Artificial intelligent assistant

indeterminable

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indeterminable
indeterminable, a. (n.) (ɪndɪˈtɜːmɪnəb(ə)l) [ad. L. indēterminābilis (Tertullian): see determinable. Cf. F. indéterminable (1753 in Hatz.-Darm.).] Not determinable. † 1. Incapable of being limited or bounded in respect of range, number, etc. Obs. rare.1486 Bk. St. Albans, Her. A v, Ther ben ix. vice... Oxford English Dictionary
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indeterminable
indeterminable/ˌɪndɪˈtɜ:mɪnəbl; ˌɪndɪ`təmɪnəbl/ adj(fml 文) that cannot be decided or settled 无法决定的; 无法解决的. 牛津英汉双解词典
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Prophaethon
Some more indeterminable remains from the Late Paleocene of Maryland, US might also belong here. wikipedia.org
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undeterminable
undeˈterminable, a. [un-1 7 b and 5 b.] † 1. Incapable of being terminated; unending. Obs.1581 J. Bell Haddon's Answ. Osor. 444 Albeit the thing it selfe..be past, and y⊇ tyme thereof determined: yet doth the power..thereof remaine unmoveable, sure, and undeterminable beyond all ages. 1605 Chapman A... Oxford English Dictionary
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Scullya
It is considered an indeterminable specimen. wikipedia.org
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indeterminably
indeˈterminably, adv. rare. [In sense 1, f. in-3 + determinably; in 2, f. prec. + -ly2.] † 1. In an indefinite manner: cf. determinably adv.1471 Fortescue Wks. (1869) I. 533 Our lorde sayde..indiffinytely or indetermynably that she [woman] shulde be vnder the power and lordshipp of man. 2. In an ind... Oxford English Dictionary
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Danio erythromicron
A phylogenetic analysis of Danio found it indeed close to that genus, but its precise placement was still indeterminable. wikipedia.org
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Albertino Barisoni
In 1614, Barisoni went to Rome in the company of Paolo Gualdo to solve some curial questions and afterward (at an indeterminable date) was appointed to wikipedia.org
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Range of $\log(16-4x^2-4y^2-z^2)$ I am trying to find the range of $f(x,y,z) = ln(16-4x^2-4y^2-z^2)$ I know that the natural log function of one variable has range of all real numbers, so would this function be the sa...
$$\text{The argument of the log must be positive:}$$ $$\ 16-4x^2-4y^2-z^2>0$$ $$\ 4x^2+4y^2+z^2<16$$ $$\ \frac{x^2}{4}+\frac{y^2}{4}+\frac{z^2}{16}<1$$ $$\ (\frac{x}{2})^2+(\frac{y}{2})^2+(\frac{z}{4})^2<1$$ $$\text {so the domain is a region enclosed in an ellipsoid.}$$ $$\ \\\ \text{Now you calcul...
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Galve, Teruel
Fossil teeth belonging to baryonychines, allosauroids, dromaeosaurids and indeterminable coelurosaurs have also been recovered at some of the Galve sites Those indeterminable coelurosaur teeth are from the Galve outcrops of the El Castellar Formation, and bear some avian resemblance. wikipedia.org
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Limit factoring I've the following limit to be calculated. $\lim_{x \to 7} \dfrac{5 - \sqrt{4 + 3x}}{7 - x}$ I'm used to solve this limits from Calculus I text books but I've been struggling without success on this ...
**Hint:** multiply by $$\frac{5+\sqrt{4+3x}}{5+\sqrt{4+3x}}$$ And recall that $(\alpha-\beta)(\alpha+\beta) = \alpha^2 - \beta^2$. This _trick_ is called **multiplying by the conjugate** , and it is a way of getting rid of those roots and the $\frac{0}{0}$ type of indetermination.
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Natchitochia
Natchitochia is known from three incomplete ribs and thirteen vertebrae of which four are thoracics, five lumbars, one sacral, two caudals, and one of indeterminable wikipedia.org
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The Impossibility of Automating Ambiguity - MIT Press
Abstract. On the one hand, complexity science and enactive and embodied cognitive science approaches emphasize that people, as complex adaptive systems, are ambiguous, indeterminable, and inherently unpredictable. On the other, Machine Learning (ML) systems that claim to predict human behaviour are becoming ubiquitous in all spheres of social life. I contend that ubiquitous Artificial ...
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如何：将 TreeView 绑定到深度无法确定的数据 - WPF .NET Framework
有时，你可能想要将 TreeView 绑定到深度未知的数据源。. 当数据本质上是递归的则可能会发生这种情况，例如文件系统（文件夹可以包含文件夹）或公司的组织结构（员工有其他员工作为其直接下属）。. 数据源必须具有分层对象模型。. 例如，类 Employee 可能 ...
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Convergence of Infinite Series With Trig functions I need some urgent help in determining whether the following infinite series actually converges or not. Upon graphing, it does seem like so but I can't be sure. I'm n...
**Hint**. One may use standard Taylor series expansions as $i \to \infty$, to obtain $$ \begin{align} &(2i+4)\tan\left(\frac{\pi }{2i+4}\right)+(2i+3)\tan\left(\frac{\pi }{2i+3}\right)=2 \pi +\frac{\pi ^3}{6 i^2}+O\left(\frac1{i^3}\right) \\\\\\\ &\frac{\pi }{1-\frac{(i+2)\left(1-\sin\left(\frac{\pi...
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