbreviation COND stand for? Meaning: condition. www.merriam-webster.com
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cond - Wiktionary, the free dictionary
See also: cond. Contents. 1 English. 1.1 Pronunciation; 1.2 Etymology 1. 1.2.1 Adjective. 1.3 Etymology 2. 1.3.1 Verb. 1.3.1.1 Derived terms. en.wiktionary.org
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cond
cond, cund, v. ? Obs. (kʌnd, kɒnd) [app. from the earlier condie, condue: perh. the final vowel was sunk in that of the inflexion, e.g. in past tense, condyde, condude. See also con v.2] † 1. trans. To conduct. Obs.c 1400 Beryn 3980 He woll have..a saff condit enselid. Ibid. 3995 He chargit Barons t... Oxford English Dictionary
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COND. Definition & Meaning - Dictionary.com
abbreviation · condenser. · condition; conditional. · conductivity. · conductor. Did You Know? Tuxedo was given its name after gaining popularity among diners ... www.dictionary.com
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cond-> - Community-Powered Clojure Documentation and Examples
Takes an expression and a set of test/form pairs. Threads expr (via ->) through each form for which the corresponding test expression is true. clojuredocs.org
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Condition number properties Assuming $A$ is invertible, I know if $A^{-1} = A^T$, then $cond(A)=1$. Is it true the other way around, as in If $cond(A)=1$, $A^{-1}=A^T$. Also, does $cond(A^{-1})$ always equal $con...
.$$ Then you can see that the condition number of $A$ is in fact $$cond(A)=\frac{|\lambda_1|}{|\lambda_n|}.$$ Next, you are going to use the fact that Finally, you can obtain the relation immediately: $$cond(A)=cond(A^{-1}).$$ Now if $cond(A)=1$, this means all eigenvalues of $A^TA$ equals $1$ because
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cond - Word Root - Membean
The word part "cond" is a root that means "hide, put away". membean.com
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3.12 Conditionals: if, cond, and, and or - Racket Documentation
Evaluates test-expr. If it produces any value other than #f, then then-expr is evaluated, and its results are the result for the if form. docs.racket-lang.org
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cond - Condition number for inversion - MATLAB - MathWorks
C = cond( A ) returns the 2-norm condition number for inversion, equal to the ratio of the largest singular value of A to the smallest. www.mathworks.com
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cond | cund, v. meanings, etymology and more | Oxford English ...
The earliest known use of the verb cond is in the Middle English period (1150—1500). OED's earliest evidence for cond is from around 1460, ... www.oed.com
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COND - Definition by AcronymFinder
Rank Abbr. Meaning. COND · Conductivity · COND · Conditioner · COND · Conductor · COND · Condition · COND · Condominium (postcode use, Puerto Rico) · COND ... www.acronymfinder.com
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$\text{cond}(A)\gt \text{cond}(A+B)$ for $AA^T=I$ Let $A$ a matrix such that $AA^T=I$. Is there a matrix $B$ such that $$\text{cond}(A)\gt \text{cond}(A+B)$$ If so give numerical exmples for this, otherwise prove th...
Assuming you're using the spectral norm, the condition number of $A$ is $1$. But there is no matrix with condition number less than $1$, because $$1 = \|I\| = \|M M^{-1}\| \le \|M \| \|M^{-1}\|$$ for all invertible matrices $M$.
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Singularity of a matix If $A$ is any $n\times n$ non-singular matrix, then $\mathrm{cond}(A) = \mathrm{cond}(A^{-1})$? True or False? I'm not sure how to answer this question.
Generally, we define $\mathrm{cond}(A)$ as $$\mathrm{cond}(A):=\vert\vert A\vert\vert\cdot \vert\vert A^{-1}\vert\vert.$$ So we do have $$\mathrm{cond }(A)=\vert\vert A\vert\vert\cdot \vert\vert A^{-1}\vert\vert=\vert\vert A^{—1}\vert\vert\cdot \vert\vert A\vert\vert=\mathrm{cond}(A^{-1})
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Is the condition number of a 2x2 block symmetric matrix greater than the condition number of its upper left hand block? Is there any known relation between _cond(M)_ and _cond(Q)_ when $$M=\begin{bmatrix}Q&A^T\\\A&0\...
We give an example in which $\operatorname{cond}(M)>\operatorname{cond}(Q)$ and an example in which $\operatorname{cond}(M)<\operatorname{cond}(Q)$, showing }(M)$, and for $a=0.1$ we get $\operatorname{cond}(Q)=10>\operatorname{cond}(M)$.
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