Artificial intelligent assistant

induct

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induct
▪ I. † inˈduct, ppl. a. Obs. rare. Also 5 en-. [ad. L. inductus, pa. pple. of indūcĕre to induce.] a. Induced. b. Initiated, instructed. c. Introduced.1460 J. Capgrave Chron. (Rolls) 308 Jon..vas loth to resine; but be the emperoure he vas induct that he schuld do it. 1481 Caxton Godefroy cxcv. 286 ... Oxford English Dictionary
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induct
induct/ɪnˈdʌkt; ɪn`dʌkt/ v[Tn, Tn.pr, Cn.n/a]~ sb (to/into/as sth) install sb formally or with ceremony in a position or an office; admit sb as a member of sth 使某人正式就职; 吸收某人为成员 induct sb to/into the priesthood/as a priest 使某人就任牧师职位[任职牧师]. 牛津英汉双解词典
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SF Giants announce plans to induct 'Core 4' onto Wall of Fame
Jan 16, 2024SF Giants will induct 'Core 4' onto Wall of Fame this summer Among the promotions unveiled Tuesday, Jeremy Affeldt, Santiago Casilla, Javier Lopez and Sergio Romo will be inducted onto the ...
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The National Inventors Hall Of Fame Will Induct Its First 2 Black ... - NPR
Sep 27, 2021Croak and Bath are among the seven honorees announced this month and will join the 22 others announced last year as the hall of fame's Class of 2022. All 29 will be celebrated and inducted at back ...
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Air India Express set to induct 50 new Boeing 737 ... - The Indian Express
Oct 13, 2023Currently, the combined entity has a fleet of 56 aircraft, including 26 B737, 2 B737 MAX, 5 A320 neo and 23 A320. "Over the next 15 months, a total of 50 new B737 MAX aircraft will join the LCC fleet, allowing us to grow our network to new destinations and increase flights on existing routes," Singh said in the message.
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Phoenix Suns to Induct Shawn Marion and Amar'E Stoudemire Into Ring of ...
Aug 9, 2023Phoenix Suns. August 9, 2023 2:13 PM MST. PHOENIX - The Phoenix Suns today announced that the team will induct legends Shawn Marion and Amar'e Stoudemire into the Phoenix Suns Ring of Honor ...
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Who Should Induct Jimmy Buffett into the Rock Hall?
Apr 25, 2024 — Who should induct Jimmy Buffett as part of the 2024 Rock and Roll Hall of Fame class this fall? We have some ideas.
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Who Should Induct Jimmy Buffett into the Rock Hall?
4 days ago — Who should induct Jimmy Buffett as part of the 2024 Rock and Roll Hall of Fame class this fall? We have some ideas.
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Phoenix Suns to Induct Shawn Marion Into Suns Ring of Honor During ...
Oct 18, 2023PHOENIX - The Phoenix Suns today announced that Suns legend Shawn Marion will be inducted into the Suns Ring of Honor on Friday, Dec. 15, when the Suns host the New York Knicks. A special ...
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prove by induction: $\forall n \in N, \exists k \in N: 165^{2n} - 1 = 166k$ I am trying to prove by induction: $\forall n \in N, \exists k \in N: 165^{2n} - 1 = 166k$. But I've never come across having to possibly i...
For $n=m\in\Bbb N$ let $165^{2m}-1 = 166 k \implies \color{blue}{165^{2m} = 166k+1}\ , k \in \Bbb N$ For $n=m+1$, $$165^{2m+2} - 1 = \color{blue}{165^{2m}}\cdot165^2-1 = (\color{blue}{166k+1})165^2 - 1$$ $$165^{2m+2} - 1 = 166\cdot165^2k+165^2-1 = 166\cdot165^2k+166\cdot164 = 166k'$$ $k' = 165^2k+16...
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Use Induction to prove $\forall m,n \in \Bbb Z_{\ge 0}, 1 +mn \leq (1 + m)^n$ Use Induction to prove: $$\forall m,n \in N, 1 +mn \leq (1 + m)^n$$ for integers $m,n\ge 0$. My biggest problem with this proof is...
The trick is not to induct on $m$, just do the induction on $n$. You don't **have** to induct for both variables.
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Induction on an if-then statement So we are told to do induction on this statement: **"Let P(n) be the statement: If a + n = c + n, then a = b."** , and I am told to induct on n, so I do. Base: Let P(0) be the state...
Any time you're trying to do a proof, you need to look at what your premises are. If you're trying to prove this in Peano arithmetic, then you have the axiom that (a = b) => (a+1=b+1). So if (a+n)=(b+n), then (a+n)+1=(b+n)+1, and by associativity a+(n+1)=b+(n+1).
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Prove using ordinal induction that for any two ordinals $\alpha$ and $\beta$, if $\alpha \in \beta$ then $S(\alpha)$ $\in$ $S(\beta)$ So I am trying to use ordinal induction to prove a rather trivial fact about ordina...
Let us assume that $\beta$ is a limit ordinal, in other words $\beta=\bigcup_{\beta'\in \beta}\beta'$. The inductive hypothesis is that, for every $\beta' \in \beta$, if $\alpha \in \beta'$ then $S(\alpha) \in S(\beta')$. Let us assume that $\alpha \in \beta$. We are left to prove that $S(\alpha) \i...
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Understanding Less Frequent Form of Induction? (Putnam and Beyond) I won't paste the question here since my problem is not a technical one but a conceptual one. Book is here: (Page 22 of the pdf) I do not understan...
Please do insert more details in your question. In any case, forward-backward induction is a very common concept, so here's my answer: It is not sufficient to be able go from $n+1$ to $n$ because you don't have a large value of $n$ to start. The forward part of going from $2^k$ to $2^{k+1}$ ensures ...
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Write an inductive proof that if there is a surjection $ f : \lceil m \rceil → \lceil n \rceil $ then $m ≥ n$. **Here's the problem:** Write an inductive proof that if there is a surjection $ f : \lceil m \rceil → \l...
You are going on right direction. I will use the notation $[n] = \\{1,2,\cdots,n\\}$. Let assume that the inductive hypothesis holds. That is, for every $k\le n$ if there is a surjection $f$ from $[m]$ to $[k]$ then $m\ge k$. Let the surjection $g:[m]\to [n+1]$ given. Consider the set $$A=\\{j\in [m...
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