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lineal
lineal, a. and n. (ˈlɪnɪəl) Forms: 4–7 lineall, 5–6 liniall, (5 linealle, -yalle, 6 lin-, lyneal(l, -iall, -yall), 6– lineal. [a. F. lineal, f. late L. līneālis, f. līnea line n.2] A. adj. 1. a. Of or pertaining to a line or lines; consisting of lines. † lineal alphabet: one in which the symbols con... Oxford English Dictionary
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Lineal
Lineal is a geometric term of location which may refer to: pertaining to a lineage Lineal kinship or "Eskimo kinship" Lineal descendant, a blood relative offices Lineal championship, in boxing, "the man who beats the man" takes his championship pertaining to a line Foot (length) or "lineal foot" Lineal wikipedia.org
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lineal
lineal/ˈlɪnɪəl; `lɪnɪəl/ adj[usu attrib 通常作定语]1 (fml 文) in the direct line of descent 直系的; 嫡系的 a lineal heir to the title 该头衔的直系承袭人.2 = linear. 牛津英汉双解词典
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Parque Lineal (Puerto Vallarta)
Parque Lineal is a linear park in Puerto Vallarta, in the Mexican state of Jalisco. The park features a skatepark. wikipedia.org
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Lineal descendant
A lineal or direct descendant, in legal usage, is a blood relative in the direct line of descent – the children, grandchildren, great-grandchildren, etc ," as used in a statute providing for the non-lapse of a devise where the devisee predeceases the testator but leaves lineal descendants. wikipedia.org
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Lineal championship
The lineal championship is intended as a return to that era. Issues An issue in the implementation of a lineal championship is what to do if the lineal champion retires, dies, or moves to a different weight class wikipedia.org
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If $V$ is finite-dimensional and exist $\beta$ basis of $V$ such that $T(\beta)$ is a basis for $W$, then $T$ is a isomorphism? Let $V$ and $W$ vector space over $F$ and $T : V \rightarrow W$ lineal. The statement is ...
Consider $V=\Bbb{R}^2$ and $W=\Bbb{R}^1$, and let $\pi:V\to W$, $\pi(x,y)=x$. Let $\beta=\\{(1,0),(1,1)\\}$, then $\pi(\beta)=\\{(1)\\}$, which is basis of $W$.
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Ciudad Lineal
Ciudad Lineal (, "Linear City") is one of 21 districts of Madrid, Spain. The ‘Ciudad Lineal’ takes a form of a city 400 meters wide, centered on a tramway (line 70 - closed in 1972) and a thoroughfare running in parallel. wikipedia.org
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Laplacian and Fourier transform Show the laplacian is rotationally invariant: $\Delta(f\circ R)=(\Delta f)\circ R, \forall R\in SO_d(\mathbb{R})$. Suggestion: You can use that the Fourier Transform (FT) of $f(Ax)$ ...
The Fourier transform of $f(Ax)$ is $$ \mathcal{F}\\{f\circ A\\}(\xi)= \frac{1}{(2\pi)^{n/2}}\int_{\mathbb{R}^n} f(Ax)e^{-ix\cdot \xi}dx. $$ Let $y=Ax$. Then $x=A^t y$ because $A^tA=AA^t=I$ by the definition of a symmetric orthogonal matrix. The Jacobian of this transformation is $|A^t|=1$, which gi...
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Ciudad Lineal (Madrid Metro)
Ciudad Lineal is a station on Line 5 of the Madrid Metro, named for the Ciudad Lineal district. It is located in fare Zone A. References Line 5 (Madrid Metro) stations Railway stations in Spain opened in 1964 Buildings and structures in Ciudad Lineal District, Madrid wikipedia.org
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Let $V$ a $F$-vectorial space with finite dimension, $T: V \rightarrow V$ lineal and $W$ invariant under $T$ with dimension $n$ Let $V$ a $F$-vectorial space with finite dimension, $T: V \rightarrow V$ lineal and $W$ ...
Whenever you have such abstract looking questions especially in linear algebra, I find it best to look at concrete examples. Say, we have the following matrix- $$\begin{pmatrix} * & *&0 \\\ * & * &0 \\\ 0 & 0 &1 \\\ \end{pmatrix}\begin{pmatrix}0\\\0\\\x\end{pmatrix}=\begin{pmatrix}0\\\0\\\x\end{pmat...
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Lineal succession
Lineal succession was a doctrine of the Latter Day Saint movement, whereby certain key church positions were held by right of lineal inheritance. Russell Ballard Interrelation of church offices with the Smith family Notes References Latter Day Saint belief and doctrine Lineal Lineal Lineal Kinship wikipedia.org
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The Continuous Dependence of Solutions to Volterra Equation Can any tell me why the solutions of the lineal _Volterra integral equation_ of second kind, have continuous dependence? $y(t)=g(t)+\int_{0}^{t}k(t,s)y(s)d...
If I understand your question correctly, you want to know why $y$ is continuous. The answer follows from the following $$\begin{align} &y(t+\Delta t)-y(t)=g(t+\Delta t)-g(t)+\int_0^{t+\Delta t} k(t+\Delta t,s)y(s)\mathrm{d}s-\int_0^t k(t,s)y(s) \mathrm{d}s \\\ &=g(t+\Delta t)-g(t)+\int_0^t \left( k(...
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直系血親卑親屬是什麼？原來這些親屬都不包括在內! - 法律人
雖然收養的子女和養父母並無血緣關係，但依照民法 § 1077 第 1 項規定，養子女在親屬關係的認定上，和婚生子女是相同的。 因此，收養的子女對於養父母、甚至養父母的父母而言，仍然是直系血親卑親屬。 讓法律人 app 幫你實現「法律用語隨手查自由」!
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Inverse of operators norm Could someone help me to prove this inequality and decide if it can be an equality? Let be T a lineal isomorphism between $ (X,||·||) (Y,||·||)$ prove that $||T^{-1}||\geq||T||^{-1}$. Thanks.
We have $1=\|\operatorname{Id}\|=\|T^{-1}\circ T\|\leqslant\|T^{-1}\|.\|T\|$ and therefore $\|T^{-1}\|\geqslant\|T\|^{-1}$. However, in general the equality doesn't hold. Take, for instance, $X=Y=\mathbb{R}^2$ with its usual norm. Define $T\colon\mathbb{R}^2\longrightarrow\mathbb{R}^2$ defined by $T...
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