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single-valued

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SINGLE-VALUED Definition & Meaning - Merriam-Webster
adjective. sin·gle-val·ued ˌsiŋ-gəl-ˈval-(ˌ)yüd. : having one and only one value of the range associated with each value of the domain . www.merriam-webster.com
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Single-Valued Function -- from Wolfram MathWorld
A single-valued function is function that, for each point in the domain, has a unique value in the range. It is therefore one-to-one or many-to-one. mathworld.wolfram.com
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What is the definition of a single valued function
It means that every element maps to exactly one value. Because in complex analysis you can sometimes deal with things like n √ x , which has n solutions if x ... math.stackexchange.com
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single-valued
single-valued, a. Math. [single a.] Having a unique value for each value of its argument(s); that maps to one and only one point, number, etc. Hence single-valuedness, the property of being single-valued.1879 Maxwell Electr. & Magn. (1881) II. 252 The potential of the magnetic system is single value... Oxford English Dictionary
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Single or Multi-valued Complex Functions : r/askmath - Reddit
If a function can be defined by an algebraic expression (polynomial, rational function, power series, etc), it's bound to be single-valued. www.reddit.com
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[PDF] Complex functions, single and multivalued.
Single-valued functions have one value per z, while multivalued functions have two or more distinct values for each z. Examples include √z and logz. www.wtamu.edu
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Borel Measures: Single-Valued Given the complex plane $\mathbb{C}$. Consider the Dirac measure: $$\mu_\lambda(A):=\chi_A(\lambda)$$ Then it attains only zero and one: $$\mu_\lambda(A)=0,1$$ Are there any other such...
Same proof, less technical. Suppose $\mu$ is a measure taking exactly values $0,1$. We claim $\mu$ is a dirac measure. Let $U$ be the union of all open sets of measure zero. Since $\mathbb C$ is 2nd countable, $U$ is the union of coutably many open sets of measure zero, so $\mu(U) = 0$. Let $F$ be t...
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single-valued - Wiktionary, the free dictionary
Adjective. single-valued (not comparable) (mathematics) Of a function, associating a unique value of its range with each value of its domain. en.wiktionary.org
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SINGLE-VALUED Definition & Meaning - Dictionary.com
Single-valued definition: (of a function) having the property that each element in the domain has corresponding to it exactly one element in the range. www.dictionary.com
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How to identify single valued functions - YouTube
In this video, we learn how to tell apart a single valued function from a relation. #soloanch To learn Precalculus/calc 1, ... www.youtube.com
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Single-valued vs. multivalued context keys - AWS Documentation
Single-valued condition context keys have at most one value in the request context. For example, when you tag resources in AWS, each resource tag is stored as a ... docs.aws.amazon.com
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What is a single valued function? - Quora
A well defined function associates one and only one output to any particular input...That is nothing but single valued function. www.quora.com
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What is the definition of a single valued function this is potentially a dumb question but I am a touch confused about some terminology. I'm reading Ahlfor's complex analysis, and I am in a section on integrals of har...
Some authors call such functions multi-valued functions. So the text just means it is a "proper" function.
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Why $f(z)=z^2$ is single valued? Why $f(z)=z^2$ is single valued where $z\in\mathbb{C}$? From definition we have $$z^2=e^{2 \log z}=e^{2(\ln|z|+i(2k\pi+Arg(z)))}$$ I dont get it ;/ Maybe it's getting late.
Normally, $z^a$ with $a \in \mathbb Z$ _can_ be defined as a single-valued function without drawbacks, so we do so; it is not defined as $\exp(a \log z is no ambiguity though, because if $a \in \mathbb Z$ we have that $\exp(a \log z) = z^a$ (as defined above); in particular $\exp(a \log z)$ admits a single
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How would yo make a branch cut to define a single-valued branch of the function log(z - 1 + i)? The question says it all. I understand the concept of branch cuts, but I have not quite yet figured out how to find branc...
There are infinite different branch cuts that satisfy this, but for one, you could do $1-i+z$ for $\\{{z\in \mathbb{R}}|z>0\\}$.
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