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trangle
trangle Heraldry. (ˈtræŋg(ə)l) [a. obs. F. trangle (Cotgr. 1611), var. of tringle: see tringle.] A diminutive of the fess; a bar or barrulet.1725 Coats Heraldry, Trangle is the Diminutive of a Fesse, by us commonly call'd a Bar. 1894 Parker Gloss. Her., Trangles,..used by French heralds for bars and...
Oxford English Dictionary
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Guoping Feng
American Academy of Arts and Sciences (2019)
Elected to the National Academy of Medicine (2023)
Selected publications
Barak B, Zhang Z, Liu Y, Nir A, Trangle
wikipedia.org
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tringle
▪ I. tringle (ˈtrɪŋg(ə)l) [a. F. tringle (16th c.), in Cotgr. tringle, trangle, ‘a Curtaine-rod; and more generally, a peece of round yron, or wire,..vsed for [various purposes]; also, a flat sticke, or lath-like peece of wood’. In OF. tingle beam (1328 in Godef.): cf. mod.Du. tengel flat lath. Hatz...
Oxford English Dictionary
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Aloe djiboutiensis
The inflorescences have flowers that are orange on the bottom with trangle white streaks on the top half with the non streaked part being orange.
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please help with a mathematical recreational problem I want to compute the area of a right trangle with base 2 and 3, but I want to test the truth of integration of the polar coordinate, so i decide to use this integr...
Corrected: The area element doesn't have the $r^2$ in it, so the integral should be $\int_{0}^{\arctan \frac{3}{2}} \int_0^{\frac{2}{\cos \theta}} r\;dr\;d\theta$. Alpha says this is $3$.
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Madeleine Vernet
Madeleine Vernet distributed a clandestine brochure and two numbers of Les Voix qu’on étrangle, a pacifist sheet.
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Geometry/ Similar Triangles Problem Consider the trangle shown below with vertices _A_ , _B_ , _C_ where point _D_ lies on the side _AB_ , point _E_ lies on the side _BC_ and point _F_ lies on the side _AC_ and the th...
Because the height from $G$ to $\overline{AC}$ is common to both triangles, $$\frac{Area(\triangle CGF)}{Area(\triangle AGF)}=\frac{CF}{AF}.$$ Likewise, since the height from $B$ to $\overline{AC}$ is common to both triangles, $$\frac{Area(\triangle CBF)}{Area(\triangle ABF)}=\frac{CF}{AF}.$$ Now, $...
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Pavlos Argyriadis
Une mère qui, poussée par la misère étrangle ses enfants. Plaidorie.
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Centroids and Position vectors I'm currently struggling how to visualise this question. I.e where the vectors fall along the plane and how they are connected. If possible, a diagram would be great. > Let K, L, M, N ...
Ok, I'll do your homework. First: $$c ={1\over 3}(k+l+m)$$ $\vec{CA} = {4\over 7}\vec{CN}$ so $7a-7c =4n-4c$ and thus $$7a =3c+4n \Longrightarrow a= {1\over 7}(k+l+m+4n)$$ so finally we have: \begin{eqnarray}\vec{AL} + \vec{AM} + 4\vec{AN} &=& l+m+4n-6a \\\&=& {1\over 7}(7l+7m+28n-6k-6l-6m-24n)\\\ &...
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Future Thought Productions
Productions
Crime Time
Bizarre Love Trangle
Feliz Navidad
External links
Future Thought Productions - official site
Future Thought Productions at the
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Intro to Probability Question I'm stucked in two problems: 2. Suppose that a 1-meter glass rod falls onto the floor and is broken into two pieces. Assume that the breaking point is uniform between 0 and 1 meter. Wh...
Suppose $Z$ is the distance between the breaking point and one end point of your rod. Then Z~U(0,1) So P(The longer piece has length at least 0.6 meter)= $P(Z>0.6$ or $Z0.6)+P(Z<0.4)=(1-0.6)+(0.4)=0.8$, that's the answer of you question. Notice that you cannot use two dimension plot to help you solv...
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如何看待2016年6月8日日本提交「nihonium」作为 113 号元素名称?
美国东部时间11月30日,北京时间12月1日,国际纯粹与应用化学联合会(IUPAC)在美国北卡研究三角园(Research Trangle Park)正式宣布,确认新发现的四个元素分别被命名为 113号: Nihonium (Nh) (命名来自“日本”的罗马拼写,由日本理化学研究所命名,为亚洲首例)
zhihu
www.zhihu.com
Moly/GraphicsDevice.hpp at master · XR-stb/Moly · GitHub
Moly is tiny Graphics Engine that used by Easyx And Modern CPP,you can use it to Draw Trangle,Rectangle,Circle... - Moly/GraphicsDevice.hpp at master · XR-stb/Moly
github.com
The sum of the lengths of the hypotenuse and another side of a right angled triangle is given. The sum of the lengths of the hypotenuse and another side of a right angled triangle is given.The area of the triangle wil...
.$$ So, since we know that the maximum of $f(a)$ is $f(k/3)$, it follows that the maximum of the area of the trangle is attained when $a=k/3$.
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why exist $a_{i},a_{j},a_{k}(1\le i<j<k\le 4)$ are side lengths of a triangle,if $2(a^4_{1}+a^4_{2}+a^4_{3}+a^4_{4})<33a_{1}a_{2}a_{3}a_{4}$ Assmue that postive real numbers $a_{1},a_{2},a_{3},a_{4}$ such $$2(a^4_{1}+...
Let $a_4\geq a_3\geq a_2\geq a_1$ and $a_4=a$, $a_3=b$, $a_2=c$, $a_1=d$ and $c=xd$. Hence, $x\geq1$. Let $a\geq b+c$, $b\geq c+d$ and $f(a)=2(a^4+b^4+c^4+d^4)-33abcd$. Hence, $f'(a)=8a^3-33bcd\geq8(b+c)^3-33bcd>0$, which says that $$f(a)\geq f(b+c)=2(b+c)^4+2b^4+2c^4+2d^4-33(b+c)bcd$$ Let $g(b)=2(b...
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