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alternately
alternately, adv. (ælˈtɜːnətlɪ, ɒl-) [f. alternate a. + -ly2.] 1. In alternate order; one after the other by turns, by alternation, time about.1552 Huloet, Alternatelye, or by turne. Subalternatim. 1646 Sir T. Browne Pseud. Ep. 96 Parallels or like relations alternately releeve each other. 1661 Gran...
Oxford English Dictionary
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Alternately Deep
Alternately Deep is the fifth studio album of original material by Roots Manuva. It was released on 13 March 2006 on the Big Dada label.
wikipedia.org
en.wikipedia.org
Two players shooting a target alternately > Two players **A** and **B** shoot a target alternately, until somebody hits it and wins the game. Player **A** takes the first shot. Each time they take a shot, their probab...
yes, it is correct. Alternatively, you can condition on the first outcome. If $A$ doesn't win in the first outcome, the first two trials must be failure and then it is a renewal process. $$\mathbb{P}=p + (1-p)(1-q)\mathbb{P}$$ $$(1-(1-p)(1-q))\mathbb{P}=p$$ $$\mathbb{P}=\frac{p}{1-(1-p)(1-q)}$$
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There are $5$ boys and $5$ girls. Find the ways in which boy and girl can sit alternately. > There are $5$ boys and $5$ girls. Find the ways in which boy and girl can sit alternately. I think it is $$5!×\binom65\tim...
It isn't 6 choose 5. In order to actually sit alternatively, there are only two such ways; either GB GB GB GB GB or BG BG BG BG BG. Thus, it is $2(5!)^2$.
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Doubt with probability of men and women sitting at a table alternately I just have a question regarding this existing question. > Probability of men and women sitting at a table alternately As specified there, > T...
Re your query about the famous $(n-1)!$ formula, I have a few points to make: * Here we want the **probability** , so it doesn't really matter whether we take the seats to be unnumbered (which we normally do unless it is explicitly stated otherwise) or take them as numbered. * Taking them as numbere...
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Number of ways in which boys and girls sit alternately if six boys and six girls sit randomly? > Six boys and six girls sit in a row randomly. What is the total number of ways in which the boys and the girls sit alter...
You are implicitly assuming that there are 13 seats for $6+6=12$ people. It is likely that the original question is making the implicit assumption that there are only 12 seats. In this latter case, when a boy sits first, there $6! \cdot 6!$ ways to sit the others. Multiply this by 2 to cover the cas...
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1115. Print FooBar Alternately - GitHub Pages
1115. Print FooBar Alternately. The same instance of FooBar will be passed to two different threads. Thread A will call foo () while thread B will call bar (). Modify the given program to output "foobar" n n times. Input: n = 1 Output: "foobar" Explanation: There are two threads being fired asynchronously. One of them calls foo (), while the ...
techlarry.github.io
Probability with two random variables Suppose two basketball players throw alternately to a basket (infinity times). Player A has probability of 0.7 to score, player B has probability of 0.4 to score. Player A is star...
The chance that both score at very first attempt = 0.7*0.4 at second attempt = (0*3*0.6)*(0.7*0.4) (Both have to fail their first attemts and succeed in second attempt) at nth attempt is (0.3*0.6)^n *(0.7*0.4) (Both have to fail there n attempts and suceed at n+1 th attempt) The combined probabillit...
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Name already in use - GitHub
Leetcode Solution C/C++/Golang Version（leetocde 刷题解答，C、C++、Golang 版本 ） - leetcode/print-foobar-alternately.cpp at master · smilelc3/leetcode
github.com
我爱你，现在去死吧 I Love You, Now Die: The Commonwealth Vs. Michelle Carter
This HBO special showcases the prosecution's point of view and alternately the defense's. Which side do you fall on?
豆瓣
movie.douban.com
Problems regarding probability A fair die is alternately thrown by two persons . The first one wins if one dot appears and the second one wins if 2-dots or 3-dots appear. The first one starts throwing the die. What is...
**HINT** Denote by $W$ (or $L$) the event that the first one wins (or loses). $W$ consists of some possibilities: * in one rolls is $1/6$ * in 3 rolls is $5/6$ for rolling not 1, $4/6$ for the second rolling not 2 nor 3, and $1/6$ for rolling 1 on the 3rd roll * all subsequent ones just add extra fa...
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Players $A$ and $B$ alternately toss a biased coin,with $A$ going first.$A$ wins if $A$ tosses a tail before $B$ tosses a head;otherwise $B$ wins. Players $A$ and $B$ alternately toss a biased coin,with $A$ going firs...
$A$ wins on the first toss if $T$, probability $(1-p)$ $B$ wins on the second toss if $HH$, with probability $p^2$ If neither wins in two tosses, we are back to the start. Thus for both to have equal chances, $(1-p) = p^2$ Proceed.... > $0.5(\sqrt5 - 1)$
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A formula for a sequence which has three odds and then three evens, alternately We know that triangular numbers are 1, 3, 6, 10, 15, 21, 28, 36... where we have alternate two odd and two even numbers. This sequence ha...
The sequence $$n \mapsto 4n^6+n^5+6n^3+4n \pmod 7$$ for $n \geq 1$ gives $$1,1,1,0,0,0,1,1,1,0,0,0,\ldots.$$
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Time and Work in Unitary Method Let us suppose, A and B can do a given work in 12 and 18 days respectively. They work alternately for equal period of time. And A started the work. Now, what is the time taken by A and ...
$A$ completes $\frac1{12}$ part of the work in $1$ day $B$ completes $\frac1{18}$ part in $1$ day So, in consecutive $2$ days, $A,B$ will complete $\displaystyle\frac1{12}+\frac1{18}=\frac5{36}$ part of the whole work Now, $\left\lfloor \frac{36}5\right \rfloor=7$ So, in $2\cdot7=14$ days, they will...
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