Probability with two random variables Suppose two basketball players throw alternately to a basket (infinity times). Player A has probability of 0.7 to score, player B has probability of 0.4 to score. Player A is starting. What is the probability that the 2 first scores were together?

The chance that both score at very first attempt = 0.7*0.4

at second attempt = (0*3*0.6)*(0.7*0.4) (Both have to fail their first attemts and succeed in second attempt)

at nth attempt is (0.3*0.6)^n *(0.7*0.4) (Both have to fail there n attempts and suceed at n+1 th attempt)

The combined probabillity hence is 0.28 [1+0.18 + 0.18^2...] ~ 0.341