Artificial intelligent assistant

acounter

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acounter
@@@LINK=acountre Oxford English Dictionary
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acountering
† acountering, vbl. n. Obs. [f. acounter v. + -ing1.] Encountering, jousting.c 1420 Avowynge of Arthur xxxv, Of knyȝtus in a-cowunturinge This forward to fulfille. Oxford English Dictionary
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acuntre
acuntre early form of acounter v. Obs. Oxford English Dictionary
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acountre
▪ I. acounter, -our early forms of accounter.▪ II. † aˈcounter, v. Obs. Also 4 acuntre. [A reduced form of encounter, a. OFr. encontrer, encountrer; see a- prefix 10.] To encounter, meet.c 1350 Will. Palerne 3602 So kenli þei a-cuntred at þe coupyng to gadere Þat þe kniȝt spere..alto-schiuered.▪ III... Oxford English Dictionary
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accounter
† accounter Obs. (əˈkaʊntə(r)) Forms: 4 acountour, acounter; 6–7 accompter, accounter. [Prob. a. OFr. acuntour, acontour (not in Godefr.), n. of agent f. acunter: see account v. and -our.] 1. One who accounts, reckons, calculates, renders an account.1303 R. Brunne Handl. Synne 5410 Lordynges cunseyl... Oxford English Dictionary
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counter
▪ I. † counter, n.1 Obs. (ˈkaʊntə(r)) Forms: 4 cuntre, cunter, 5 countire, cowntere, 6 counter. [Aphetic form of acuntre, acounter, encounter.] Encounter, hostile meeting, opposition.c 1330 R. Brunne Chron. (1810) 38 Tille þei com to mide⁓weie, cuntre non þei fond. c 1350 Will. Palerne 1344 Ȝe ne he... Oxford English Dictionary
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Sum of differentiable functions. True/False Question : suppose that $f+g$ is differentiable at point $x_0$ therefore $f$ and $g$ are differentiable at $x_0$ I think this statement is false and I got a counter example...
Use the fact that $(f+g)-f=g$ and that the difference of differentiable functions is differentiable.
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