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proportionally
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proportionally
proportionally, adv. (prəʊˈpɔəʃənəlɪ) [f. proportional + -ly2.] 1. In a proportional manner or degree; in proportion; in due proportion.1396 in Scott. Antiq. XIV. 217, ii. c. [marks] to be payit in the yhere at four termes proportionaly. 1434 in Exch. Rolls Scotl. IV. 567 note, Ten markkis of usuale...
Oxford English Dictionary
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Overdose deaths involving buprenorphine did not proportionally increase ...
Jan 20, 2023In contrast, buprenorphine-involved overdose deaths included fewer Black, non-Hispanic people (5.7%), and Hispanic people (5.5%) compared with other opioid-involved overdose deaths (18.8% and 9.4%, respectively), which the authors note might be related to inequitable access to treatment.
nida.nih.gov
Proportionally scale values I have a series of values that are percentages of a whole For example: * 10 % * 8 % * 17 % * 14 % * 12 % * 19 % * 16 % These are plotted on a bar graph with the top scal...
Usually you just make the left axis run from $0\%$ to the maximum or some round number a little above the maximum. In your case, from $0\%$ to $20\%$ seems reasonable. You could multitply by $\frac {100}{max value}$ but it wouldn't be percent any more.
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Cutting proportionally Given any convex quadrilateral $ABCD$ and an inner point $z$ is it possible to draw/construct a line $EF$ passing through $z$ s.t. $$\frac{AE}{EB}=\frac{DF}{FC}$$ !quadrilateral
EDIT1: If we only want to prove if $ EF$ exist,that $z$ is on $EF$, it is easy. let $A(0,0),D(x_1,0),C(x_2,y_2),B(x_3,y_3),Z(a,b),H(p,q),H$ is on $AC$with $FH//AD \to EH//BC$, if we can find $H(p,q)$, then we can draw $EF$ and the problem is solved. with the conditions, we have: $((x_2-x_1)y_3-x_3y_...
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Proportional percentage increases in groups If I have 4 gases in an atmosphere, lets say: * A makes up 78% * B makes up 21% * C makes up .93% * D makes up .04% If the percentage of gas D increases to 5%, h...
So the other components must be decreased proportionally by (99.96-4.96)/99.96 = 95.00/99.96.
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Finding proportions....... kindly accept my apology in advance as i am not good in mathematics and this post might be trivial for some of the forum members. Consider I have $100 and I want to distribute among three po...
One possibility would be to distribute the money proportionally to $11-s$ where $s$ is the person's poverty score. Then the money would be distributed proportionally $10:8:7$ with the poorest person getting the most (40 dollars), and the other two getting 32 and 28
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Proportionally decrease 3 numbers by n percent I have 3 numbers 5, 90, 60, that gives = 155, I need to decrease them by n percent, so they together give 100, but to keep the ratio between them. Not sure is it even pos...
First keep in mind that if you decrease each number by the same percentage, their ratio remains same. $$a \rightarrow a- \frac{na}{100}$$ and $$b \rightarrow b- \frac{nb}{100}$$ $$\implies \frac ab=\frac{a-\frac{na}{100}}{b- \frac{nb}{100}}=\frac ab$$ Now, for your problem, you must have, $$\left(a-...
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Is fat distributed proportionally around the body? One guide I have been using to tell me if I really am gaining a lot of weight is a ring around my 2nd last finger on my right hand, if I can slip it on and off withou...
@fileunderwater's suggestion to use a scale is probably the best answer you could get, but looking at this broadly, the answer is no. The oft-referenced apple and pear shapes are indeed very real and have medical consequences. One of the issues is that there are sex differences in fat distribution. ...
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How many ways to choose a group of 7 out of 16 men and 12 women if sex should be proportionally represented (a) If we have no restrictions, its $\dbinom{28}{7}$ (b) If we need to have each sex proportionally represen...
Your answer to (d) is not correct: it should be $$\binom{16}{7} + \binom{12}{7},$$ because the choice of an all-male group is **exclusive** of the choice of an all-female group. Therefore, the number of such choices is the sum, not the product, of the number of choices within each sex. For a simpler...
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Rotation of necklaces The number of fixed necklaces of length $n$ with $a$ types of beads is $$N(n,a)=\frac1n\sum_{d|n}\phi(d)a^{n/d}\;.$$ It is clear intuitively that the number of rotational coincidences gets propor...
A necklace that has no rotational symmetry is called a _primitive_ or _aperiodic_ necklace, or a _Lyndon word_ (if written as a word by taking the lex-smallest rotation.) The number of primitive necklaces is given by almost the same formula as the one you give for the number of necklaces, but with E...
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Formula to convert time to pixels I have a list of times represented as `000000` to `240000`. For a web application, I convert those times to pixels by simply dividing by 100, so that their display position is ordered...
Given a "time" of the form: `t = HHMMSS`, we want to convert it to a four digit number of pixels representing $100$ times the number of hours that have elapsed since midnight. Using Python $3.3$ together with the flooring and modulo operations, we can achieve this goal by doing something like this: ...
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Divide proportionnally to lowest possible value? I'm trying to write an algorithm to convert RGB to RGBW, and a problem I'm running in is that my white value should, depending on the luminance, go from: 255----------...
So you have $255\geq x\geq 120$. Subtract $120$ and you'll get: $$135\geq x-120\geq 0$$ multiply with $\frac{255}{135}$ to obtain: $$255\geq\frac{255}{135}(x-120)\geq 0$$ Now it's in the range that you want. So to get the number between $255$ and $0$, subtract $120$ and then multiply by $\dfrac{255}...
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Side-Splitter Theorem, which sides are proportionally I'm currently wondering about the side splitter theorem. !enter image description here Lets say I have this triangle. Now the side splitter theorem says, that if...
Triangles $ EMB $ and $ CDE $ are similiar, so yes, the last relation you mentioned holds.
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Formula to calculate the coordinates of some points on a circle Given the following variables * $a$ : the number of points proportionally spread on a circle * $(O_x, O_y)$ : the origin of the circle * $\thet...
The angle separating point has to be $\frac{2\pi}{a}$ (using radians). Using the definition of $\sin$ and $\cos$ (and assuming that the first point has $\theta=0$), translating the points from the origin to the centre of the circle and applying a simmetry on the x-axis, we get the following: Given t...
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