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QUOT. definition in American English - Collins Dictionary
1. a phrase or passage from a book, poem, play, etc, remembered and spoken, esp to illustrate succinctly or support a point or an argument . 2. the act or habit of quoting from books, plays, poems, etc.
www.collinsdictionary.com
www.collinsdictionary.com
QUOT Definition & Meaning - Merriam-Webster
What does the abbreviation QUOT stand for? Meaning: quotation.
www.merriam-webster.com
www.merriam-webster.com
quot - Wiktionary, the free dictionary
how old are you: quot annos natus es? many men, many minds: quot homines, tot sententiae; to be absolutely ignorant of arithmetic: bis bina ...
en.wiktionary.org
en.wiktionary.org
quot
▪ I. quot, pa. pple. dial. (kwɒt) Also 7 quotted, 8 quott. [f. quot quat v.1 1 b.] Sated, cloyed.1674–91 Ray S. & E.C. Words, Quotted, cloyed, glutted. Suss. c 1741 E. Carter Let. in Mem. (1808) I. 27, I believe I am grown quott of assemblies, &c. 1887 Kentish Gloss., Quot, cloyed, glutted.▪ II. † q...
Oxford English Dictionary
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Quotient Technology - QUOT - Stock Price & News | The Motley Fool
Quotient Technology operates a digital marketing platform connecting brands and retailers with consumers through web, mobile, and social channels.
www.fool.com
www.fool.com
Quotient Technology Inc. Stock (QUOT) - Quote Nyse- MarketScreener
Quotient Technology Inc. is a promotion and media technology company. The Company is engaged in delivering digital promotions and media for advertisers and ...
www.marketscreener.com
www.marketscreener.com
Quot scheme
scheme called the quot scheme associated to a Hilbert polynomial . This shows represents the quot functor
Projective space
As a special case, we can construct the project space as the quot schemefor a sheaf on an
wikipedia.org
en.wikipedia.org
QUOT. Definition & Meaning - Dictionary.com
a minimum wage hike being unlikely to make it in the final coronavirus relief package: "You cannot make it in any state in this country on $9 or $10 an ...
www.dictionary.com
www.dictionary.com
-quot- - WordReference.com Dictionary of English
-quot- comes from Latin, where it has the meaning "how many; divided.'' This meaning is found in such words as: quota, quotation, quotidian, quotient.
www.wordreference.com
www.wordreference.com
Quot Definition & Meaning - YourDictionary
noun Abbreviation of quotation. Senses indistinct in early use; see quots. Wiktionary Advertisement adjective Abbreviation of quoted. N/A as quot.
www.yourdictionary.com
www.yourdictionary.com
Quot meaning in English - DictZone
quot meaning in English ; quot [undeclined] adjective. as many + adjective [UK: əz ˈmen.i] [US: ˈæz ˈmen.i]. how many + adjective. of what number + adjective.
dictzone.com
dictzone.com
Quotient field of a domain Let $A$ be a commutative domain and $K=Quot(A)$, its field of fractions (quotient field). Prove that $K$ is a f.g. $A$-module if and only if $A=K$.
Let $\\{\frac{1}{a_1},\ldots,\frac{1}{a_n}\\}$ generate $K$ as an $A$ module, with each $a_j\in A$, and let $x$ be an element of $K$. Then there exist $b_1,\ldots,b_n$ in $A$ such that $\frac{x}{a_1a_2\cdots a_n}=\sum\limits_{j=1}^n\frac{b_j}{a_j}$. Multiplying both sides of the equation by $a_1a_2\...
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$\mathbb{Q}[t]$ is integrally closed in $Quot(\mathbb{Q}[t])$ I'm having trouble trying to show that $\mathbb{Q}[t]$ is integrally closed in $Quot(\mathbb{Q}[t])$. Where $Quot(\mathbb{Q}[t])$ is the field of fractions...
A unique factorization domain is always integrally closed in its field of fractions. The proof is exactly the same as for $\mathbb Z$.
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Degree of the field extension $K(x)\hookrightarrow\operatorname{Quot}\left(K[x,y]/(f)\right) $ > Let $K$ be a field, and $f\in K[x,y]$ an irreducible degree $d$ polynomial. I want to prove that the field extension $$ ...
I've proved in this thread that the field of fractions of $KX,Y$ is $K(X)[Y]/(f)$, so $[K(X)[Y]/(f):K(X)]=\deg_Yf$.
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Extensions between integral domains give extensions of fields of the same degree. Assume that $S \subset R$ is a ring extension where, both $S$, $R$ are integral domains. Furthermore, assume that $R$ is a free $S$-mod...
_Hint:_ Show that $\text{Quot}(R) \xleftarrow{\cong} R\otimes_S \text{Quot}(S)$; in words, it suffices to have all elements of $S\setminus\\{0\\}$ invertible
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