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CON Definition & Meaning - Merriam-Webster
: a dishonest trick used to gain someone's confidence . also : a confidence game : swindle. con.
www.merriam-webster.com
www.merriam-webster.com
Con - Wikipedia
Con · Con (name) · Confidence trick, also known as con, scam, or flim flam; con is also a person who perpetrates a confidence trick · Conn (nautical), also ...
en.wikipedia.org
en.wikipedia.org
Con - Definition, Meaning & Synonyms - Vocabulary.com
con · noun. an argument opposed to a proposal · adverb. in opposition to a proposition, opinion, etc. · noun. (offensive) a swindle in which you cheat at ...
www.vocabulary.com
www.vocabulary.com
con
▪ I. con, n.5 Brit. /kɒn/, U.S. /kɑn/ [Shortened <convention n.] Esp. among enthusiasts of science fiction and role-playing games: a convention, an organized gathering of people with a shared interest. Freq. as the final element in the names of such events.1944 J. B. Speer Fancyclopedia 55/1 In t...
Oxford English Dictionary
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Con Edison - Powering New York City and Westchester
Providing electric, gas, and steam to NYC and Westchester. Pay your bill, manage your account, report an outage, and learn how to save energy.
www.coned.com
www.coned.com
Rootcast: Thoroughly Together With "Con-" | Membean
The prefix con-, which means “with” or “thoroughly,” appears in numerous English vocabulary words, for example: connect, consensus, and conclude.
membean.com
membean.com
con
con/kɔn; kɑn/ n[sing](sl 俚) instance of cheating sb; confidence trick 欺骗; 骗局 This so-called bargain is just a con! 这种所谓的大减价不过是个骗局! [attrib 作定语]a con trick 欺骗的手段 He's a real con artist/merchant, ie swindler. 他是个不折不扣的假艺术家[商人](骗子). con, v (-nn-) [Tn, Tn.pr]~ sb (into doing sth/out of sth) (infml 口) swi...
牛津英汉双解词典
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CON | definition in the Cambridge English Dictionary
to make someone believe something false, usually so that that person will give you their money or possessions: be conned into She felt she had ...
dictionary.cambridge.org
dictionary.cambridge.org
con - Wiktionary, the free dictionary
See also: Appendix:Variations of "con". Contents. 1 Translingual. 1.1 Etymology; 1.2 Symbol; 1.3 See also. 2 English. 2.1 Pronunciation; 2.2 Etymology 1.
en.wiktionary.org
en.wiktionary.org
CON Definition & Meaning | Dictionary.com
verb (used with object) · to learn; study; peruse or examine carefully. She's been conning her grandfather's medical diaries for months. · to commit to memory.
www.dictionary.com
www.dictionary.com
1241 Synonyms & Antonyms for CON | Thesaurus.com
con · criminal · felon · offender · prisoner. Strong matches. culprit · jailbird · malefactor · repeater. Weak matches. long-termer · yardbird. verb as in ...
www.thesaurus.com
www.thesaurus.com
Is 'con” actually a negative word? Is “con” short for “convey”? - Quora
Generally 'con' means negative only. It means deceiving someone. It has also a meaning to make one to believe something or pressurise to lie ...
www.quora.com
www.quora.com
Con(PA) implies consistency of $\mathsf{PA}$ + ¬Con($\mathsf{PA}$) The Wikipedia article for $\omega$-consistency says "Now, assuming PA is really consistent, it follows that $\mathsf{PA}$ + ¬Con($\mathsf{PA}$) is als...
If $\sf PA+\lnot \rm Con\sf (PA)$ is inconsistent but $\sf PA$ is consistent, then in every model of $\sf PA$ it is true that $\rm Con\sf (PA)$, now by
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"con" meaning in The Japense podcast "nihongo con teppei" Hey just wanted a quick clarification for "Con" in this podcast tite. Does it mean "Japanese with Teppei"? sorry I don't know the exact script for "con" as it ...
The guy is using the Spanish word "con" which means "with".
"Nihongo con Teppei" => "Japanese with Teppei"
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If $\operatorname{Con}(\mathrm{PA})$, then $\operatorname{Con}(\mathrm{PA}+\operatorname{Con}(\mathrm{PA}))$? Assume $\newcommand\PA{\mathrm{PA}}\newcommand\Con{\operatorname{Con}}$ that $\PA$ is consistent. Then we ...
I assume that you mean can we prove from $\newcommand\PA{\mathsf{PA}}\newcommand\Con{\operatorname{Con}}\PA+\Con(\PA)$ the statement $\Con(\PA+\Con(\PA Note that $$\PA\vdash\Con(\PA)\rightarrow\Con(\PA+\Con(\PA))\iff\PA+\Con(\PA)\vdash\Con(\PA+\Con(\PA)),$$ so the above argument shows that indeed the implication
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