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inducting
▪ I. inˈducting, vbl. n. [f. induct v. + -ing1.] 1. Eccl. The action of introducing into, or putting in formal possession of, a benefice.c 1380 [see induct v. 1]. 1575–85 Abp. Sandys Serm. (Parker Soc.) 241 The bestowing of benefices, the presenting, instituting, and inducting of pastors. 1684 Baxte...
Oxford English Dictionary
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WWE inducting Claude 'Thunderbolt' Patterson into Hall of ...
4 days ago — Claude “Thunderbolt” Patterson, a Black pro wrestler who was blacklisted from one of the most well-known promotions in the 1970s in part due ...
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List of halls of fame inducting Elvis Presley
This is a list of Halls and Walks of Fame that have inducted Elvis Presley as a member. Rock and Roll Hall of Fame Country Music Hall of Fame Rockabilly Hall of Fame Gospel Hall of Fame Honky Tonk Hall of Fame Memphis Music Hall of Fame Mississippi Musicians Hall of Fame Mississippi Walk of Fame Shr...
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Country Music Hall of Fame Inducting Ronnie Milsap - People.com
Ronnie Milsap, Hank Cochran Named to Country Music Hall of Fame The third inductee is singer Mac Wiseman; all three men will be honored in a ceremony later this year By Kay West
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Migration-inducting gene 7
Migration inducting gene 7 (Mig-7 or Mig7) is a gene that corresponds to a cysteine-rich protein localized to the cell membrane and cytoplasm.
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induct
▪ I. † inˈduct, ppl. a. Obs. rare. Also 5 en-. [ad. L. inductus, pa. pple. of indūcĕre to induce.] a. Induced. b. Initiated, instructed. c. Introduced.1460 J. Capgrave Chron. (Rolls) 308 Jon..vas loth to resine; but be the emperoure he vas induct that he schuld do it. 1481 Caxton Godefroy cxcv. 286 ...
Oxford English Dictionary
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A case of double induction? The question being: Given $n,m\in\mathbb{Z}$ and for $n>0,m\ge-1$ prove that $1+nm=(1+m)^n$. I have never laid eyes upon a problem of inducting across two variables, but I assume that is ...
If you set the proof up as an inductive proof on one variable, and then, during the inductive step for that variable, conduct an inductive proof on the second variable, I think you'll find that everything proceeds exactly the way you would expect it. I.e., your base case might be $n=1$, then your ou...
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Kerala Sahitya Akademi Fellowship
Kerala Sahitya Akademi Fellowship is an honour of the Kerala Sahitya Akademi (Kerala Literary Academy), given to writers of Malayalam literature by inducting
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Understanding Less Frequent Form of Induction? (Putnam and Beyond) I won't paste the question here since my problem is not a technical one but a conceptual one. Book is here: (Page 22 of the pdf) I do not understan...
Please do insert more details in your question. In any case, forward-backward induction is a very common concept, so here's my answer: It is not sufficient to be able go from $n+1$ to $n$ because you don't have a large value of $n$ to start. The forward part of going from $2^k$ to $2^{k+1}$ ensures ...
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Second N. Chandrababu Naidu ministry
The cabinet was expanded by inducting twenty six new ministers, Increasing the strength of the cabinet to thirty five. On 26 November 2001, the council was reshuffled by dropping eight ministers and inducting eleven new ones.
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Decomposition of a semisimple Lie algebra. I am struggling with the following logic which appears in Humphreys' introduction to semisimple Lie algebras. > Suppose that $\mathfrak{h}$ is a Cartan subalgebra in a semis...
Since $Ad_h$ is simultaneously diagonalizable, Let $(e_1,...,e_n)$ be a basis of $g$ where the element of $Ad_h$ are diagonalisable. We have for every $x\in h, [x,e_i]=\alpha_i(x)e_i$, $\alpha_i$ is an element of $h^*$, you deduce that $g$ is the direct sum of $g^{\alpha_i}$ where $g^{\alpha_i}$ is ...
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Prove a property of divisor function Let $n$ be a positive natural number whose prime factorization is $n=p_1^{a_1}p_2^{a_2}\cdots p_k^{a_k}$, where $p_i$ are natural distinct prime numbers, and $a_i$ are positive nat...
Hint: Instead of inducting on $n$ consider inducting on $k$.
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Existence of nontrivial normal subgroups in solvable finite groups Let $G$ be a finite solvable group. Is it true that $G$ has a minimal nontrivial normal subgroup, i.e. a subgroup $N$ with $N\trianglelefteq G$, $N\ne...
Start with $N_{0}=G$. Once you have $N_{i}$, look to see if there are any nontrivial proper subgroup of $N_{i}$ that is also a normal subgroup of $G$. If there is, then let that be $N_{i+1}$ and repeat. If not, then you are done, and $N_{i}$ is what you get. The process must halt, as $|G|$ is finite...
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Properties of Abelian Groups I'm trying to prove that if $G$ is an Abelian group under $\cdot$, $\forall a,b \in G. \forall z \in \mathbb{Z}. (a \cdot b)^n = a^n \cdot b^n.$ I was originally considering doing this pro...
$G$ is an abelian group, so let $a,b\in G$ be given, and fix $n$. Then $$ (ab)^n=(ab)(ab)(ab)\cdots(ab).$$ Because $G$ is abelian $$ (ab)(ab)(ab)\cdots(ab)=(aa\cdots a)(bb\cdots b)=a^nb^n.$$ This follows naturally from the definition of commutativity.
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A question on solvable groups. Let's suppose $S$ is a group and can be written as $S= G_1\times G_2\times\cdots\times G_K$; here each $G_i$ is a group of prime power order. And $o(S)= n.$ Is this $S$ solvable group? I...
Now demonstrate such a sequence on $S$ by inducting on $K$, the number of prime power factors.
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