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abut

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abut
abut, v. (əˈbʌt) [appears to represent two Fr. vbs. of cognate origin; OFr. abouter ‘toucher par un bout,’ abouter à, sur, to border on (countries, estates), mod.Fr. abouter, techn. to join two things end to end, f. à to + bout end; and OFr. abuter, ‘toucher au but,’ f. à to + but end, mod.Fr. abute... Oxford English Dictionary
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Abut Head
Abut Head is a forested headland on the West Coast of New Zealand's South Island. wikipedia.org
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abut
abut/əˈbʌt; ə`bʌt/ v(-tt-) [Ipr]~ on/against sth (of land or a building) have a common boundary or side with sth; adjoin sth （指土地或建筑物）邻接或毗连某物, 与某物接界 His land abuts on the motorway. 他的土地和高速公路毗连. Their house abuts against ours. 他们的房子紧挨著我们的房子. 牛津英汉双解词典
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7 things you didn't know about the start of Spring - Beem
The first day of spring 2023 officially arrives on March 20 with the spring equinox. Beem logo Black.
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aboutie
aboutie obs. form of abut v. Oxford English Dictionary
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Polynomial subspace Wondering abut this set : $E=(p(X) \ \in \mathbb{R}[X]; Xp(X)+p'(X)=0)$, is it a subspace of $\mathbb{R}[X] $? I definitely think it is because it only includes the zero polynomial but how could w...
If you already see that the set only includes the zero polynomial, then all you need to do is, as always, prove that if $u,v\in E$, then so is $\lambda u +v \in E$. There's nothing special that requires you to change the definition you're using - however, if $u,v\in E$ and $E$ contains only the zero...
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Behaviour of untagged traffic on TRUNK and ACCESS VLAN ports I have a situation where I have a switch with 2 vlans, that needs to connect to an upstream router -- which does not and will not know abut my VLANS (this i...
As Adam stated, generally in a well designed network, you should not be receiving untagged frames on a trunk port. Based on your description, you only want and expect to send and receive VLAN 24 on the uplink port. Thus, configure the port as an access port in VLAN 24: interface gig0/1 switchport ac...
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ABOUT | reallylikefilms
LIVING ROOM THEATER. Charlotte Gainsbourg - Jane par Charlotte (1st Feature Documentary Film) / France | Photo ©️Manabu Matsunaga. Lola Quivoron - Rodéo (1st Feature Film) | France / Photo: ©️Rie Odawara. Sheng Qiu - Suburban Birds (1st Feature Film) | China.
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瓦塔罗阿河
瓦塔罗阿河是一条位于纽西兰南岛西岸大区南部的河流，它的源头位于南阿尔卑斯山脉，蜿蜒流向西及西北方，途经瓦塔罗阿镇东侧，在Abut Head的正南注入塔斯曼海。伯斯河是它众多支流之一，而瓦塔罗阿镇与Te Taho农业小区一段的6号国道横跨其上。 wikipedia.org
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Structure separating the left atrium from the ascending aorta? With reference to the (adult) anatomy of the human heart: The left atrium (LA) and the proximal part of the ascending aorta (Ao) abut one another, as sho...
There isn't any particular structure there: you have the wall of the aorta/adventitia, and if you have an explanted heart there is a space and then the auricle of the left atrium on one side and the right atrium on the other. These would all be contained within the pericardium. Where the aorta is mo...
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Probability of a $\max$ number of an array of Uniform rv's being higher than $x$ Recently I faced this question > Let $U_1, U_2, U_3$ all come from a uniform$(0,1)$ distribution. Let $M = \max(U_1, U_2, U_3)$. Estima...
I assume that the $U_i$'s are independent. 1. Step 1: Make sure that you understand the following equivalence (if and only if statement) $$\max{\\{U_1,U_2,U_3\\}}\le 0.75\iff U_1\le 0.75,\;U_2\le 0.75,\;U_3\le 0.75$$ (the LHS implies the RHS and vice versa, can you see this?). This implies that $$\P...
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if X not finite then O is not a $\sigma$ - algebra let O (family of sets) consist of those sets which are either finite or have a finite complement. then O is an algebra. I did this part! my question now is: if X (...
_Hint:_ $X$ contains a countable subset with an infinite complement.
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Roots of cubic polynomial lying inside the circle Show that all roots of $a+bz+cz^2+z^3=0$ lie inside the circle $|z|=max{\\{1,|a|+|b|+|c| \\}}$ Now this problem is given in Beardon's Algebra and Geometry third chapt...
Suppose $a + bz + cz^2 + z^3 = 0$ and $|z| > \max\\{1,|a|+|b|+|c|\\}$. Use the triangle inequality to show that $$ |z^3| = |a + bz + cz^2| < (|a|+|b|+|c|)|z^2|, $$ which contradicts the assumption on the size of $|z|$.
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编辑以下句子以确保其语法正确。 "I don't know alot abut quantum physics"
I don't know a lot about quantum physics.
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Positive Definiteness problem Consider the positive definite matrix $B \succ 0$ and the matrix ( not necessarily square) $A$. what can we say abut the positive definiteness of: $$ A^\prime B A$$ My hunch is that this ...
You are right, but there is an easier way to see it. Why not denote $Ax$ as $y$ so you don't know $y$ equals 0 or not, but you can always have $y'Ay\geq 0$.
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