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integrant

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integrant
integrant, a. (n.) (ˈɪntɪgrənt) [ad. L. integrānt-em, pr. pple. of integrāre: see integrate v. Cf. F. intégrant (1690 in Hatz.-Darm.).] Of parts: Making up or contributing to make up a whole, constituent, component; essential to the completeness of the whole: = integral A. 1. integrant parts, in F. ... Oxford English Dictionary
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Br'oZ
Matheus Herriez acted in some musicals and is performing with his rock band Monk; he is married with the ex-Rouge integrant Lissah Martins since 2009. wikipedia.org
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disintegrant
disˈintegrant, a. and n. [f. as prec. + -ant1.] A. adj. Disintegrating, or becoming disintegrated. B. n. Something that disintegrates; a disintegrating agent.1855 H. Spencer Princ. Psychol. (1872) I. i. iv. 75 A direct disintegrant of the tissues. 1866 Pall Mall G. 10 Nov. 4 Post-classical and disin... Oxford English Dictionary
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Socialist Mexican Party
The following month, it was announced that a faction of the PST led by Graco Ramírez would join the PMS as its sixth integrant. wikipedia.org
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Derivative of an integral function Say $$\varphi(\theta) = \int_{0}^{2\pi} \frac{f((1-\theta)z+\theta(z_0+re^{it}))}{z_0+re^{it}-z}ire^{it}dt.$$ Why do we have $$\varphi'(\theta) = \int_{0}^{2\pi} f'((1-\theta)z+\thet...
Note that $$\frac{d}{dx} \left (\int_{a(x)}^{b(x)}f(x,t)dt \right) = f(x,b(x))\cdot b'(x) - f(x,a(x))\cdot a'(x) + \int_{a(x)}^{b(x)} \frac{\partial}{\partial x}f(x,t) dt$$ also known as _differentiation under the integral_. In your case $a$ and $b$ are both costants, so the first part of the RHS is...
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Federació Catalana d'Escoltisme i Guiatge
L’escolta se sent part integrant de la natura i la defensa de qualsevol agressió. L’estima, la coneix i la respecta. wikipedia.org
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solvend
ˈsolvend ? Obs. [ad. L. solvend-um, neut. gerundive of solvĕre solve v.] Something to be dissolved.1738 Phil. Trans. XLI. 108 The Particles of the Solvend having imbibed the Particles of the Menstruum. 1799 Kirwan Geol. Ess. 467 A fluid whose specific affinity to the particles of a solvend is greate... Oxford English Dictionary
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Intel Capital
AppyStore, AVG, Bellrock Media, Box, Broadcom, Cloudera, CNET, Citrix Systems, Elpida Memory, Gaikai, Gigya, IndiaInfoline.com, Inktomi, Insyde Software, Integrant wikipedia.org
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sectile
sectile, a. (ˈsɛktɪl, -aɪl) [a. F. sectile, ad. L. sectil-em, f. sect-, ppl. stem of secāre to cut.] Capable of or suited for being cut. † a. sectile leek [= L. sectile porrum Juv.], a dwarf or stunted variety of Allium Porrum. Obs. rare—1.1716 M. Davies Athen. Brit. II. 349 The Sectile or Cropt Lee... Oxford English Dictionary
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Rema-Rema
Pirroni had been an original member of Siouxsie and the Banshees, and was a short-time integrant of Cowboys International, but shortly afterwards went wikipedia.org
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How to Apply Cauchy Integral Theorem I have a question about complex analysis. Let C be the unit circle z = ejθ described from θ = -π to θ = π where _α_ is a real constant. I need to prove this equation: !enter ima...
We have \begin{align} \int_0^\pi e^{a\cos \theta} \cos(a\sin \theta)\, d\theta &= \frac{1}{2}\int_{-\pi}^{\pi} e^{a\cos \theta} \cos(a\sin \theta)\, d\theta \\\ &= \frac{1}{2}\operatorname{Re} \int_{-\pi}^{\pi} e^{ae^{i\theta}}\, d\theta\\\ &= \frac{1}{2}\operatorname{Re} \oint_C e^{az} \frac{dz}{iz...
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1835 Massachusetts gubernatorial election
In total, the state was divided between the Everett Whigs, Armstrong Whigs, Everett Anti-Masons, Van Buren Anti-Masons, "integrant" Van Buren Democrats wikipedia.org
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On the linear combination of $\pm 1$ random variables Let $X_1,\dots, X_n$ be i.i.d symmetric $\pm 1$ random variables, i.e. $X_j$ takes values in $\\{-1,1\\}$ with $$\mathbb{P}(X_j=1)=\mathbb{P}(X_j=-1)=\frac{1}{2}.$...
Write $\cos(a_j t) = (\exp(i a_j t) + \exp(-i a_j t))/2$, and expand the product. We get $$ 2^{-n} \sum_{x \in \\{-1,1\\}^n} \exp \left( i \sum_{j=1}^n x_j a_j t\right) $$ Now note that $$\dfrac{1}{2\pi} \int_0^{2\pi} \exp(ikt)\; dt = \cases{0 & if $k$ is a nonzero integer\cr 1 & if $k = 0$\cr}$$ Th...
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Sleeping (Rick Astley song)
Extended Mix) – 5:58 "Sleeping" (Hifi Crash Remix 2) – 6:27 Chart performance Cover versions The song was covered in 2008 by Randy Jones, a former integrant wikipedia.org
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Application of Fubini's theorem to prove that convolution is integrable I guess that this is an easy question, but I don't have a very solid math background. I'm trying to prove that if $f,g \in L^1(\mathbb{R})$, the...
**Hint:** Use Fubini-Tonelli Theorem instead of Fubini's Theorem, which only requires that your integrant is non-negative, and has the same conclusion
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